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What is the general form of a p-series?

n=11np\sum_{n=1}^{\infty} \frac{1}{n^{p}}

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What is the general form of a p-series?

n=11np\sum_{n=1}^{\infty} \frac{1}{n^{p}}

What is the formula for the harmonic series?

n=11n\sum_{n=1}^{\infty} \frac{1}{n}

How do you determine convergence/divergence of n=11n2\sum_{n=1}^{\infty} \frac{1}{n^{2}}?

Identify p = 2. Since 2 > 1, the series converges.

How do you determine convergence/divergence of n=11n\sum_{n=1}^{\infty} \frac{1}{\sqrt{n}}?

Rewrite as n=11n1/2\sum_{n=1}^{\infty} \frac{1}{n^{1/2}}. Identify p = 1/2. Since 1/2 < 1, the series diverges.

How do you determine convergence/divergence of n=1n2n3\sum_{n=1}^{\infty} \frac{n^2}{n^3}?

Simplify to n=11n\sum_{n=1}^{\infty} \frac{1}{n}. Identify p = 1. Since p=1, the series diverges (Harmonic Series).

Determine convergence/divergence of n=11n0.75\sum_{n=1}^{\infty} \frac{1}{n^{0.75}}

Identify p = 0.75. Since 0.75 < 1, the series diverges.

Determine convergence/divergence of n=1n4\sum_{n=1}^{\infty} n^{-4}

Rewrite as n=11n4\sum_{n=1}^{\infty} \frac{1}{n^4}. Identify p = 4. Since 4 > 1, the series converges.

Determine convergence/divergence of n=1nn5\sum_{n=1}^{\infty} \frac{n}{\sqrt{n^5}}

Simplify to n=11n3/2\sum_{n=1}^{\infty} \frac{1}{n^{3/2}}. Identify p = 3/2. Since 3/2 > 1, the series converges.

Determine convergence/divergence of n=1(1n)3\sum_{n=1}^{\infty} (\frac{1}{n})^3

Rewrite as n=11n3\sum_{n=1}^{\infty} \frac{1}{n^3}. Identify p = 3. Since 3 > 1, the series converges.

Define a p-series.

A series of the form n=11np\sum_{n=1}^{\infty} \frac{1}{n^{p}}, where p is a constant.

Define a harmonic series.

A p-series where p = 1, represented as n=11n\sum_{n=1}^{\infty} \frac{1}{n}.

What does it mean for a series to converge?

The sum of the infinite terms approaches a finite value.

What does it mean for a series to diverge?

The sum of the infinite terms does not approach a finite value; it tends to infinity or oscillates.