$\text{Average Value} = \frac{1}{b-a} \int_{a}^{b} f(x) , dx$

$\int_{a}^{b} f(x) , dx$

The average y-value of a function over a given interval.

The function has no breaks, jumps, or undefined points on the closed interval from a to b.

The definite integral of a function f(x) from a to b represents the net signed area between the curve of f(x) and the x-axis from x=a to x=b.

1. Set up the integral: $\int_{a}^{b} f(x) , dx$. 2. Multiply by $\frac{1}{b-a}$. 3. Evaluate the expression.

Identify the interval [a,b] and the function f(x). Then setup: $\frac{1}{b-a} \int_{a}^{b} f(x) , dx$