zuai-logo
zuai-logo
  1. AP Physics C E M
FlashcardFlashcardStudy GuideStudy Guide
Question BankQuestion Bank

Power in a Circuit 🔦

Hannah Baker

Hannah Baker

7 min read

Next Topic - Steady State Circuits
Study Guide Overview

This study guide covers electrical power in circuits, including the definition of power as the rate of energy transfer. It explains the core equations: P=IV, P=I²R, and P=V²/R, along with the relationship between power and energy (E=Pt). Practice problems (multiple-choice, short answer, and free response) are provided with solutions and explanations. Finally, exam tips emphasize mastering the equations, problem-solving skills, and FRQ strategies.

#AP Physics C: E&M - Power in Circuits: The Ultimate Study Guide ⚡

Hey future physicists! Let's dive into the world of power in circuits. This guide is designed to be your go-to resource, especially the night before the exam. We'll break down the concepts, highlight the key points, and get you feeling confident and ready to ace that test!

#Electrical Power: The Basics

#What is Power? 🤔

In simple terms, power is the rate at which energy is transferred or converted. In electrical circuits, power tells us how quickly electrical energy is being transformed into other forms of energy, like heat or light. Remember this fundamental concept:

Key Concept

Power (P) is the rate of energy transfer (or work done), measured in Watts (W).

markdown-image

#Power Equations: Your Toolkit 🧰

The fundamental equation for power is:

P=dWdtP = \frac{dW}{dt}P=dtdW​

Where:

  • P is power (in Watts)
  • dW is the change in energy (in Joules)
  • dt is the change in time (in seconds)

In electrical terms, we can express power using voltage (V) and current (I):

P=IVP = IVP=IV

Quick Fact

Remember: Power is the product of current and voltage!

Using Ohm's Law (V=IRV = IRV=IR), we can derive two more useful equations:

markdown-image

By substituting Ohm's Law (V=IRV=IRV=IR) into P=IVP=IVP=IV, we get:

P=I2RP = I^2RP=I2R

Or, by substituting I=V/RI=V/RI=V/R into P=IVP=IVP=IV, we get:

P=V2RP = \frac{V^2}{R}P=RV2​

Memory Aid

Power is Important, so remember *...

Feedback stars icon

How are we doing?

Give us your feedback and let us know how we can improve

Previous Topic - Electric CircuitsNext Topic - Steady State Circuits

Question 1 of 9

A circuit has a voltage of 10 V and a current of 2 A. What is the power dissipated in the circuit? 💡

5 W

10 W

20 W

100 W