What is the effect of doubling the mass (m) on the period (T) of a mass-spring system?
The period increases by a factor of (sqrt{2}).
What is the effect of doubling the displacement (x) on the potential energy (U) of a spring?
The potential energy is quadrupled.
What happens to kinetic energy as an object in SHM approaches its equilibrium position?
Kinetic energy increases, reaching its maximum at the equilibrium position.
What happens to potential energy as an object in SHM reaches maximum displacement?
Potential energy is at its maximum value.
What happens when displacement (x) increases in a spring?
The potential energy (U) stored in the spring increases quadratically: \(U = \frac{1}{2}kx^2\).
What happens at the equilibrium position in SHM?
Kinetic energy is maximum, potential energy is minimum.
What happens at maximum displacement in SHM?
Kinetic energy is minimum (zero), potential energy is maximum.
What happens when the mass in a mass-spring system is doubled?
The period of oscillation increases by a factor of \(\sqrt{2}\).
How to calculate the period (T) of a mass-spring system?
Use the formula: \(T = 2\pi\sqrt{\frac{m}{k}}\) where m is mass and k is the spring constant.
How does energy transform in SHM?
Energy constantly shifts between kinetic energy (K) and potential energy (U), while the total energy remains constant (assuming no friction).
How to calculate the total energy of a SHO?
The total energy is the sum of kinetic and potential energy: \(E_{total} = K + U\).
