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Representing Motion

Ava Garcia

Ava Garcia

6 min read

Study Guide Overview

This study guide covers motion representation including motion diagrams, figures, graphs, equations, and narratives. It explains the kinematic equations for constant acceleration and their applications. It also covers acceleration due to gravity (g=10 m/s²) and interpreting motion graphs (position, velocity, and acceleration vs. time). Finally, it provides practice questions and exam tips.

Motion: Representing How Things Move 🚀

Hey there, future AP Physics 1 master! Let's break down motion representation, which is super important for understanding how objects move. Think of this as your ultimate cheat sheet for the night before the exam. We'll cover everything from motion diagrams to graphs, making sure you're ready to ace it!


Motion Representations: The Big Picture

Motion Diagrams and Descriptions

  • We use different ways to show motion: motion diagrams, figures, graphs, equations, and even written descriptions. 📊
  • Motion diagrams show an object's position at different times, like a flipbook of its movement.
  • Figures, like free-body diagrams, show the forces acting on an object.
  • Graphs show us how position, velocity, and acceleration change over time.
  • Equations give us the math to calculate motion.
  • Narrative descriptions explain the motion in words, giving us context.

Key Concept

Understanding how to interpret and switch between these representations is key to solving motion problems.


Kinematic Equations: Your Toolkit for Constant Acceleration

When acceleration is constant, we have these awesome equations:

  • vx=vxo+axtv_x = v_{xo} + a_xt (Final velocity using initial velocity, acceleration, and time)
  • x=xo+vxot+12axt2x = x_o + v_{xo}t + \frac{1}{2} a_xt^2 (Final position using initial position, initial velocity, acceleration, and time)
  • v2=vo2+2ax(xxo)v^2 = v_{o}^2 + 2a_x (x - x_o) (Final velocity using initial velocity, acceleration, and displacement)

Memory Aid

Remember these equations with the acronym VAT (Velocity, Acceleration, Time) and VAX (Velocity, Acceleration, Displacement) in mind.


  • These equations work in any direction (x, y, z) just change the variables.
  • Important: These only work for constant acceleration. If acceleration changes, you can't use these directly!

Acceleration Due to Gravity: Earth's Pull 🌍

  • Near Earth, gravity pulls things down with a constant acceleration of g=10,m/s2g = 10 , \text{m/s}^2.
  • This is a simplified value for AP Physics 1. You can use g=9.81,m/s2g = 9.81 , \text{m/s}^2 or g=9.8,m/s2g = 9.8 , \text{m/s}^2 if you want, but 10 is easiest.
  • Gravity only acts vertically. It doesn't care about an object's mass.

Quick Fact

Always use g=10,m/s2g = 10 , \text{m/s}^2 unless the question specifies otherwise.


Motion Graphs: Visualizing Movement 📈

  • Position vs. Time:
    • Slope = velocity
    • Positive slope = moving in the positive direction
    • Negative slope = moving in the negative direction
    • Steeper slope = higher velocity
  • Velocity vs. Time:
    • Slope = acceleration
    • Positive slope = speeding up
    • Negative slope = slowing down
    • Steeper slope = higher acceleration
    • Area under the curve = displacement
  • Acceleration vs. Time:
    • Area under the curve = change in velocity

Exam Tip

Remember: Slope of a graph gives you the rate of change of the y-axis quantity with respect to the x-axis quantity. Area under the curve gives you the product of the y-axis and x-axis quantities.


Common Mistake

Don't confuse displacement (area under velocity-time) with total distance traveled. Displacement can be negative, while distance is always positive.


Important Note: AP Physics 1 doesn't require you to do complex math with non-uniform acceleration. But, you should be able to understand and draw graphs for these situations.


Final Exam Focus: What to Really Nail Down

  • Kinematic Equations: Know them cold! Practice using them in different scenarios.
  • Motion Graphs: Be able to interpret and draw position, velocity, and acceleration graphs.
  • Gravity: Remember g=10,m/s2g = 10 , \text{m/s}^2 and that it acts vertically.
  • Connections: AP questions often combine multiple concepts, so understand how motion relates to forces and energy.

Last-Minute Tips:

  • Time Management: Don't spend too long on one question. If you're stuck, move on and come back later.
  • Common Pitfalls: Watch out for negative signs, units, and assumptions.
  • Challenging Questions: Break down complex problems into smaller steps. Use diagrams and graphs to visualize the situation.

Practice Questions

Practice Question

Multiple Choice Questions

  1. A car accelerates uniformly from rest to a speed of 20 m/s in 5 seconds. What is the magnitude of the car's acceleration? (A) 2 m/s² (B) 4 m/s² (C) 5 m/s² (D) 10 m/s²

  2. An object is thrown vertically upward. Which of the following is true about its velocity and acceleration at the highest point? (A) Velocity is zero, and acceleration is zero. (B) Velocity is zero, and acceleration is 10 m/s² downward. (C) Velocity is 10 m/s upward, and acceleration is zero. (D) Velocity is 10 m/s upward, and acceleration is 10 m/s² downward.

  3. The slope of a velocity-time graph represents: (A) Displacement (B) Acceleration (C) Position (D) Time

Free Response Question

A ball is thrown vertically upward from the ground with an initial velocity of 30 m/s. Assume no air resistance and use g = 10 m/s².

(a) Calculate the maximum height reached by the ball. (3 points) (b) Calculate the total time the ball is in the air. (3 points) (c) Sketch a velocity-time graph for the ball's motion from the moment it is thrown until it returns to the ground. (3 points) (d) If the ball was thrown on a planet with half the gravity of Earth, how would the maximum height reached by the ball change? Explain. (3 points)

Scoring Breakdown:

(a) Maximum Height (3 points)

  • 1 point: Using the correct kinematic equation: v2=v02+2aΔyv^2 = v_0^2 + 2 a \Delta y
  • 1 point: Setting final velocity to 0 at max height
  • 1 point: Correct answer: Δy=45m\Delta y = 45 m

(b) Total Time in Air (3 points)

  • 1 point: Recognizing that time to reach max height is half the total time.
  • 1 point: Using the correct kinematic equation: v=v0+atv = v_0 + at
  • 1 point: Correct answer: t=6st = 6 s

(c) Velocity-Time Graph (3 points)

  • 1 point: Correctly labeling axes
  • 1 point: Correctly showing a straight line with a negative slope
  • 1 point: Correctly showing the line crossing the x-axis at the midpoint (3s) and ending at -30 m/s

(d) Effect of Reduced Gravity (3 points)

  • 1 point: Recognizing that lower gravity will result in a higher maximum height.
  • 1 point: Using the correct kinematic equation to show that height is inversely proportional to gravity.
  • 1 point: Correct answer: The maximum height would double

You've got this! Go get that 5! 🌟