Increasing resistance increases the time constant, slowing down the charging/discharging process.

Increasing capacitance increases the time constant, slowing down the charging/discharging process and allowing it to store more charge.

The capacitor blocks DC current, acting like an open circuit.

Current flows freely through the circuit.

The total capacitance increases, allowing the circuit to store more charge at a given voltage.

Increases the time constant (τ), resulting in slower charging and discharging of the capacitor.

Increases the time constant (τ), resulting in slower charging and discharging of the capacitor.

It blocks DC current and acts like an open circuit.

It decreases the overall equivalent capacitance.

It increases the overall equivalent capacitance.

Use the reciprocal addition formula: $\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} + ...$

Add the capacitances directly: $C_{total} = C_1 + C_2 + C_3 + ...$

Initially, current flows freely. As the capacitor charges, the voltage across it increases until it equals the source voltage, at which point current stops flowing.

The capacitor releases its stored charge through the resistor, with the voltage and current decreasing exponentially over time.

The voltage across the capacitor increases over time until it reaches the voltage of the source, after which it remains constant.