Using Objects in AP Computer Science A

Com

pute

uter

Comp

equalsIgnoreCase(String other)

isSame(String other)

equalsWithoutCase(String other)

withoutCaseEquals(String other)

19

Throws an IndexOutOfBoundsException.

Compiles with an error.

18

info.getSubstring(start, end)

info.subString(start, end)

info.substring(start, end)

substring(info, start, end)

Str must contain at least one instance where contiguous characters are identical so substrings can join without loss informationally.

The string str must end with its starting character sequence up to length k-1 for correct alignment during concatenation checks against itself.

This condition will always hold true regardless of what str contains due to how substring concatenation works in Java.

Str must consist solely of repeating characters so that substring division doesn't affect equality comparison with original str.

An algorithm employing char arrays and building the result with a single pass through both arrays

An algorithm that uses pre-allocation of space by initializing StringBuilder with capacity

An algorithm using repeated concatenation with the ‘+’ operator inside a loop

An algorithm utilizing a StringBuilder appended inside a loop

1

0

-1

The index depends on the length of the string

Positive number less than or equal to ten

Negative number greater than -10

Positive integer more than ten

Zero

for loop

if statement

do-while loop

switch statement

"[aeiou]{3}".equals(phrase)

phrase.contains("[aeiou][aeiou][aeiou]")

phrase.matches(".[aeiou]{3}.")

phrase.indexOf("[aeiou]{3}") != -1