Modern Physics
What is the relationship between the maximum kinetic energy () of emitted electrons, the frequency () of the incident light, and the work function () of the material in the photoelectric effect?
In an experiment on the photoelectric effect, the stopping potential is measured to be 1.5 V when a metal with a work function of 2.5 eV is illuminated. What is the frequency of the incident light? (Assume )
Two materials, A and B, have work functions of 2.0 eV and 4.0 eV, respectively. If both materials are illuminated with light of the same frequency (high enough to cause electron emission), which material will emit electrons with higher maximum kinetic energy?
Material A
Material B
Both materials will emit electrons with the same maximum kinetic energy.
Neither material will emit electrons.
Which of the following materials is known to exhibit the photoelectric effect when exposed to light?
Wood
Sodium
Plastic
Glass
What is the threshold frequency in the context of the photoelectric effect?
The maximum frequency of light that can eject electrons from a material.
The minimum frequency of light required to eject electrons from a material.
The frequency of light at which the kinetic energy of emitted electrons is maximized.
The frequency of light that causes the highest intensity of electron emission.
What does the work function of a material represent?
The maximum energy an electron can have when emitted from the material.
The minimum energy required to remove an electron from the material's surface.
The energy of the incident photon.
The kinetic energy of the emitted electrons.
The photoelectric effect demonstrates the particle nature of light because:
The number of emitted electrons increases with the intensity of light.
Electrons are only emitted if the frequency of light is above a certain threshold.
The emitted electrons have a range of kinetic energies.
Light can be diffracted.

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A metal has a threshold frequency of 6 \times 10^{14} \text{ Hz}
. If light with a frequency of 4 \times 10^{14} \text{ Hz}
is shone on the metal, will electrons be emitted?
Yes, electrons will be emitted.
No, electrons will not be emitted.
Electrons will be emitted only if the intensity of light is high enough.
The number of emitted electrons depends on the voltage applied.
Why are no electrons emitted below the threshold frequency, regardless of the intensity of the incident light?
The energy of the photons is too low to overcome the work function of the material.
The intensity of the light is not high enough to cause electron emission.
The wavelength of the light is too short.
The electrons do not absorb the light.
Light with a frequency of 7 \times 10^{14} \text{ Hz}
is shone on a metal with a work function of 2.0 \text{ eV}
. Given that Planck's constant is approximately 4.14 \times 10^{-15} \text{ eV s}
, what is the maximum kinetic energy of the emitted electrons?
0.89 eV
2.89 eV
4.89 eV
6.89 eV