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  1. AP Calculus
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What is the arc length formula for y=f(x)y=f(x)y=f(x) from x=ax=ax=a to x=bx=bx=b?

S=∫ab1+[f′(x)]2dxS=\int_a^b \sqrt{1+[f'(x)]^2} dxS=∫ab​1+[f′(x)]2​dx

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What is the arc length formula for y=f(x)y=f(x)y=f(x) from x=ax=ax=a to x=bx=bx=b?

S=∫ab1+[f′(x)]2dxS=\int_a^b \sqrt{1+[f'(x)]^2} dxS=∫ab​1+[f′(x)]2​dx

What does f′(x)f'(x)f′(x) represent in the arc length formula?

The derivative of the function f(x)f(x)f(x) with respect to xxx.

Explain how the Pythagorean Theorem relates to the arc length formula.

The arc length formula uses the Pythagorean theorem (c=a2+b2c=\sqrt{a^2+b^2}c=a2+b2​) to find the length of small segments on the curve, where 1 represents the square of the length along the x-axis and [f′(x)]2[f'(x)]^2[f′(x)]2 represents the square of the length along the y-axis.

How does arc length relate to distance traveled?

Arc length provides a way to calculate the distance traveled along a curve, even when the curve is complex and continuously changing.

Why is arc length important in calculus?

It allows us to calculate the distance traveled along a curve, which is crucial in various applications in mathematics and physics.

How do you find the arc length of y=x2y=x^2y=x2 from x=0x=0x=0 to x=3x=3x=3?

  1. Find f′(x)=2xf'(x) = 2xf′(x)=2x. 2. Apply the arc length formula: S=∫031+(2x)2dxS=\int_0^3 \sqrt{1+(2x)^2} dxS=∫03​1+(2x)2​dx. 3. Evaluate the integral (approximately 3.823).

Steps to calculate distance traveled along a curve?

  1. Define the function f(x)f(x)f(x). 2. Find the derivative f′(x)f'(x)f′(x). 3. Apply the arc length formula S=∫ab1+[f′(x)]2dxS = \int_a^b \sqrt{1 + [f'(x)]^2} dxS=∫ab​1+[f′(x)]2​dx. 4. Evaluate the integral.