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  1. AP Chemistry
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Applications of Thermodynamics

Question 1
ChemistryAPConcept Practice
1 mark

Which of the following best describes the 'system' in thermodynamics?

Question 2
ChemistryAPConcept Practice
1 mark

Which process leads to an increase in entropy (S°S°S°)?

Question 3
ChemistryAPConcept Practice
1 mark

Given the following standard molar entropies: S°(N2(g))=191.6Jmol⋅KS°(N_2(g)) = 191.6 \frac{J}{mol \cdot K}S°(N2​(g))=191.6mol⋅KJ​, S°(H2(g))=130.7Jmol⋅KS°(H_2(g)) = 130.7 \frac{J}{mol \cdot K}S°(H2​(g))=130.7mol⋅KJ​, and S°(NH3(g))=192.3Jmol⋅KS°(NH_3(g)) = 192.3 \frac{J}{mol \cdot K}S°(NH3​(g))=192.3mol⋅KJ​, calculate the standard entropy change (ΔS°ΔS°ΔS°) for the reaction: N2(g)+3H2(g)→2NH3(g)N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)N2​(g)+3H2​(g)→2NH3​(g)

Question 4
ChemistryAPConcept Practice
1 mark

If a reaction has a Gibbs Free Energy change of ΔG°=−50kJmolΔG° = -50 \frac{kJ}{mol}ΔG°=−50molkJ​, the reaction is:

Question 5
ChemistryAPConcept Practice
1 mark

Calculate the standard Gibbs Free Energy change (ΔG°ΔG°ΔG°) at 298 K for a reaction where the standard enthalpy change (ΔH°ΔH°ΔH°) is -100 kJ/mol and the standard entropy change (ΔS°ΔS°ΔS°) is -50 J/(mol·K).

Question 6
ChemistryAPConcept Practice
1 mark

The standard Gibbs Free Energy change (ΔG°ΔG°ΔG°) for a reaction is +25kJmol+25 \frac{kJ}{mol}+25molkJ​ at 298 K. Calculate the equilibrium constant (K) for this reaction. (R = 8.314 J/(mol·K))

Question 7
ChemistryAPConcept Practice
1 mark

A reaction has a positive ΔH°ΔH°ΔH° and a negative ΔS°ΔS°ΔS°. How will increasing the temperature affect the spontaneity of the reaction?

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Question 8
ChemistryAPConcept Practice
1 mark

Which of the following is a characteristic of a galvanic cell?

Question 9
ChemistryAPConcept Practice
1 mark

Calculate the cell potential (E°cellE°_{cell}E°cell​) for a galvanic cell composed of the following two half-reactions: Zn2+(aq)+2e−→Zn(s)Zn^{2+}(aq) + 2e^- \rightarrow Zn(s)Zn2+(aq)+2e−→Zn(s), E°=−0.76VE° = -0.76 VE°=−0.76V Cu2+(aq)+2e−→Cu(s)Cu^{2+}(aq) + 2e^- \rightarrow Cu(s)Cu2+(aq)+2e−→Cu(s), E°=+0.34VE° = +0.34 VE°=+0.34V

Question 10
ChemistryAPConcept Practice
1 mark

For a redox reaction, the cell potential (E°E°E°) is +0.50 V at 298 K. Calculate the standard Gibbs Free Energy change (ΔG°ΔG°ΔG°) for the reaction if two electrons are transferred (n = 2). (F = 96485 C/mol)