Electrostatics

2F

$\frac{F}{4}$

4F

$\frac{F}{2}$

$W_{ext} = qEd$, where $q$ is the particle's charge.

$W_{ext} = -q\Delta V$, with $\Delta V$ being the potential difference between two points.

$W_{ext} = 0$

$W_{ext} = Fd$

$-12xy \ \mathrm{m/s^2} \ \mathbf{i} +18z \ \mathrm{m/s^2} \ \mathbf{j} +8 \ \mathrm{m/s^2} \ \mathbf{k}$

$-6 \times 10^{14} \ \mathrm{m/s^2} \ \mathbf{i} +9 \times 10^{14} \ \mathrm{m/s^2} \ \mathbf{j} -16 \times 10^{14} \ \mathrm{m/s^2} \ \mathbf{k}$

$-6x \ \mathrm{m/s^2} \ \mathbf{i} +9y \ \mathrm{m/s^2} \ \mathbf{j} -18z \ \mathrm{m/s^2} \ \mathbf{k}$

$-9.11 \times 10^{14} \ \mathrm{m/s^2} \ \mathbf{i} + 6.07 \times 10^{14} \ \mathrm{m/s^2} \ \mathbf{j} -18 \times 10^{14} \ \mathrm{m/s^2} \ \mathbf{k}$

It exerts an electrical force on it.

It increases its mass.

It nullifies gravitational forces on it.

It changes its color spectrum emission.

To measure the potential difference between two points.

To increase voltage level at its terminals.

To control the power supplied to the load.

To provide a path for excess current.

No resultant field since symmetry leads all forces canceling each other out at corners.

Towards the center of the square due to attraction by hypothetical negative charge at center.

Along one side of square due to cancellation effects along diagonals.

Directly away from that corner due to repulsion from adjacent and diagonal charges.

The electric field strength is halved.

No change to the electric field strength.

The electric field strength is quadrupled.

The electric field strength is doubled.

1.6 x 10^-16 J

-3.2 x 10^-16 J

4.8 x 10^-16 J

3.2 x 10^-16 J

Positron

Electron

Neutron

Proton

Equal to the external electric field

Opposite to the external electric field

Proportional to the distance from the center

Zero