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  1. AP Calculus
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Differential Equations

Question 1
college-boardCalculus AB/BCAPExam Style
1 mark

What is the purpose of writing the differential equation in standard form before applying separation of variables?

Question 2
college-boardCalculus AB/BCAPExam Style
1 mark

What must be done after performing integration on each side when solving a separable differential equation?

Question 3
college-boardCalculus AB/BCAPExam Style
1 mark

Given that dxdt=x2(t−1)\frac{dx}{dt} = x^2(t-1)dtdx​=x2(t−1), with initial condition (1,d)(1,d)(1,d) where d>0d>0d>0, what is the effect on ddd if we want to ensure that xxx grows without bound for all t>1t>1t>1?

Question 4
college-boardCalculus AB/BCAPExam Style
1 mark

Solve the initial value problem dydx=1x\frac{dy}{dx} = \frac{1}{x}dxdy​=x1​, y(1)=0y(1) = 0y(1)=0.

Question 5
college-boardCalculus AB/BCAPExam Style
1 mark

Find the general solution for the differential equation dydx=2cos⁡(x)\frac{dy}{dx} = 2\cos(x)dxdy​=2cos(x).

Question 6
college-boardCalculus AB/BCAPExam Style
1 mark

How are general solutions defined in the context of differential equations?

Question 7
college-boardCalculus AB/BCAPExam Style
1 mark

What is the first step in solving the differential equation dydx=3x2y\frac{dy}{dx} = 3x^2ydxdy​=3x2y by separation of variables?

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Question 8
college-boardCalculus AB/BCAPExam Style
1 mark

Given a separable differential equation where dydx=g(x)h(y)\frac{dy}{dx}=g(x)h(y)dxdy​=g(x)h(y), for which values of x must g(x) be continuous?

Question 9
college-boardCalculus AB/BCAPExam Style
1 mark

What is the general solution of the differential equation dydx=ycos⁡(x)\frac{dy}{dx} = y \cos(x)dxdy​=ycos(x) using the method of separation of variables?

Question 10
college-boardCalculus AB/BCAPExam Style
1 mark

Solve the initial value problem dydx=2x\frac{dy}{dx} = 2xdxdy​=2x, y(0)=3y(0) = 3y(0)=3.