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  1. AP Calculus
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Applications of Integration

Question 1
college-boardCalculus AB/BCAPExam Style
1 mark

Given the function f(y)=1y2f(y) = \frac{1}{y^2}f(y)=y21​, which alteration to this function would result in the greatest increase in the area between it and the y-axis from y=1y = 1y=1 to y=2y = 2y=2?

Question 2
college-boardCalculus AB/BCAPExam Style
1 mark

What happens when using Integration Formulas without considering the order of functions for area calculation between f(y)f(y)f(y) and g(y)g(y)g(y)?

Question 3
college-boardCalculus AB/BCAPExam Style
1 mark

Given two curves defined by their parametric equations, x1(t)=t3−t2+tx_1(t) = t^3 - t^2 + tx1​(t)=t3−t2+t, y1(t)=ety_1(t) = e^{t}y1​(t)=et and x2(t)=sin⁡(t)x_2(t) = \sin(t)x2​(t)=sin(t), y2(t)=ln⁡(t)y_2(t) = \ln(t)y2​(t)=ln(t) for t>0{t > 0}t>0, how would you find the coordinates where they intersect?

Question 4
college-boardCalculus AB/BCAPExam Style
1 mark

How do you determine the exact area between two polar curves given by r1(θ)=a(1+cos⁡(θ))r_1(\theta)=a(1+\cos(\theta))r1​(θ)=a(1+cos(θ)) and r2(θ)=b(1−cos⁡(θ))r_2(\theta)=b(1-\cos(\theta))r2​(θ)=b(1−cos(θ)) over an interval [0,π][0,\pi][0,π]?

Question 5
college-boardCalculus AB/BCAPExam Style
1 mark

If you must evaluate an enclosed region by integrating horizontally between two curves described by x=f(y)x = f(y)x=f(y) and x=g(y)x = g(y)x=g(y) from ccc to ddd in terms of dydydy, what step is crucial before applying integration?

Question 6
college-boardCalculus AB/BCAPExam Style
1 mark

What would be the proper setup for an integral to find the area between two curves expressed as functions of y if the first function is h(y)=y3/2h(y) = y^{3/2}h(y)=y3/2 and the second function is k(y)=(4−y)2k(y) = (4-y)^2k(y)=(4−y)2 over the interval from 0 to ?

Question 7
college-boardCalculus AB/BCAPExam Style
1 mark

Determine the area enclosed by the curves y=exy = e^xy=ex and y=1xy = \frac{1}{x}y=x1​ for 1≤y≤e1 \leq y \leq e1≤y≤e.

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Question 8
college-boardCalculus AB/BCAPExam Style
1 mark

For what reason does computing the definite integral ∫−13(x+4−x+43)dy\int_{-1}^{3} (\sqrt{x+4}-\sqrt[3]{x+4}) dy∫−13​(x+4​−3x+4​)dy not yield a valid solution when determining the area bounded by these two curves?

Question 9
college-boardCalculus AB/BCAPExam Style
1 mark

If you have two curves, f(y)f(y)f(y) and g(y)g(y)g(y), how do you write an integral expression for the area between these curves?

Question 10
college-boardCalculus AB/BCAPExam Style
1 mark

Find the area enclosed by the curves y=sin(x)y = \\sin(x)y=sin(x) and y=cos(x)y = \\cos(x)y=cos(x) for 0leqyleq10 \\leq y \\leq 10leqyleq1.