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What is the Squeeze Theorem?

If f(x)leqg(x)leqh(x)f(x) leq g(x) leq h(x) and limxaf(x)=limxah(x)=L\lim_{x \to a} f(x) = \lim_{x \to a} h(x) = L, then limxag(x)=L\lim_{x \to a} g(x) = L.

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What is the Squeeze Theorem?

If f(x)leqg(x)leqh(x)f(x) leq g(x) leq h(x) and limxaf(x)=limxah(x)=L\lim_{x \to a} f(x) = \lim_{x \to a} h(x) = L, then limxag(x)=L\lim_{x \to a} g(x) = L.

Define 'limit' in calculus.

The value that a function approaches as the input approaches a specific value.

What are bounding functions?

Functions that enclose another function, used in the Squeeze Theorem.

Define continuity at a point.

A function f(x)f(x) is continuous at x=ax=a if limxaf(x)=f(a)\lim_{x \to a} f(x) = f(a).

What does the graph of xcos(1x)x\cos(\frac{1}{x}) squeezed between x-|x| and x|x| tell us?

It visually confirms that as xx approaches 0, xcos(1x)x\cos(\frac{1}{x}) is forced to approach 0 as well.

State the Squeeze Theorem.

If f(x)g(x)h(x)f(x) \leq g(x) \leq h(x) for all xx in an interval containing aa (except possibly at aa itself) and limxaf(x)=limxah(x)=L\lim_{x \to a} f(x) = \lim_{x \to a} h(x) = L, then limxag(x)=L\lim_{x \to a} g(x) = L.