Use the reciprocal addition formula: $\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} + ...$

Add the capacitances directly: $C_{total} = C_1 + C_2 + C_3 + ...$

Initially, current flows freely. As the capacitor charges, the voltage across it increases until it equals the source voltage, at which point current stops flowing.

The capacitor releases its stored charge through the resistor, with the voltage and current decreasing exponentially over time.

The voltage across the capacitor increases over time until it reaches the voltage of the source, after which it remains constant.

Increasing resistance increases the time constant, slowing down the charging/discharging process.

Increasing capacitance increases the time constant, slowing down the charging/discharging process and allowing it to store more charge.

The capacitor blocks DC current, acting like an open circuit.

Current flows freely through the circuit.

The total capacitance increases, allowing the circuit to store more charge at a given voltage.

Series: Charge is the same on each capacitor ($Q_{total} = Q_1 = Q_2 = Q_3 = ...$) | Parallel: Total charge is the sum of charges on each capacitor ($Q_{total} = Q_1 + Q_2 + Q_3 + ...$)

Series: $\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} + ...$ | Parallel: $C_{total} = C_1 + C_2 + C_3 + ...$

Initial State: Current flows freely, capacitor is uncharged | Steady State: No current flows, capacitor is fully charged and acts as an open circuit.

Series: Voltage is split across each capacitor. | Parallel: Voltage is the same across each capacitor.

Series: Current is the same through each capacitor. | Parallel: Current divides through each capacitor.