Kinematics
Which of the following is a scalar quantity?
Velocity
Acceleration
Speed
Force
A car travels 40 km north and then 30 km south. Identify the quantities given in the scenario as scalars or vectors.
Distance is a vector, displacement is a scalar.
Distance and displacement are both vectors.
Distance is a scalar, displacement is a vector.
Distance and displacement are both scalars.
A hiker walks 5 km east, then 3 km north, then 2 km west. Which values are scalars and which are vectors? Justify your answer.
The total distance walked is a scalar because it only considers magnitude, while each individual leg of the journey (5 km east, 3 km north, 2 km west) is a vector because it includes both magnitude and direction.
The total distance walked is a vector because it considers magnitude, while each individual leg of the journey (5 km east, 3 km north, 2 km west) is a scalar because it includes both magnitude and direction.
The total distance walked and each individual leg of the journey (5 km east, 3 km north, 2 km west) are vectors because they all include magnitude and direction.
The total distance walked and each individual leg of the journey (5 km east, 3 km north, 2 km west) are scalars because they all only include magnitude.
What does the length of an arrow representing a vector indicate?
The direction of the vector.
The magnitude of the vector.
The type of vector.
The unit of the vector.
In one-dimensional motion, what does a negative sign in front of a vector quantity indicate?
The magnitude of the vector is decreasing.
The vector is less than zero.
The direction of the vector is opposite to the positive direction.
The vector quantity is a scalar.
A car is traveling east at 20 m/s. Represent the car's velocity as a vector. If east is considered the positive direction, how would you represent this velocity using vector notation in one dimension?
west
A car moves 10 m to the right, then 5 m to the left. What is the resultant displacement?
15 m to the right
5 m to the right
15 m to the left
5 m to the left

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An object moves 20 m east, then 15 m west, and then 10 m east again. What is the object's total displacement?
45 m east
5 m east
35 m west
15 m east
A person walks 3 km north, then 4 km west, then 2 km south, and finally 1 km east. Calculate the total displacement, considering both magnitude and direction, and explain the steps to arrive at the answer.
The total displacement is approximately 3.2 km in a direction 56.3° west of north. This is found by adding the north-south components (3 km - 2 km = 1 km north) and the east-west components (4 km west - 1 km east = 3 km west), then using the Pythagorean theorem to find the magnitude and trigonometry to find the direction.
The total displacement is approximately 3.2 km in a direction 56.3° east of north. This is found by adding the north-south components (3 km + 2 km = 5 km north) and the east-west components (4 km west + 1 km east = 5 km west), then using the Pythagorean theorem to find the magnitude and trigonometry to find the direction.
The total displacement is approximately 7 km in a direction 45° west of north. This is found by adding the north-south components (3 km - 2 km = 1 km north) and the east-west components (4 km west - 1 km east = 3 km west), then using the Pythagorean theorem to find the magnitude and trigonometry to find the direction.
The total displacement is approximately 7 km in a direction 45° east of north. This is found by adding the north-south components (3 km + 2 km = 5 km north) and the east-west components (4 km west + 1 km east = 3 km west), then using the Pythagorean theorem to find the magnitude and trigonometry to find the direction.
A student walks 5 meters east and then 5 meters west. What is the total distance the student traveled?
0 meters
5 meters
10 meters
25 meters