zuai-logo

First-Order Differential Equations

Emily Davis

Emily Davis

5 min read

Listen to this study note

Study Guide Overview

This guide covers slope fields, which use tangent lines to represent solutions to differential equations. You'll learn to calculate gradients at points, estimate solutions by following the lines, and identify key features like horizontal tangents. The guide includes a worked example, practice questions, and a glossary of terms. Key topics include understanding boundary conditions when sketching solution curves.

Slope Fields Study Notes

Table of Contents

  1. Introduction to Slope Fields
  2. Calculating Gradients on a Slope Field
  3. Estimating Solutions Using Slope Fields
  4. Key Observations in Slope Fields
  5. Worked Example
  6. Practice Questions
  7. Glossary
  8. Summary and Key Takeaways
  9. Exam Strategy

Introduction to Slope Fields

A slope field for a differential equation is a graphical representation consisting of short tangent lines drawn at various points. These tangent lines illustrate the direction of the solution curve at those points.

Key Concepts

Key Concept
  • Gradient of Tangent Line: The gradient of each tangent line corresponds to the value of dydx\frac{dy}{dx} at that point. This is the same as the gradient of the solution curve passing through that point.
  • Regular Grid: Tangent lines are usually drawn at points forming a regularly spaced grid of xx and yy values.

Calculating Gradients on a Slope Field

To determine the gradient at a specific point on a slope field:

  1. Rewrite the differential equation in the form dydx=g(x,y)\frac{dy}{dx} = g(x, y) if it isn't already.
  2. Calculate the derivative dydx\frac{dy}{dx} at any point (x,y)(x, y) by substituting the xx and yy values into g(x,y)g(x, y).
**Example:** Given dydx=x2+y\frac{dy}{dx} = x^2 + y, to find the gradient at the point (1,2), substitute x=1x = 1 and y=2y = 2: \[ \frac{dy}{dx} = 1^2 + 2 = 3 \] Therefore, the gradient at (1,2) is 3.

Estimating Solutions Using Slope Fields

Slope fields can be used to estimate solutions to differential equations, particularly when an analytical solution is not feasible.

Steps to Sketch a Solution Curve

  1. Identify the Boundary Condition: The given point through which the solution curve must pass.
  2. Follow the Tangent Lines: Sketch the solution curve through the given point, following the tangent lines' general direction.
  3. Smooth Curve: Ensure that the sketched solution is smooth and does not cut across tangent lines.
Exam Tip

Exam Tip: The sketched solution curve should align with the direction of the tangent lines and should only pass through the given point on the grid.

Key Observations in Slope Fields

Horizontal Tangent Lines

  • Points where the tangent lines are horizontal indicate that dydx=0\frac{dy}{dx} = 0.
  • These points may represent local minima or maxima of the solution curve.
Common Mistake

Common Mistake: Not every point where dydx=0\frac{dy}{dx} = 0 is a local minimum or maximum. However, every local extremum occurs where dydx=0\frac{dy}{dx} = 0.

Identifying Critical Points

  • Solve dydx=g(x,y)=0\frac{dy}{dx} = g(x, y) = 0 to find points where the gradient is zero.
  • These points can help identify potential local extrema when they fall between grid points.

Worked Example

Consider the differential equation: [ \frac{dy}{dx} = -0.4 \left(y - 2\right)^{\frac{1}{3}}\left(x - 1\right)e^{-\frac{(x - 1)^2}{25}} ]

(a) Determine Points with Horizontal Tangents

The exponential function is never zero, so: [ \frac{dy}{dx} = 0 ] When: [ y - 2 = 0 \quad \text{or} \quad x - 1 = 0 ] Thus, solutions have horizontal tangents at y=2y = 2 or x=1x = 1.

(b) Sketch Solution Curve Through (0, -8)

  • Ensure the curve passes through (0, -8).
  • The curve should follow the flow of the tangent lines without cutting across any.

Practice Questions

Practice Question

Question 1: Given the differential equation dydx=xโˆ’y\frac{dy}{dx} = x - y, calculate the gradient at the point (2, 3).

Answer: [ \frac{dy}{dx} = 2 - 3 = -1 ]

Practice Question

Question 2: Sketch the solution curve for dydx=y+x2\frac{dy}{dx} = y + x^2 passing through (0,1)(0, 1).

Answer: The solution curve should start at (0, 1) and follow the general direction of the tangent lines in the slope field.

Glossary

  • Gradient: The slope of a curve at a given point.
  • Tangent Line: A straight line that touches a curve at a point without crossing it.
  • Differential Equation: An equation involving derivatives of a function.
  • Boundary Condition: A condition that specifies values of the solution at certain points.
  • Local Minimum/Maximum: Points where the function has a minimum or maximum value locally.

Summary and Key Takeaways

  • Slope fields visually represent the solutions of differential equations through tangent lines.
  • The gradient at any point on a slope field is given by dydx\frac{dy}{dx}.
  • Solution curves can be sketched by following the flow of tangent lines in the slope field.
  • Horizontal tangent lines indicate critical points where dydx=0\frac{dy}{dx} = 0.

Exam Strategy

  • Always start by rewriting the differential equation in the form dydx=g(x,y)\frac{dy}{dx} = g(x, y).
  • Identify and use boundary conditions to sketch solution curves accurately.
  • Pay attention to horizontal tangent lines to identify potential local extrema.
  • Practice sketching solution curves to gain confidence in interpreting slope fields.

By following these strategies and understanding the underlying concepts, you will be well-prepared to tackle questions involving slope fields in your exams.

Question 1 of 6

What do the short tangent lines in a slope field represent? ๐Ÿค”

The general shape of the solution curves

The rate of change of x with respect to y

The direction of the solution curve at various points

The points of intersection of the solution curves