What is the effect of increasing the resistance in an RC circuit on the time constant?
It increases the time constant, slowing down the charging/discharging process.
What is the effect of increasing the capacitance in an RC circuit on the time constant?
It increases the time constant, slowing down the charging/discharging process.
What happens to the current in an RC circuit as a capacitor charges?
The current decreases over time, approaching zero when the capacitor is fully charged.
What happens when a charged capacitor is discharged through a resistor?
The stored energy in the capacitor is dissipated as heat in the resistor, and the capacitor's voltage decreases.
What happens when an uncharged capacitor is connected to a voltage source through a resistor?
Charge begins to flow, accumulating on the capacitor plates, and a current flows through the resistor.
What happens to the charging/discharging rate if the resistance in an RC circuit is increased?
The charging/discharging rate decreases; it takes longer for the capacitor to charge or discharge because the time constant \(\tau = RC\) increases.
What happens to the charging/discharging rate if the capacitance in an RC circuit is increased?
The charging/discharging rate decreases; it takes longer for the capacitor to charge or discharge because the time constant \(\tau = RC\) increases.
What happens to the current in an RC circuit after a very long time when the capacitor is fully charged?
The current becomes zero because the capacitor acts like an open circuit.
What is the effect of increasing the voltage of the battery on the maximum charge accumulated on the capacitor?
The maximum charge increases because \(Q = CV\).
What happens immediately after a charged capacitor begins to discharge?
The plate charge and stored energy immediately decrease.
What happens to the time constant if both resistance and capacitance are doubled?
The time constant quadruples because \(\tau = RC\).
What are the steps to find the equivalent capacitance of capacitors in series?
1. Identify all capacitors in series. 2. Calculate the inverse of each capacitance. 3. Sum the inverses. 4. Take the inverse of the sum to find \(C_{eq,s}\): \(\frac{1}{C_{\text{eq}, \text{s}}}=\sum_{i} \frac{1}{C_{i}}\) .
What are the steps to find the equivalent capacitance of capacitors in parallel?
1. Identify all capacitors in parallel. 2. Sum the individual capacitances to find \(C_{eq,p}\): \(C_{\text {eq.p }}=\sum_{i} C_{i}\).
Describe the process of charging a capacitor in an RC circuit.
1. Initially, the uncharged capacitor acts like a wire. 2. Charge flows, increasing the capacitor's potential difference and stored energy. 3. The rate of charging decreases over time. 4. After a long time, the capacitor is fully charged, and the current becomes zero.
Describe the process of discharging a capacitor in an RC circuit.
1. Initially, the capacitor is charged. 2. Charge flows out of the capacitor through the resistor, decreasing its potential difference and stored energy. 3. The rate of discharging decreases over time. 4. After a long time, the capacitor is fully discharged, with zero charge and energy.
How do you calculate the time constant (ฯ) in an RC circuit?
Multiply the equivalent resistance (\(R_{eq}\)) by the equivalent capacitance (\(C_{eq}\)): \(\tau = R_{eq}C_{eq}\).
