Analytical Applications of Differentiation
Can a local extremum be a global extremum?
Yes, a global extremum is also a local extremum.
Yes, but only if the local extremum occurs at x = 1.
Yes, but only if the local extremum occurs at x = 0.
No, a local extremum can never be a global extremum.
Identify the critical point(s) for the function .
If a continuous function has a derivative that exists everywhere except at , which of the following statements must be true regarding the existence of an absolute maximum or minimum for over a closed interval containing ?
The absence of the derivative at guarantees no extreme value can occur there.
A critical point may occur at , potentially leading to an absolute extremum if all other values are less extreme.
The Extreme Value Theorem ensures that an absolute maximum and minimum cannot exist in this scenario.
Since the derivative does not exist at , it implies that both an absolute maximum and minimum must occur at points different from .
Given the function on the interval [0,3], at which value of is there a critical point?
What must be true for a function to have an absolute maximum at in a closed interval?
The value of is greater than or equal to every other function value on the interval.
The second derivative of is positive at .
The derivative of is zero at .
There are no other critical points in the interval.
If the function has a critical point at , which of the following justifies that is neither a local minimum nor a local maximum?
The first derivative test shows that decreases before and after .
The original function, , is greater than zero.
The second derivative, , equals zero and changes sign around .
The first derivative, , equals zero but does not change sign around .
Which conclusion can be drawn if for some where ?
Function reaches global maxima always when .
There's likely to be local minima at .
There should exist an inflection point exactly when .
Existence of critical point at implies discontinuity in .

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For what reason might we prefer using critical points instead of endpoints to find global extrema on open intervals?
Endpoints guarantee only local extrema while critical points provide information about global extrema as well.
Evaluating functions at endpoints may give false positives for global extrema due to potential discontinuities there.
Endpoints do not exist for open intervals; thus we rely on critical points to identify possible global extrema within these intervals.
Critical points are easier to calculate than evaluating functions at their endpoints for any given interval.
How are critical points of a function defined?
Points where the function is always increasing
Points where the function has an asymptote
Points where the function is always decreasing
Points where the function is not differentiable or where the derivative is equal to 0
How can relative extrema be identified by analyzing the derivatives of a function?
By analyzing the rate of change of the function
By analyzing the function values at the endpoints of the interval
By analyzing the integral of the function
By analyzing the signs and changes in the first and second derivatives