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  1. AP Calculus
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Integrating Vector-Valued Functions

Benjamin Wright

Benjamin Wright

6 min read

Next Topic - Solving Motion Problems Using Parametric and Vector-Valued Functions

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Study Guide Overview

This study guide covers integrating vector-valued functions. It explains how to integrate these functions component-wise in both two and three dimensions. It provides examples, including a walkthrough and a practice word problem involving velocity and position. The guide also briefly discusses the applications of integrating vector-valued functions, such as finding total area moved over time.

#9.5 Integrating Vector-Valued Functions

By now, you should have a good understanding of vector functions. It’s alright if you don’t, for a refresher you can read our 9.4 study guide which talks about defining and differentiating vector-valued functions. This will help you understand this study guide and new concept easier!

Integrating these vector-valued functions allows us to go backward when relating the movement of a particle to its equation. For example, let's say we have a vector-valued function that gives the acceleration of a particle moving in space. A question asks us to determine the velocity of said particle. This means we need ✨integration✨

#💭 Integrating Vector-Valued Functions

It’s good to first recognize the format of your function. It is either written in two or three dimensions; we want to know which one so that we are not confused about which terms should be paid attention to when integrating.

A two-dimension vector function might look like this:

r(t)=f(t)i+g(t)jr(t)=f(t)i+g(t)jr(t)=f(t)i+g(t)j

or like this:

r(t)=⟨f(t),g(t)⟩r(t)=⟨f(t),g(t)⟩r(t)=⟨f(t),g(t)⟩

These both mean the same thing! 🪄

#❓ How do we integrate?

Luckily, we integrate each component of a vector function separate...

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Previous Topic - Defining and Differentiating Vector-Valued FunctionsNext Topic - Solving Motion Problems Using Parametric and Vector-Valued Functions

Question 1 of 9

Given the vector-valued function r(t)=<t3,cos⁡(t)>r(t) = <t^3, \cos(t)>r(t)=<t3,cos(t)>, what is the result of integrating only the first component with respect to t?

<t44\frac{t^4}{4}4t4​ ,cos⁡(t)\cos(t)cos(t)>

t44\frac{t^4}{4}4t4​ + C

<t44\frac{t^4}{4}4t4​ +C ,sin⁡(t)\sin(t)sin(t) +C>

<t4,sin⁡(t)t^4, \sin(t)t4,sin(t)>