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Limits

Sarah Miller

Sarah Miller

6 min read

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Study Guide Overview

This study guide covers the Squeeze Theorem (definition, formal statement, and worked example) and Trigonometric Limits, including important theorems like lim(x→0) (sin x)/x = 1 and lim(x→0) (cos x - 1)/x = 0. It also provides worked examples for trigonometric limits, practice questions, a glossary of terms, and key takeaways.

Study Notes: Squeeze Theorem and Trigonometric Limits

Table of Contents

  1. Squeeze Theorem
  2. Trigonometric Limits
  3. Practice Questions
  4. Glossary
  5. Summary and Key Takeaways

Squeeze Theorem

Definition

The squeeze theorem is a method used to determine the limit of a function that is bounded above and below by two other functions. If these bounding functions converge to the same limit at a specific point, the bounded function will also converge to that same limit.

Formal Statement

Let ff, gg, and hh be functions defined on an open interval containing aa such that:

  • g(x)f(x)h(x)g(x) \le f(x) \le h(x) for all xx in the interval, and
  • limxag(x)=limxah(x)=L\lim_{x \to a} g(x) = \lim_{x \to a} h(x) = L

Then: limxaf(x)=L\lim_{x \to a} f(x) = L

Worked Example

Let f(x)=x26x+13f(x) = x^2 - 6x + 13 and g(x)=6xx25g(x) = 6x - x^2 - 5. It is known that g(x)f(x)g(x) \le f(x) for 0 < x < 6. Let h(x)h(x) be another function such that 0 < x < 6. Find limx3h(x)\lim_{x \to 3} h(x).

Solution: First, find the limits for f(x)f(x) and g(x)g(x) at x=3x = 3 using substitution: limx3f(x)=(3)26(3)+13=4\lim_{x \to 3} f(x) = (3)^2 - 6(3) + 13 = 4

Question 1 of 8

If g(x)=x2+2g(x) = x^2 + 2 and h(x)=4x2h(x) = 4x - 2, and it's known that g(x)f(x)h(x)g(x) \le f(x) \le h(x) for 1 < x < 3, and limx2g(x)=6\lim_{x \to 2} g(x) = 6 and limx2h(x)=6\lim_{x \to 2} h(x) = 6, what is limx2f(x)\lim_{x \to 2} f(x)? 🤔

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