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  1. AP Calculus
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How can you find the power series of x2exx^2e^xx2ex if you know the power series of exe^xex?

Multiply the power series of exe^xex by x2x^2x2.

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How can you find the power series of x2exx^2e^xx2ex if you know the power series of exe^xex?

Multiply the power series of exe^xex by x2x^2x2.

How to find the power series of f′(x)f'(x)f′(x) if you have the power series for f(x)f(x)f(x)?

Take the derivative of each term in the power series of f(x)f(x)f(x).

Power series representation of exe^xex?

ex=∑n=0∞xnn!=1+x+x22!+x33!+…+xnn!e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!} = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \ldots+\frac{x^n}{n!}ex=∑n=0∞​n!xn​=1+x+2!x2​+3!x3​+…+n!xn​

Power series representation of cos⁡(x)\cos(x)cos(x)?

cos⁡(x)=∑n=0∞(−1)nx2n(2n)!=1−x22!+x44!−x66!+…+(−1)nx2n(2n)!\cos(x) = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n}}{(2n)!} = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \ldots+\frac{(-1)^nx^{2n}}{(2n)!}cos(x)=∑n=0∞​(2n)!(−1)nx2n​=1−2!x2​+4!x4​−6!x6​+…+(2n)!(−1)nx2n​

Power series representation of sin⁡(x)\sin(x)sin(x)?

sin⁡(x)=∑n=0∞(−1)nx2n+1(2n+1)!=x−x33!+x55!−x77!+…+(−1)nx2n+1(2n+1)!\sin(x) = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n+1}}{(2n+1)!} = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \ldots+\frac{(-1)^nx^{2n+1}}{(2n+1)!}sin(x)=∑n=0∞​(2n+1)!(−1)nx2n+1​=x−3!x3​+5!x5​−7!x7​+…+(2n+1)!(−1)nx2n+1​

Find the power series for x2exx^2e^xx2ex.

  1. Start with ex=∑n=0∞xnn!e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!}ex=∑n=0∞​n!xn​. 2. Multiply each term by x2x^2x2. 3. Result: x2+x3+x42!+x53!+...+xn+2n!+...x^2 + x^3 + \frac{x^4}{2!} + \frac{x^5}{3!} + ... + \frac{x^{n+2}}{n!} + ...x2+x3+2!x4​+3!x5​+...+n!xn+2​+...

Find h′(x)h'(x)h′(x) if h(x)h(x)h(x) is the power series of cos⁡(x)\cos(x)cos(x) centered at x=0x=0x=0.

  1. Start with h(x)=1−x22!+x44!+...+(−1)nx2n(2n)!+...h(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} + ... + \frac{(-1)^nx^{2n}}{(2n)!} + ...h(x)=1−2!x2​+4!x4​+...+(2n)!(−1)nx2n​+.... 2. Take the derivative of each term. 3. Result: −x+x33!−x55!+...+(−1)nx2n−1(2n−1)!+...-x + \frac{x^3}{3!} - \frac{x^5}{5!} + ... + \frac{(-1)^nx^{2n-1}}{(2n-1)!} + ...−x+3!x3​−5!x5​+...+(2n−1)!(−1)nx2n−1​+...

Find the first four nonzero terms and the general term for an infinite series that represents f′(x)f'(x)f′(x), where f(x)=x−x33+x55−x77+...+(−1)nx2n+12n+1+...f(x)=x-\frac{x^3}{3}+\frac{x^5}{5}-\frac{x^7}{7}+...+\frac{(-1)^nx^{2n+1}}{2n+1}+...f(x)=x−3x3​+5x5​−7x7​+...+2n+1(−1)nx2n+1​+...

  1. Take the derivative of each term in f(x)f(x)f(x). 2. f′(x)=1−x2+x4−x6+...+(−1)nx2n+...f'(x) = 1 - x^2 + x^4 - x^6 + ... + (-1)^nx^{2n} + ...f′(x)=1−x2+x4−x6+...+(−1)nx2n+...