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Methods of Integration

Michael Green

Michael Green

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Study Guide Overview

This study guide covers polynomial long division to simplify rational functions for integration. Key steps include identifying the dividend and divisor, dividing leading terms, multiplying, and subtracting. It includes a worked example, exam tips, and practice questions. The guide also defines terms like remainder and indefinite integral.

#Integration Using Long Division

#Table of Contents

  1. Introduction to Polynomial Long Division
  2. Steps for Polynomial Long Division
  3. Worked Example
  4. Exam Tips
  5. Practice Questions
  6. Glossary
  7. Summary and Key Takeaways
Key Concept

#Introduction to Polynomial Long Division

Polynomial long division is a method used to simplify rational functions, making them easier to integrate. For example, consider the rational function:

x3+6x2−9x−11x−2\frac{x^3 + 6x^2 - 9x - 11}{x-2}x−2x3+6x2−9x−11​

Using polynomial long division, we can rewrite this function in a form that is easier to integrate.

Key Concept

#Steps for Polynomial Long Division

#Step 1: Setup

Identify the dividend (the polynomial you are dividing) and the divisor (the polynomial you are dividing by).

For example:

  • Dividend: x3+6x2−9x−11x^3 + 6x^2 - 9x - 11x3+6x2−9x−11
  • Divisor: x−2x - 2x−2

#Step 2: Divide the Leading Terms

Compare the highest power term in the dividend with the highest power term in the divisor.

x3÷x=x2x^3 \div x = x^2x3÷x=x2

Place x2x^2x2 on top of the division line.

#Step 3: Multiply and Subtract

Multiply the divisor by the term you just found and subtract it from the dividend.

x2⋅(x−2)=x3−2x2x^2 \cdot (x - 2) = x^3 - 2x^2x2⋅(x−2)=x3−2x2 Subtract from the dividend:

(x3+6x2−9x−11)−(x3−2x2)=8x2−9x−11(x^3 + 6x^2 - 9x - 11) - (x^3 - 2x^2) = 8x^2 - 9x - 11(x3+6x2−9x−11)−(x3−2x2)=8x2−9x−11

#Step 4: Repeat

Repeat the process with the new polynomial.

Divide: 8x2÷x=8x8x^2 \div x = 8x8x2÷x=8x

Multiply and Subtract: 8x⋅(x−2)=8x2−16x8x \cdot (x - 2) = 8x^2 - 16x8x⋅(x−2)=8x2−16x Subtract:

(8x2−9x−11)−(8x2−16x)=7x−11(8x^2 - 9x - 11) - (8x^2 - 16x) = 7x - 11(8x2−9x−11)−(8x2−16x)=7x−11

Divide: 7x÷x=77x \div x = 77x÷x=7

Multiply and Subtract: 7⋅(x−2)=7x−147 \cdot (x - 2) = 7x - 147⋅(x−2)=7x−14 Subtract:

(7x−11)−(7x−14)=3(7x - 11) - (7x - 14) = 3(7x−11)−(7x−14)=3

The remainder is 3. ### Final Answer Combine all the terms including the remainder:

x3+6x2−9x−11x−2=x2+8x+7+3x−2\frac{x^3 + 6x^2 - 9x - 11}{x-2} = x^2 + 8x + 7 + \frac{3}{x-2}x−2x3+6x2−9x−11​=x2+8x+7+x−23​

Key Concept

#Worked Example

#Problem

Find the indefinite integral:

∫x3+2x+13x+3,dx\int \frac{x^3 + 2x + 13}{x + 3} , dx∫x+3x3+2x+13​,dx

#Solution

Start by using polynomial long division. Add 0x20x^20x2 as a placeholder for the missing x2x^2x2 term:

x3+2x+13x+3=x2−3x+11−20x+3\frac{x^3 + 2x + 13}{x + 3} = x^2 - 3x + 11 - \frac{20}{x + 3}x+3x3+2x+13​=x2−3x+11−x+320​

Now integrate term by term:

∫(x2−3x+11−20x+3),dx\int \left( x^2 - 3x + 11 - \frac{20}{x + 3} \right) , dx∫(x2−3x+11−x+320​),dx

=∫x2,dx−∫3x,dx+∫11,dx−∫20x+3,dx= \int x^2 , dx - \int 3x , dx + \int 11 , dx - \int \frac{20}{x + 3} , dx=∫x2,dx−∫3x,dx+∫11,dx−∫x+320​,dx

=13x3−32x2+11x−20ln⁡∣x+3∣+C= \frac{1}{3} x^3 - \frac{3}{2} x^2 + 11x - 20 \ln|x + 3| + C=31​x3−23​x2+11x−20ln∣x+3∣+C

#Answer

∫x3+2x+13x+3,dx=13x3−32x2+11x−20ln⁡∣x+3∣+C\int \frac{x^3 + 2x + 13}{x + 3} , dx = \frac{1}{3} x^3 - \frac{3}{2} x^2 + 11x - 20 \ln|x + 3| + C∫x+3x3+2x+13​,dx=31​x3−23​x2+11x−20ln∣x+3∣+C

Exam Tip

#Exam Tips

Be extra careful when subtracting expressions with negative coefficients. Using brackets can help you keep track of things.

Practice Question

#Practice Questions

  1. Find the indefinite integral: ∫x3+4x2+x+2x+1,dx\int \frac{x^3 + 4x^2 + x + 2}{x + 1} , dx∫x+1x3+4x2+x+2​,dx

  2. Simplify and integrate: ∫2x3+3x2+x+5x+2,dx\int \frac{2x^3 + 3x^2 + x + 5}{x + 2} , dx∫x+22x3+3x2+x+5​,dx

Key Concept

#Glossary

  • Dividend: The polynomial being divided.
  • Divisor: The polynomial by which the dividend is divided.
  • Remainder: The leftover part of the dividend after division.
  • Indefinite Integral: The general form of the antiderivative, including a constant of integration CCC.
Key Concept

#Summary and Key Takeaways

#Summary

Polynomial long division simplifies rational functions, making them easier to integrate. The process involves dividing, multiplying, and subtracting terms in a step-by-step manner.

#Key Takeaways

  • Use polynomial long division to simplify rational functions.
  • Always compare the highest power terms during division.
  • Be meticulous with signs and subtraction to avoid errors.
  • Practice using polynomial long division to become proficient.

By mastering polynomial long division, you can handle a broader range of integration problems with confidence.

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Question 1 of 5

Ready to integrate? 🤔 When is polynomial long division typically used before integrating a rational function?

When the denominator is a constant

When the degree of the numerator is less than the degree of the denominator

When the degree of the numerator is greater than or equal to the degree of the denominator

Only when the denominator is a quadratic