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Solving quadratic equations

Kevin Lee

Kevin Lee

8 min read

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Study Guide Overview

This guide covers solving quadratic equations for the AP SAT (Digital) exam using factoring, the quadratic formula, and completing the square. It explains the discriminant for analyzing roots and includes practice questions. Key topics are factoring techniques, applying the quadratic formula, and the completing the square process. The guide also provides exam tips, memory aids, and last-minute advice.

Quadratic Equations: Your Ultimate Guide 🚀

Hey there, future math whiz! Quadratic equations might seem intimidating, but they're just puzzles waiting to be solved. This guide is your go-to resource for mastering them, especially for the AP SAT (Digital) exam. Let's dive in!

Why Quadratics Matter? 🤔

Quadratic equations are everywhere! From figuring out projectile motion in physics to modeling growth in finance, they're a fundamental tool. Mastering them not only boosts your SAT score but also sets you up for success in higher-level math and science courses.

Overview of Solving Methods

There are three main ways to solve quadratic equations:

  1. Factoring: Great for equations that break down nicely.
  2. Quadratic Formula: Your trusty backup for any quadratic equation.
  3. Completing the Square: A bit more involved, but powerful for understanding the structure of quadratics.

Let's explore each method in detail!

Solving Quadratics by Factoring

Key Concept

Factoring Techniques

  • Standard Form: A quadratic equation is written as ax2+bx+c=0ax^2 + bx + c = 0, where a, b, and c are real numbers and a0a ≠ 0.
  • Zero Product Property: If the product of two factors is zero, at least one of the factors must be zero. This is the key to solving by factoring.
  • Finding the Right Numbers: Look for two numbers that multiply to acac and add up to bb.
  • Factoring with a=1a = 1: For equations like x2+bx+c=0x^2 + bx + c = 0, factor as (x+m)(x+n)=0(x + m)(x + n) = 0, where mm and nn are factors of cc that add up to bb.
  • Factoring with a1a ≠ 1: Factor out the greatest common factor (GCF) first, then factor the remaining quadratic expression.

Solving Process

  1. Factor the Quadratic Equation: Use the techniques above.
  2. Set Each Factor to Zero: Apply the zero product property.
  3. Solve for the Variable: Find the roots or solutions of the equation.

Examples

  • Example 1: Solve x2+5x+6=0x^2 + 5x + 6 = 0
    • Factors: (x+2)(x+3)=0(x + 2)(x + 3) = 0
    • Solutions: x=2x = -2 or x=3x = -3
  • Example 2: Solve 2x2+7x+3=02x^2 + 7x + 3 = 0
    • Factor: (2x+1)(x+3)=0(2x + 1)(x + 3) = 0
    • Solutions: x=1/2x = -1/2 or x=3x = -3
Practice Question
json
{
  "multiple_choice": [
    {
      "question": "What are the solutions to the equation <math-inline>x^2 - 5x + 6 = 0</math-inline>?",
      "options": [
        "x = 2 and x = 3",
        "x = -2 and x = -3",
        "x = 2 and x = -3",
        "x = -2 and x = 3"
      ],
      "answer": "x = 2 and x = 3"
    },
    {
      "question": "Solve for x: <math-inline>3x^2 + 10x - 8 = 0</math-inline>",
      "options": [
        "x = 2/3 and x = -4",
        "x = -2/3 and x = 4",
        "x = 3/2 and x = -4",
         "x = -3/2 and x = 4"
      ],
      "answer": "x = 2/3 and x = -4"
    }
  ],
  "free_response": {
    "question": "Solve the equation <math-inline>2x^2 + 7x - 15 = 0</math-inline> by factoring. Show all steps.",
    "solution": [
      "1. Rewrite the middle term: <math-inline>2x^2 + 10x - 3x - 15 = 0</math-inline>",
      "2. Factor by grouping: <math-inline>2x(x + 5) - 3(x + 5) = 0</math-inline>",
      "3. Factor out the common binomial: <math-inline>(2x - 3)(x + 5) = 0</math-inline>",
      "4. Set each factor equal to zero: <math-inline>2x - 3 = 0</math-inline> or <math-inline>x + 5 = 0</math-inline>",
      "5. Solve for x: <math-inline>x = 3/2</math-inline> or <math-inline>x = -5</math-inline>"
    ],
    "scoring": {
      "step_1": "1 point for rewriting the middle term correctly",
      "step_2": "1 point for factoring by grouping correctly",
      "step_3": "1 point for factoring out the common binomial",
      "step_4": "1 point for setting each factor equal to zero",
      "step_5": "1 point for solving for x correctly"
    }
  }
}

Solving Quadratics with the Quadratic Formula

Formula and Application

  • The Formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where aa, bb, and cc are the coefficients of the quadratic equation in standard form ax2+bx+c=0ax^2 + bx + c = 0, and a0a ≠ 0.
  • Universal Solver: This formula works for any quadratic equation, whether it's factorable or not.
  • Step-by-Step: Simplify the expression under the square root first, then add and subtract the square root term to find both solutions.

Example

  • Solve: 2x25x12=02x^2 - 5x - 12 = 0
    • a=2a = 2, b=5b = -5, c=12c = -12
    • x=5±(5)24(2)(12)2(2)x = \frac{5 \pm \sqrt{(-5)^2 - 4(2)(-12)}}{2(2)}
    • x=5±25+964=5±1214=5±114x = \frac{5 \pm \sqrt{25 + 96}}{4} = \frac{5 \pm \sqrt{121}}{4} = \frac{5 \pm 11}{4}
    • Solutions: x=4x = 4 or x=3/2x = -3/2

Key Concept

Discriminant Analysis

  • Discriminant: The expression b24acb^2 - 4ac under the square root in the quadratic formula.
  • Nature of Roots: The discriminant determines the nature of the roots:
    • Positive Discriminant: Two distinct real roots.
    • Zero Discriminant: One real root (a double root).
    • Negative Discriminant: No real roots (two complex roots).

Example

  • Analyze: x2+4x+5=0x^2 + 4x + 5 = 0
    • Discriminant =424(1)(5)=1620=4= 4^2 - 4(1)(5) = 16 - 20 = -4
    • A negative discriminant means no real roots.
Practice Question
json
{
  "multiple_choice": [
    {
      "question": "Use the quadratic formula to find the solutions to the equation <math-inline>x^2 - 6x + 5 = 0</math-inline>",
      "options": [
        "x = 1 and x = 5",
        "x = -1 and x = -5",
        "x = 1 and x = -5",
        "x = -1 and x = 5"
      ],
      "answer": "x = 1 and x = 5"
    },
    {
      "question": "How many real solutions does the equation <math-inline>2x^2 - 4x + 5 = 0</math-inline> have?",
      "options": [
        "0",
        "1",
        "2",
        "3"
      ],
      "answer": "0"
    }
  ],
  "free_response": {
    "question": "Use the quadratic formula to solve the equation <math-inline>3x^2 + 5x - 2 = 0</math-inline>. Show all steps.",
    "solution": [
      "1. Identify coefficients: <math-inline>a = 3, b = 5, c = -2</math-inline>",
      "2. Apply the quadratic formula: <math-inline>x = \frac{-5 \pm \sqrt{5^2 - 4(3)(-2)}}{2(3)}</math-inline>",
      "3. Simplify: <math-inline>x = \frac{-5 \pm \sqrt{25 + 24}}{6}</math-inline>",
      "4. Further simplification: <math-inline>x = \frac{-5 \pm \sqrt{49}}{6}</math-inline>",
      "5. Solve for x: <math-inline>x = \frac{-5 \pm 7}{6}</math-inline>, so <math-inline>x = 1/3</math-inline> or <math-inline>x = -2</math-inline>"
    ],
    "scoring": {
      "step_1": "1 point for correctly identifying a, b, and c",
      "step_2": "1 point for correctly applying the quadratic formula",
      "step_3": "1 point for simplifying the expression under the square root",
      "step_4": "1 point for further simplification",
      "step_5": "1 point for obtaining the correct solutions"
    }
  }
}

Solving Quadratics by Completing the Square

Completing the Square Process

  • Perfect Square Trinomial: This method creates a perfect square trinomial to solve quadratic equations.
  • Leading Coefficient: The leading coefficient of the quadratic term must be 1 (if not, divide both sides by the leading coefficient).
  • Rewrite the Equation: Rewrite the quadratic equation as x2+bx=cx^2 + bx = -c.
  • Add the Magic Number: Add the square of half the x-term coefficient to both sides: x2+bx+(b2)2=(b2)2cx^2 + bx + (\frac{b}{2})^2 = (\frac{b}{2})^2 - c.
  • Factor the Left Side: Factor the left side as a perfect square: (x+b2)2=(b2)2c(x + \frac{b}{2})^2 = (\frac{b}{2})^2 - c.
  • Take the Square Root: Take the square root of both sides and solve for xx to find the roots.

Applications and Examples

  • Deriving the Quadratic Formula: You can derive the quadratic formula by solving the general quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 using this method.

Example

  • Solve: x2+6x7=0x^2 + 6x - 7 = 0
    • Rewrite: x2+6x=7x^2 + 6x = 7
    • Add (6/2)2=9(6/2)^2 = 9 to both sides: x2+6x+9=16x^2 + 6x + 9 = 16
    • Factor the left side: (x+3)2=16(x + 3)^2 = 16
    • Take the square root: x+3=±4x + 3 = \pm 4
    • Solve for xx: x=3±4x = -3 \pm 4
    • Solutions: x=1x = 1 or x=7x = -7
Practice Question
json
{
  "multiple_choice": [
    {
      "question": "What is the value of 'c' that completes the square for the equation <math-inline>x^2 + 8x + c = 0</math-inline>?",
      "options": [
        "4",
        "8",
        "16",
        "64"
      ],
      "answer": "16"
    },
     {
      "question": "Solve for x using completing the square method: <math-inline>x^2 - 4x - 5 = 0</math-inline>",
      "options": [
         "x = -1 and x = 5",
        "x = 1 and x = -5",
        "x = -1 and x = -5",
         "x = 1 and x = 5"
      ],
      "answer": "x = -1 and x = 5"
    }
  ],
  "free_response": {
    "question": "Solve the equation <math-inline>x^2 - 6x + 8 = 0</math-inline> by completing the square. Show all steps.",
    "solution": [
      "1. Rewrite: <math-inline>x^2 - 6x = -8</math-inline>",
      "2. Add <math-inline>(6/2)^2 = 9</math-inline> to both sides: <math-inline>x^2 - 6x + 9 = -8 + 9</math-inline>",
      "3. Factor the left side: <math-inline>(x - 3)^2 = 1</math-inline>",
      "4. Take the square root: <math-inline>x - 3 = \pm 1</math-inline>",
      "5. Solve for x: <math-inline>x = 3 \pm 1</math-inline>, so <math-inline>x = 4</math-inline> or <math-inline>x = 2</math-inline>"
    ],
    "scoring": {
      "step_1": "1 point for correctly rewriting the equation",
      "step_2": "1 point for adding the correct value to both sides",
      "step_3": "1 point for factoring the left side correctly",
      "step_4": "1 point for taking the square root correctly",
      "step_5": "1 point for obtaining the correct solutions"
    }
  }
}

Exam Tip

Final Exam Focus

  • Highest Priority Topics: Factoring, using the quadratic formula, and understanding the discriminant are crucial. These concepts appear frequently in both multiple-choice and free-response questions.
  • Common Question Types: Expect to see questions that require you to solve quadratic equations, analyze the nature of roots, and apply these concepts in real-world scenarios.
  • Time Management: Practice solving quadratic equations quickly and accurately. Knowing when to use each method can save you valuable time.
  • Common Pitfalls: Be careful with signs, especially when using the quadratic formula. Double-check your calculations to avoid careless errors.

Memory Aid

Memory Aids

  • Quadratic Formula Song: Try singing the quadratic formula to the tune of "Pop Goes the Weasel" to help you remember it!
  • Discriminant Rule: Remember "Positive, Two; Zero, One; Negative, None" to quickly recall the number of real roots.
  • Completing the Square: Think of it as "making the left side a perfect square" to visualize the process.

Last-Minute Tips

  • Practice, Practice, Practice: The more you practice, the more confident you'll feel. Try solving a variety of quadratic equations.
  • Stay Calm: Take a deep breath and approach each question step-by-step. You've got this!
  • Review Your Notes: Use this guide as your final review. Focus on the key concepts and examples.

Good luck on your exam! You're well-prepared to tackle those quadratic equations. Let's ace this! 💪

Question 1 of 12

What are the three main methods for solving quadratic equations? 🤔

Graphing, Substitution, Elimination

Factoring, Quadratic Formula, Completing the Square

Synthetic Division, Long Division, Remainder Theorem

Cross-multiplication, Transposition, Elimination