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Conservation of Linear Momentum

Daniel Miller

Daniel Miller

9 min read

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Study Guide Overview

This study guide covers collisions and center of mass in AP Physics 1. It explains momentum conservation, differentiates between elastic and inelastic collisions, and provides the formula and examples for calculating center of mass. It also includes problem-solving strategies, exam tips, and practice questions.

AP Physics 1: Collisions & Center of Mass - The Night Before πŸš€

Hey there, future physicist! Let's get you prepped and confident for tomorrow's exam. We're going to break down collisions and center of mass, making sure everything clicks. Ready? Let's dive in!

1. Collisions: Momentum is Key! 🎯

1.1 What's a Collision?

A collision is when two or more objects interact, exerting forces on each other for a short period. Think of it like a quick high-five between objects. The most important thing to remember is that momentum is usually conserved during a collision.

Key Concept

Momentum Conservation: If the net external force on a system is zero (or negligible), the total momentum of the system remains constant. This is true for both elastic and inelastic collisions.

1.2 Types of Collisions

There are two main types of collisions:

  • Elastic Collisions: Objects bounce off each other, and both momentum and kinetic energy are conserved. It's like a perfect billiard ball hit - no energy is lost to heat or sound.

Quick Fact

Elastic Collision: KE initial = KE final

  • Inelastic Collisions: Objects either stick together or deform, and kinetic energy is not conserved (some energy is lost to heat, sound, etc.). Momentum is still conserved. Think of a car crash where the cars crumple.

Quick Fact

Inelastic Collision: KE initial β‰  KE final

*   **Completely Inelastic Collisions:** A special type of inelastic collision where objects stick together after colliding. 

Memory Aid

Memory Aid: Inelastic collisions are messy (energy is lost), while elastic collisions are clean (energy is conserved).

1.3 Visualizing Collisions

Inelastic Collision

Inelastic Collision: Objects stick together after the collision, kinetic energy is not conserved.

Elastic Collision

Elastic Collision: Objects bounce off each other, both kinetic energy and momentum are conserved.

1.4 Solving Collision Problems

  1. Identify the Type: Determine if the collision is elastic or inelastic. This helps you know whether to conserve kinetic energy.

  2. Conserve Momentum: Use the principle of conservation of momentum: pinitial=pfinalp_{initial} = p_{final} m1v1i+m2v2i=m1v1f+m2v2fm_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f} Where:

    • m1m_1 and m2m_2 are the masses of the objects.
    • v1iv_{1i} and v2iv_{2i} are the initial velocities.
    • v1fv_{1f} and v2fv_{2f} are the final velocities.
  3. Elastic Collisions (if applicable): If the collision is elastic, also conserve kinetic energy: KEinitial=KEfinalKE_{initial} = KE_{final} 12m1v1i2+12m2v2i2=12m1v1f2+12m2v2f2\frac{1}{2}m_1v_{1i}^2 + \frac{1}{2}m_2v_{2i}^2 = \frac{1}{2}m_1v_{1f}^2 + \frac{1}{2}m_2v_{2f}^2

  4. Solve: Use the equations to find the unknowns.

Exam Tip

Exam Tip: Remember to treat velocity as a vector. Pay attention to direction (positive or negative) when calculating momentum. Also, if a problem involves 2D collisions, analyze momentum conservation in both x and y directions separately.

Common Mistake

Common Mistake: Forgetting that kinetic energy is not conserved in inelastic collisions. Don't try to use the KE conservation equation if the objects stick together!

1.5 Example: Inelastic Collision

Two carts of the same mass lie on a table. The first cart is moving and the second cart is at rest. At the end of the collision, the two carts were stuck together. What is the final speed of the system?

Solution:

  • Initial momentum: pinitial=m1v1+m2v2p_{initial} = m_1v_1 + m_2v_2
  • Final momentum: pfinal=(m1+m2)vfinalp_{final} = (m_1 + m_2)v_{final}
  • Conservation of momentum: pinitial=pfinalp_{initial} = p_{final}
  • Solve for vfinalv_{final}

2. Center of Mass: The Balance Point βš–οΈ

2.1 What is Center of Mass?

The center of mass (COM) of a system is the point where the system's mass is evenly distributed. It's like the balancing point of an object. Imagine balancing a ruler on your finger; the point where it balances is its center of mass.

Quick Fact

Center of Mass: The point where an object can be balanced in a uniform gravitational field.

2.2 Calculating Center of Mass

For a system of particles, the center of mass can be found using the following formula:

xcm=m1x1+m2x2+...m1+m2+...x_{cm} = \frac{m_1x_1 + m_2x_2 + ...}{m_1 + m_2 + ...}

Where:

  • xcmx_{cm} is the x-coordinate of the center of mass.
  • m1m_1, m2m_2,... are the masses of the particles.
  • x1x_1, x2x_2,... are the x-coordinates of the particles.

You can use the same formula for the y-direction to find the y-coordinate of the center of mass.

2.3 Center of Mass and Net Force

  • Zero Net Force: If the net external force on a system is zero, the acceleration of the center of mass is zero. If the center of mass is moving, it will continue to move with the same velocity.

  • Non-Zero Net Force: If there's a net external force, the center of mass will accelerate as if it were a single particle with the total mass of the system.

Key Concept

Key Point: The center of mass of a system accelerates precisely as if it were a point particle of mass M acted upon by the net external force. This is a powerful concept for analyzing complex systems.

2.4 Example: Center of Mass

A stick of length 1 meter is balanced on a fulcrum at its midpoint. A mass of 2 kg is attached to one end of the stick, and a mass of 3 kg is attached to the other end. What is the distance from the fulcrum to the center of mass of the system?

Solution:

  • Use the center of mass formula: xcm=m1x1+m2x2m1+m2x_{cm} = \frac{m_1x_1 + m_2x_2}{m_1 + m_2}
  • Plug in the values and solve for xcmx_{cm}

3. Final Exam Focus 🎯

3.1 High-Value Topics

  • Conservation of Momentum: This is huge! Understand when and how to apply it.
  • Types of Collisions: Know the difference between elastic and inelastic collisions.
  • Center of Mass: Be able to calculate it and understand its motion under different forces.

3.2 Common Question Types

  • Multiple Choice: Conceptual questions about momentum, energy conservation, and types of collisions.
  • Free Response: Problems requiring you to calculate final velocities, kinetic energy changes, and center of mass positions.

3.3 Last-Minute Tips

  • Time Management: Don't get stuck on one problem. Move on and come back if you have time.
  • Units: Always include units in your answers.
  • Vector Nature: Remember that momentum and velocity are vectors. Consider direction!
  • Draw Diagrams: Visualizing the problem can help you understand it better.
  • Stay Calm: You've got this! Take deep breaths and approach each problem methodically.

4. Practice Questions

Practice Question

Multiple Choice Questions

  1. Two objects collide. Which of the following is always conserved during the collision? (A) Kinetic energy (B) Momentum (C) Velocity (D) Both kinetic energy and momentum

  2. A 2 kg ball moving at 3 m/s collides head-on with a 1 kg ball at rest. If the collision is perfectly inelastic, what is the final velocity of the combined mass? (A) 1 m/s (B) 2 m/s (C) 3 m/s (D) 4 m/s

  3. A system consists of two particles with masses 2kg and 3kg. The 2 kg particle is located at (1,2) and the 3kg particle is located at (4, -1). What is the x coordinate of the center of mass of the system? (A) 2.8 (B) 3.0 (C) 3.2 (D) 3.4

Free Response Question

A 0.5 kg cart A is moving on a horizontal, frictionless track with a velocity of 2 m/s to the right. It collides with a 1.0 kg cart B, which is initially at rest. After the collision, cart A moves to the left with a velocity of 0.5 m/s, and cart B moves to the right.

(a) Calculate the velocity of cart B after the collision.

(b) Determine whether the collision is elastic or inelastic. Justify your answer.

(c) Calculate the center of mass of the system before the collision, given that cart A is at position x=0 and cart B is at position x=2m.

(d) If the collision was completely inelastic, calculate the final velocity of the combined carts.

Scoring Rubric:

(a) Velocity of cart B (3 points)

  • 1 point: Correctly applying conservation of momentum: mAvAi+mBvBi=mAvAf+mBvBfm_Av_{Ai} + m_Bv_{Bi} = m_Av_{Af} + m_Bv_{Bf}
  • 1 point: Plugging in correct values: (0.5)(2)+(1.0)(0)=(0.5)(βˆ’0.5)+(1.0)vBf(0.5)(2) + (1.0)(0) = (0.5)(-0.5) + (1.0)v_{Bf}
  • 1 point: Correctly solving for vBfv_{Bf}: vBf=1.25m/sv_{Bf} = 1.25 m/s

(b) Type of Collision (3 points)

  • 1 point: Calculating initial kinetic energy: KEi=12mAvAi2+12mBvBi2=12(0.5)(2)2+0=1JKE_i = \frac{1}{2}m_Av_{Ai}^2 + \frac{1}{2}m_Bv_{Bi}^2 = \frac{1}{2}(0.5)(2)^2 + 0 = 1 J
  • 1 point: Calculating final kinetic energy: KEf=12mAvAf2+12mBvBf2=12(0.5)(βˆ’0.5)2+12(1)(1.25)2=0.8125JKE_f = \frac{1}{2}m_Av_{Af}^2 + \frac{1}{2}m_Bv_{Bf}^2 = \frac{1}{2}(0.5)(-0.5)^2 + \frac{1}{2}(1)(1.25)^2 = 0.8125 J
  • 1 point: Correctly stating the collision is inelastic because KEiβ‰ KEfKE_i β‰  KE_f

(c) Center of Mass Before Collision (2 points)

  • 1 point: Using the center of mass formula: xcm=mAxA+mBxBmA+mBx_{cm} = \frac{m_Ax_A + m_Bx_B}{m_A + m_B}
  • 1 point: Correctly calculating xcm=(0.5)(0)+(1.0)(2)0.5+1.0=1.33mx_{cm} = \frac{(0.5)(0) + (1.0)(2)}{0.5 + 1.0} = 1.33 m

(d) Final Velocity for Completely Inelastic Collision (2 points)

  • 1 point: Using conservation of momentum for completely inelastic collision: mAvAi+mBvBi=(mA+mB)vfm_Av_{Ai} + m_Bv_{Bi} = (m_A + m_B)v_f
  • 1 point: Correctly solving for vfv_f: vf=(0.5)(2)+(1.0)(0)0.5+1.0=0.67m/sv_f = \frac{(0.5)(2) + (1.0)(0)}{0.5 + 1.0} = 0.67 m/s

Alright, you've got this! Go ace that exam! πŸ’ͺ

Question 1 of 10

Two bumper cars πŸš— collide. Assuming no external forces, what quantity is always conserved during the collision?

Kinetic energy

Momentum

Velocity

Both kinetic energy and velocity