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  1. AP Calculus
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Define a power series.

An infinite series of polynomials representing a function, generally expressed as ∑n=0∞an(x−r)\displaystyle\sum_{n=0}^{\infty}{a_n(x-r)}n=0∑∞​an​(x−r).

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Define a power series.

An infinite series of polynomials representing a function, generally expressed as ∑n=0∞an(x−r)\displaystyle\sum_{n=0}^{\infty}{a_n(x-r)}n=0∑∞​an​(x−r).

What is ana_nan​ in a power series?

ana_nan​ is a sequence of real numbers in the power series ∑n=0∞an(x−r)\displaystyle\sum_{n=0}^{\infty}{a_n(x-r)}n=0∑∞​an​(x−r).

What does 'r' represent in a power series?

'r' represents a real number in the power series ∑n=0∞an(x−r)\displaystyle\sum_{n=0}^{\infty}{a_n(x-r)}n=0∑∞​an​(x−r).

How can you find the power series of x2exx^2e^xx2ex if you know the power series of exe^xex?

Multiply the power series of exe^xex by x2x^2x2.

How to find the power series of f′(x)f'(x)f′(x) if you have the power series for f(x)f(x)f(x)?

Take the derivative of each term in the power series of f(x)f(x)f(x).

Find the power series for x2exx^2e^xx2ex.

  1. Start with ex=∑n=0∞xnn!e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!}ex=∑n=0∞​n!xn​. 2. Multiply each term by x2x^2x2. 3. Result: x2+x3+x42!+x53!+...+xn+2n!+...x^2 + x^3 + \frac{x^4}{2!} + \frac{x^5}{3!} + ... + \frac{x^{n+2}}{n!} + ...x2+x3+2!x4​+3!x5​+...+n!xn+2​+...

Find h′(x)h'(x)h′(x) if h(x)h(x)h(x) is the power series of cos⁡(x)\cos(x)cos(x) centered at x=0x=0x=0.

  1. Start with h(x)=1−x22!+x44!+...+(−1)nx2n(2n)!+...h(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} + ... + \frac{(-1)^nx^{2n}}{(2n)!} + ...h(x)=1−2!x2​+4!x4​+...+(2n)!(−1)nx2n​+.... 2. Take the derivative of each term. 3. Result: −x+x33!−x55!+...+(−1)nx2n−1(2n−1)!+...-x + \frac{x^3}{3!} - \frac{x^5}{5!} + ... + \frac{(-1)^nx^{2n-1}}{(2n-1)!} + ...−x+3!x3​−5!x5​+...+(2n−1)!(−1)nx2n−1​+...

Find the first four nonzero terms and the general term for an infinite series that represents f′(x)f'(x)f′(x), where f(x)=x−x33+x55−x77+...+(−1)nx2n+12n+1+...f(x)=x-\frac{x^3}{3}+\frac{x^5}{5}-\frac{x^7}{7}+...+\frac{(-1)^nx^{2n+1}}{2n+1}+...f(x)=x−3x3​+5x5​−7x7​+...+2n+1(−1)nx2n+1​+...

  1. Take the derivative of each term in f(x)f(x)f(x). 2. f′(x)=1−x2+x4−x6+...+(−1)nx2n+...f'(x) = 1 - x^2 + x^4 - x^6 + ... + (-1)^nx^{2n} + ...f′(x)=1−x2+x4−x6+...+(−1)nx2n+...