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  2. AP Chemistry
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Intermolecular Forces and Properties

Question 1
ChemistryAPConcept Practice
1 mark

Which of the following statements best describes the key difference between Dalton's atomic model and Rutherford's atomic model?

Question 2
ChemistryAPConcept Practice
1 mark

Which experimental evidence led to the rejection of Thomson's plum pudding model of the atom?

Question 3
ChemistryAPConcept Practice
1 mark

A photon of light has a frequency of 5.0×10145.0 \times 10^{14}5.0×1014 Hz. What is the energy of this photon? (Planck's constant, h=6.626×10−34h = 6.626 \times 10^{-34}h=6.626×10−34 Js)

Question 4
ChemistryAPConcept Practice
1 mark

A photon has an energy of 39.78 kJ/mol. What is the frequency of this photon? (h=6.626×10−34h = 6.626 \times 10^{-34}h=6.626×10−34 Js)

Question 5
ChemistryAPConcept Practice
1 mark

What is the energy of one mole of photons with a wavelength of 450 nm? (h=6.626×10−34h = 6.626 \times 10^{-34}h=6.626×10−34 Js, c=3.00×108c = 3.00 \times 10^{8}c=3.00×108 m/s)

Question 6
ChemistryAPConcept Practice
1 mark

Which of the following best describes the photoelectric effect?

Question 7
ChemistryAPConcept Practice
1 mark

Why does the photoelectric effect support the particle nature of light?

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Question 8
ChemistryAPConcept Practice
1 mark

In the photoelectric effect, what happens to the number of electrons ejected from a metal surface when the intensity of light shone on the metal is increased (assuming the frequency of the light is above the threshold frequency)?

Question 9
ChemistryAPConcept Practice
1 mark

Light with a frequency of 2.0×10152.0 \times 10^{15}2.0×1015 Hz is shone on a metal with a work function (binding energy) of 4.0×10−194.0 \times 10^{-19}4.0×10−19 J. What is the kinetic energy of the ejected electrons?

Question 10
ChemistryAPConcept Practice
1 mark

The following data was obtained from a photoelectric effect experiment: Wavelength of light = 200 nm, Kinetic energy of ejected electrons = 3.97×10−193.97 \times 10^{-19}3.97×10−19 J. What is the threshold frequency of the metal? (h=6.626×10−34h = 6.626 \times 10^{-34}h=6.626×10−34 Js, c=3.00×108c = 3.00 \times 10^{8}c=3.00×108 m/s)