Displacement (Δx) is the change in position. It's a vector!

Velocity (v) is the rate of change of displacement. Also a vector!

Acceleration (a) is the rate of change of velocity. It's a vector.

Work (W) is the transfer of energy by a force. $W = Fd\cos(\theta)$.

Kinetic Energy (KE) is the energy of motion. $KE = \frac{1}{2}mv^2$.

Impulse (J) is the change in momentum. $J = F\Delta t = \Delta p$.

Torque ($\tau$) is the rotational analog of force. $\tau = rF\sin(\theta)$.

Centripetal acceleration ($a_c$) is the acceleration directed towards the center of the circle. $a_c = \frac{v^2}{r}$

Gravitational Force ($F_g$) is the attractive force between two masses. $F_g = G\frac{m_1m_2}{r^2}$, where G is the gravitational constant.

Momentum (p) is the product of mass and velocity. $p = mv$. It is a vector quantity.

Analyze horizontal and vertical motion separately. Horizontal motion: constant velocity ($\a_x = 0$). Vertical motion: constant acceleration due to gravity ($\a_y = -g = -9.8 m/s^2$).

Resolve forces into components parallel and perpendicular to the plane. $F_{g\parallel} = mg \sin(\theta)$, $F_{g\perp} = mg \cos(\theta)$

Set gravitational force equal to centripetal force: $G\frac{Mm}{r^2} = m\frac{v^2}{r}$.

Use the equation $\tau_{net} = I\alpha$ to relate net torque to rotational inertia and angular acceleration.

The change in position; a vector quantity.

The rate of change of displacement; a vector quantity.

The rate of change of velocity; a vector quantity.

Acceleration directed towards the center of the circle. $\a_c = \frac{v^2}{r}$

Net force causing circular motion. $\F_c = m\frac{v^2}{r}$

The transfer of energy by a force. $W = Fd\cos(\theta)$

Energy of motion. $KE = \frac{1}{2}mv^2$

Product of mass and velocity. $p=mv$. It is a vector quantity.

Change in momentum. $J = F\Delta t = \Delta p$.

Rotational analog of force. $\tau = rF\sin(\theta)$