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  1. AP Calculus
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What is an indeterminate form?

An expression whose limit cannot be evaluated directly, such as 00\frac{0}{0}00​ or ∞∞\frac{\infty}{\infty}∞∞​.

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What is an indeterminate form?

An expression whose limit cannot be evaluated directly, such as 00\frac{0}{0}00​ or ∞∞\frac{\infty}{\infty}∞∞​.

What does L'Hôpital's Rule help evaluate?

Limits of indeterminate forms.

What is L'Hôpital's Rule?

If lim⁡x→af(x)g(x)\lim_{x\to a}\frac{f(x)}{g(x)}limx→a​g(x)f(x)​ is of the form 00\frac{0}{0}00​ or ∞∞\frac{\infty}{\infty}∞∞​, then lim⁡x→af(x)g(x)=lim⁡x→af′(x)g′(x)\lim_{x\to a}\frac{f(x)}{g(x)} = \lim_{x\to a}\frac{f'(x)}{g'(x)}limx→a​g(x)f(x)​=limx→a​g′(x)f′(x)​.

How to evaluate lim⁡x→af(x)g(x)\lim_{x\to a}\frac{f(x)}{g(x)}limx→a​g(x)f(x)​ using L'Hôpital's Rule?

  1. Check if the limit is in indeterminate form. 2. Verify conditions: lim⁡x→af(x)=0\lim_{x \to a} f(x) = 0limx→a​f(x)=0 and lim⁡x→ag(x)=0\lim_{x \to a} g(x) = 0limx→a​g(x)=0 or both approach ±∞\pm \infty±∞. 3. Apply L'Hôpital's Rule: lim⁡x→af′(x)g′(x)\lim_{x\to a}\frac{f'(x)}{g'(x)}limx→a​g′(x)f′(x)​. 4. Evaluate the new limit.

Steps to solve lim⁡x→0sin⁡(3x)x\lim_{x \to 0} \frac{\sin(3x)}{x}limx→0​xsin(3x)​ using L'Hopital's Rule.

  1. Check indeterminate form: 00\frac{0}{0}00​. 2. Apply L'Hopital's Rule: lim⁡x→03cos⁡(3x)1\lim_{x \to 0} \frac{3\cos(3x)}{1}limx→0​13cos(3x)​. 3. Evaluate: 3\cos(0) = 3.

How to evaluate lim⁡x→∞3x2−87x2+21\lim_{x\to \infty} \frac{3x^2 - 8}{7x^2 + 21}limx→∞​7x2+213x2−8​?

  1. Check indeterminate form: ∞∞\frac{\infty}{\infty}∞∞​. 2. Apply L'Hôpital's Rule: lim⁡x→∞6x14x\lim_{x\to \infty} \frac{6x}{14x}limx→∞​14x6x​. 3. Simplify: 614=37\frac{6}{14} = \frac{3}{7}146​=73​.