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Riemann Sums & Definite Integrals

David Brown

David Brown

8 min read

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Study Guide Overview

This study guide covers Riemann Sums as a method for approximating definite integrals. It explains the three main types: Left, Right, and Midpoint Riemann Sums, including how to calculate them and whether they overestimate or underestimate the integral. The guide provides worked examples, practice questions, a glossary of terms, and exam strategies.

Key Concept

Riemann Sums Study Notes

Table of Contents

  1. Introduction to Riemann Sums
  2. Types of Riemann Sums
  3. Worked Examples
  4. Practice Questions
  5. Glossary
  6. Summary and Key Takeaways
  7. Exam Strategy

Key Concept

Introduction to Riemann Sums

A Riemann sum is a technique for approximating the exact value of an accumulation of change, which is often represented as a definite integral or the area between a curve and the x-axis. The basic idea is to sum up the areas of multiple rectangles under a curve to estimate this value.

Key Concept

Types of Riemann Sums

There are three main types of Riemann sums:

  • Left Riemann Sum
  • Right Riemann Sum
  • Midpoint Riemann Sum

Left Riemann Sum

How to Calculate a Left Riemann Sum

To calculate the left Riemann sum of a function ff between x=ax=a and x=bx=b (where a<ba < b):

  1. Divide the interval into nn subintervals by choosing values x0,x1,...,xnx_0, x_1, ..., x_n such that a=x0<x1<<xn=ba = x_0 < x_1 < \cdots < x_n = b.
  2. Let this define nn rectangles.
  3. The width of the ii-th rectangle is (xixi1)(x_i - x_{i-1}), and the height is f(xi1)f(x_{i-1}).
  4. The left Riemann sum is the sum of the areas of these nn rectangles:

i=1n(xixi1)f(xi1)\sum_{i=1}^{n} (x_i - x_{i-1}) \cdot f(x_{i-1})

**Example:**

A social sciences researcher is using a function mm to model the total mass of garden gnomes appearing on lawns in a neighborhood over time tt. The table below gives selected values of m(t)m'(t), the rate of change of the mass, over the time interval 0 \le t \le 12. At time t=0t=0, m(0)=24.9m(0) = 24.9 kilograms.

t (days)0371012
m(t)m'(t) (kg/day)2.64.812.20.7-1.3

To find the left Riemann sum:

(3-0) \cdot 2.6 + (7-3) \cdot 4.8 + (10-7) \cdot ...

Question 1 of 12

What is the primary purpose of using a Riemann sum? 🤔

To find the exact area of a rectangle

To approximate the area under a curve

To calculate the derivative of a function

To find the x-intercept of a function