Hess’s Law

Ethan Taylor
8 min read
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Study Guide Overview
This study guide covers thermodynamics, focusing on state functions and Hess's Law. It defines pathway dependence/independence, lists examples of state functions (Energy, Enthalpy, Pressure, Volume, Temperature), and explains how to apply Hess's Law rules (reversing, multiplying, adding reactions) to calculate enthalpy changes. Example problems demonstrate Hess's Law application and manipulating thermochemical equations. Finally, it provides practice questions (multiple-choice and free-response) and exam tips for AP Chemistry.
#AP Chemistry Study Guide: Hess's Law & State Functions
Hey there, future AP Chem master! 👋 Let's break down Hess's Law and state functions. This guide is designed to be your go-to resource, especially the night before the exam. We'll make sure everything clicks, so you can walk in feeling confident and ready to ace it!
#Thermodynamics: State Functions & Hess's Law
#State Functions
In thermodynamics, we're all about changes in a system's state. Think of it like this: we care about where we start and where we end, not how we get there. Let's define some key terms:
#Pathway Dependent
- A process or function that does depend on the specific route or sequence of steps taken. 🛤️
- The result changes if you take a different path.
#Pathway Independent
- A process or function that does not depend on the specific route or sequence of steps taken. 🚀
- The result is the same no matter which path you choose.
State functions are pathway independent. They only care about the initial and final states of the system. Think of it like climbing a mountain ⛰️—the change in elevation is the same whether you take a straight path or a winding one.
- Examples of state functions:
- Energy (E)
- Enthalpy (H)
- Pressure (P)
- Volume (V)
- Temperature (T)
Mnemonic: Every Happy Penguin Volunteers Today - helps you remember the state functions: Energy, Henthalpy, Pressure, Volume, Temperature.
#Hess's Law
Hess's Law is a super useful tool that states: Enthalpy change (ΔH) is a state function. 💡 This means the total enthalpy change for a reaction is independent of the path taken. It's like a magic trick for calculating enthalpy changes! ✨
#Rules of Hess's Law
- Reversing a reaction: When you reverse a reaction, the sign of ΔH changes (e.g., +ΔH becomes -ΔH). 🔄
- Multiplying a reaction: If you multiply a reaction by a factor 'n', you also multiply the ΔH by 'n'. ✖️
- Adding reactions: When you add two or more reactions, you add their corresponding ΔH values to get the overall ΔH. ➕
#Hess's Law Example Problem #1
Let's dive into an example to make this crystal clear. Here's the reaction we want to find the enthalpy change for:
C₂H₂ (g) → 2C (s) + H₂ (g)
And we have the following thermochemical equations:
#Thought Process
-
Identify: Find the reactants and products in the given equations and the overall reaction.
-
Manipulate: Adjust the equations to match the overall reaction. Remember, what you do to the equation, you do to the enthalpy! 🔁✖️
- C (s): Needs a coefficient of 2, so we'll multiply equation #2 by 2. ❌
- H₂ (g): Already correct in equation #3. ✔️
- C₂H₂ (g): Is on the wrong side, so we'll flip equation #1. ❌
#Steps to Take
-
Step 1: Flip reaction 1 to get C₂H₂ on the product side. Change the sign of ΔH. 🔄
- 2CO₂ (g) + H₂O (l) → C₂H₂ (g) + 5/2O₂ (g) with ΔH° = +1299.5 kJ
-
Step 2: Multiply reaction 2 by 2 to get 2 solid carbon atoms. Multiply the enthalpy by 2. ✖️
#Results of Steps
After these manipulations, we have:
- Cancel out: Spectator compounds (O₂, H₂O, CO₂) cancel out when you add the equations.
- Add Enthalpies: Add the manipulated ΔH values together. ➕
ΔH = +1299.5 kJ + (−787 kJ) + (−285.8 kJ) = +226.7 kJ
#Hess's Law Example Problem #2
Let's try another one! Calculate ΔH for:
6PCl₅ (g) + 10Cl₃PO (g) → 10PCl₃ (g) + P₄O₁₀ (s)
Using these thermochemical equations:
#Thought Process
- P₄O₁₀: Wrong side, manipulate equation 2. ❌
- PCl₅: Wrong side and needs a coefficient of 6, manipulate equation 3. ❌
- Cl₃PO: Needs a coefficient of 10, manipulate equation 4. ❌
#Steps to Take
- Step 1: Flip equation 2. Change the sign of ΔH. 🔁
- Step 2: Flip equation 3 and multiply by 6. Multiply ΔH by -6. 🔁✖️
- Step 3: Multiply equation 4 by 10. Multiply ΔH by 10. ✖️
#Results of Steps
After these manipulations, we have:
- Balance: Notice that P₄, Cl₂, and PCl₃ are not balanced. They are all in equation 1. We need to manipulate equation 1. * Multiply: Multiply equation 1 by 4. Multiply ΔH by 4. ✖️
- Cancel: Everything cancels out, and we are left with the overall equation! 🥳
- Add Enthalpies: Add all the manipulated ΔH values together. ➕
ΔH = -1225.6 kJ + 2967.3 kJ + 505.2 kJ + (−2857 kJ) = -610.1 kJ
Always double-check that your final equation matches the target equation. Make sure all spectator species cancel out correctly.
#Final Exam Focus
- High-Priority Topics: Hess's Law, state functions, enthalpy changes, and manipulating thermochemical equations.
- Common Question Types:
- Multiple-choice questions that test your understanding of state functions and pathway dependency.
- Free-response questions that require you to apply Hess's Law to calculate enthalpy changes for complex reactions.
- Time Management: Practice doing these problems quickly. Focus on identifying the key species and manipulating equations efficiently.
- Common Pitfalls:
- Forgetting to change the sign of ΔH when reversing a reaction.
- Forgetting to multiply ΔH when multiplying a reaction by a coefficient.
- Not canceling out spectator species correctly.
Practice, practice, practice! The more you work through Hess's Law problems, the more comfortable you'll become. Pay close attention to the signs and coefficients.
#
Practice Question
Practice Questions
#Multiple Choice Questions
-
Which of the following is NOT a state function? (A) Enthalpy (B) Internal Energy (C) Work (D) Volume
-
Given the following reactions:
- A → B, ΔH = +20 kJ
- B → C, ΔH = -15 kJ What is the ΔH for the reaction A → C? (A) +35 kJ (B) +5 kJ (C) -5 kJ (D) -35 kJ
-
Consider the following reaction: 2H₂(g) + O₂(g) → 2H₂O(l), ΔH = -572 kJ What is the enthalpy change for the decomposition of 1 mol of liquid water? (A) -572 kJ (B) -286 kJ (C) +286 kJ (D) +572 kJ
#Free Response Question
Consider the following reactions:
- N₂(g) + O₂(g) → 2NO(g) ΔH₁ = +180 kJ
- 2NO(g) + O₂(g) → 2NO₂(g) ΔH₂ = -112 kJ
(a) Calculate the enthalpy change for the reaction:
N₂(g) + 2O₂(g) → 2NO₂(g)
(b) Draw an enthalpy diagram illustrating the relationship between the three reactions.
(c) If the reaction 2NO₂(g) → N₂(g) + 2O₂(g) is carried out, what is the enthalpy change?
#Scoring Breakdown
(a) (2 points)
- 1 point for correctly adding the two reactions
- 1 point for correctly calculating the enthalpy change: +180 kJ + (-112 kJ) = +68 kJ
(b) (2 points)
- 1 point for correctly labeling the reactants, products and intermediates
- 1 point for showing the correct enthalpy changes for each step
(c) (1 point)
- 1 point for correctly reversing the overall reaction and changing the sign of the enthalpy: -68 kJ
Remember to pay attention to the direction of the reaction and the sign of ΔH. Reversing a reaction changes the sign of ΔH!
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