zuai-logo
zuai-logo
  1. AP Calculus
FlashcardFlashcard
Study GuideStudy GuideQuestion BankQuestion Bank

Formula for velocity given position.

v(t)=ddts(t)=s′(t)v(t) = \frac{d}{dt}s(t) = s'(t)v(t)=dtd​s(t)=s′(t)

Flip to see [answer/question]
Flip to see [answer/question]
Revise later
SpaceTo flip
If confident

All Flashcards

Formula for velocity given position.

v(t)=ddts(t)=s′(t)v(t) = \frac{d}{dt}s(t) = s'(t)v(t)=dtd​s(t)=s′(t)

Formula for acceleration given velocity.

a(t)=ddtv(t)=v′(t)a(t) = \frac{d}{dt}v(t) = v'(t)a(t)=dtd​v(t)=v′(t)

Formula for acceleration given position.

a(t)=d2dt2s(t)=s′′(t)a(t) = \frac{d^2}{dt^2}s(t) = s''(t)a(t)=dt2d2​s(t)=s′′(t)

Formula for position given velocity.

s(t)=∫v(t)dt+Cs(t) = \int v(t) dt + Cs(t)=∫v(t)dt+C

Formula for velocity given acceleration.

v(t)=∫a(t)dt+Cv(t) = \int a(t) dt + Cv(t)=∫a(t)dt+C

Formula for displacement.

Δs=sf−si=∫titfv(t)dt\Delta s = s_f - s_i = \int_{t_i}^{t_f} v(t) dtΔs=sf​−si​=∫ti​tf​​v(t)dt

Formula for distance traveled.

∫titf∣v(t)∣dt\int_{t_i}^{t_f} |v(t)| dt∫ti​tf​​∣v(t)∣dt

How to find final position?

s(tf)=s(ti)+∫titfv(t)dts(t_f) = s(t_i) + \int_{t_i}^{t_f} v(t) dts(tf​)=s(ti​)+∫ti​tf​​v(t)dt

How to find final velocity?

v(tf)=v(ti)+∫titfa(t)dtv(t_f) = v(t_i) + \int_{t_i}^{t_f} a(t) dtv(tf​)=v(ti​)+∫ti​tf​​a(t)dt

What is the relationship between displacement and velocity?

Displacement is the integral of velocity over a time interval.

How to find s(t)s(t)s(t) given v(t)v(t)v(t) and s(0)s(0)s(0)?

  1. Integrate v(t)v(t)v(t) to find the general form of s(t)s(t)s(t). 2. Use s(0)s(0)s(0) to solve for the constant of integration. 3. Write the specific equation for s(t)s(t)s(t).

How to find v(t)v(t)v(t) given a(t)a(t)a(t) and v(0)v(0)v(0)?

  1. Integrate a(t)a(t)a(t) to find the general form of v(t)v(t)v(t). 2. Use v(0)v(0)v(0) to solve for the constant of integration. 3. Write the specific equation for v(t)v(t)v(t).

How to find displacement from t=at=at=a to t=bt=bt=b given v(t)v(t)v(t)?

  1. Evaluate the definite integral ∫abv(t)dt\int_{a}^{b} v(t) dt∫ab​v(t)dt.

How to find distance traveled from t=at=at=a to t=bt=bt=b given v(t)v(t)v(t)?

  1. Evaluate the definite integral ∫ab∣v(t)∣dt\int_{a}^{b} |v(t)| dt∫ab​∣v(t)∣dt.

How do you determine when an object changes direction given v(t)v(t)v(t)?

  1. Find when v(t)=0v(t) = 0v(t)=0. 2. Check if the sign of v(t)v(t)v(t) changes around those points.

How do you determine when an object is speeding up?

  1. Find when v(t)v(t)v(t) and a(t)a(t)a(t) have the same sign.

How do you determine when an object is slowing down?

  1. Find when v(t)v(t)v(t) and a(t)a(t)a(t) have opposite signs.

Given v(t)v(t)v(t) and an interval [a,b][a, b][a,b], how do you find the maximum position?

  1. Find critical points by setting v(t)=0v(t) = 0v(t)=0. 2. Evaluate s(t)s(t)s(t) at critical points and endpoints. 3. Choose the largest value.

How do you solve for the total distance traveled when v(t)v(t)v(t) changes sign on the interval?

  1. Find the times when v(t)=0v(t) = 0v(t)=0. 2. Break the integral into subintervals based on these times. 3. Integrate ∣v(t)∣|v(t)|∣v(t)∣ over each subinterval and add the results.

How do you find the average velocity on the interval [a,b][a,b][a,b]?

  1. Calculate the displacement: ∫abv(t)dt\int_{a}^{b} v(t) dt∫ab​v(t)dt. 2. Divide the displacement by the time interval (b−a)(b-a)(b−a).

What are the differences between displacement and distance traveled?

Displacement: Change in position, can be negative | Distance Traveled: Total path length, always non-negative.

What are the differences between velocity and speed?

Velocity: Rate of change of position with direction (can be negative) | Speed: Magnitude of velocity (always non-negative).

Compare finding displacement using definite integrals vs. indefinite integrals.

Definite Integral: Directly calculates displacement over an interval | Indefinite Integral: Gives a general position function, requires initial position to find displacement.

Compare finding velocity using derivatives vs. integrals.

Derivatives: Find velocity from position function | Integrals: Find velocity from acceleration function.

Compare average velocity and instantaneous velocity.

Average Velocity: Displacement over a time interval | Instantaneous Velocity: Velocity at a specific moment in time.

Compare positive and negative acceleration.

Positive Acceleration: Velocity is increasing | Negative Acceleration: Velocity is decreasing (deceleration).

Compare constant velocity and constant acceleration.

Constant Velocity: Acceleration is zero, object moves at a steady rate | Constant Acceleration: Velocity changes at a steady rate.

Compare the effect of integrating velocity when v(t)>0v(t)>0v(t)>0 vs v(t)<0v(t)<0v(t)<0.

v(t) > 0: Displacement is positive, object moves in positive direction | v(t) < 0: Displacement is negative, object moves in negative direction.

Compare the meaning of a zero velocity and a zero acceleration.

Zero Velocity: Object is momentarily at rest | Zero Acceleration: Velocity is constant.

Compare the use of initial position and initial velocity in solving motion problems.

Initial Position: Used to find the constant of integration when integrating velocity | Initial Velocity: Used to find the constant of integration when integrating acceleration.