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Power in a Circuit šŸ”¦

Hannah Baker

Hannah Baker

7 min read

Study Guide Overview

This study guide covers electrical power in circuits, including the definition of power as the rate of energy transfer. It explains the core equations: P=IV, P=I²R, and P=V²/R, along with the relationship between power and energy (E=Pt). Practice problems (multiple-choice, short answer, and free response) are provided with solutions and explanations. Finally, exam tips emphasize mastering the equations, problem-solving skills, and FRQ strategies.

#AP Physics C: E&M - Power in Circuits: The Ultimate Study Guide ⚔

Hey future physicists! Let's dive into the world of power in circuits. This guide is designed to be your go-to resource, especially the night before the exam. We'll break down the concepts, highlight the key points, and get you feeling confident and ready to ace that test!

#Electrical Power: The Basics

#What is Power? šŸ¤”

In simple terms, power is the rate at which energy is transferred or converted. In electrical circuits, power tells us how quickly electrical energy is being transformed into other forms of energy, like heat or light. Remember this fundamental concept:

Key Concept

Power (P) is the rate of energy transfer (or work done), measured in Watts (W).

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#Power Equations: Your Toolkit 🧰

The fundamental equation for power is:

P=dWdtP = \frac{dW}{dt}P=dtdW​

Where:

  • P is power (in Watts)
  • dW is the change in energy (in Joules)
  • dt is the change in time (in seconds)

In electrical terms, we can express power using voltage (V) and current (I):

P=IVP = IVP=IV

Quick Fact

Remember: Power is the product of current and voltage!

Using Ohm's Law (V=IRV = IRV=IR), we can derive two more useful equations:

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By substituting Ohm's Law (V=IRV=IRV=IR) into P=IVP=IVP=IV, we get:

P=I2RP = I^2RP=I2R

Or, by substituting I=V/RI=V/RI=V/R into P=IVP=IVP=IV, we get:

P=V2RP = \frac{V^2}{R}P=RV2​

Memory Aid

Power is Important, so remember P=IV. Then use Ohm's law to get the other forms. It's like a recipe: you start with the basic ingredients and then customize!

Choose the equation that best fits the information given in the problem. Each equation is useful in different scenarios. Here's a quick recap:

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  • P = IV: Use when you know current and voltage.
  • P = I²R: Use when you know current and resistance.
  • P = V²/R: Use when you know voltage and resistance.

#Connecting Concepts: Power and Energy

Remember that power is the rate at which energy is used. So, if you know the power and the time, you can find the total energy used:

E=PtE = PtE=Pt

Where:

  • E is energy (in Joules)

  • P is power (in Watts)

  • t is time (in seconds)

Key Concept

Energy is power multiplied by time. This relationship is crucial for calculating the total energy consumption in a circuit.

#Practice Problems

Let's put these concepts into action with some practice questions. Remember, practice makes perfect! šŸ’Ŗ

Practice Question

#Multiple Choice Questions

Question 1: A 60-W light bulb is connected to a 120-V power source. What is the current through the bulb?

(A) 0.25 A (B) 0.50 A (C) 1.0 A (D) 2.0 A

Question 2: A resistor with a resistance of 10 Ī© has a current of 2 A flowing through it. What is the power dissipated by the resistor?

(A) 10 W (B) 20 W (C) 40 W (D) 80 W

#Short Answer Question

Question 3: A heating element in a toaster has a resistance of 15 Ī©. If the toaster is plugged into a 120-V outlet, how much power does it use?

#Free Response Question

Question 4: A student assembles the circuit shown below:

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The switch is closed, and the student records the current in the circuit as shown in the graph below. The equation for the graph is:

I(t)=I0eāˆ’ktI(t) = I_0e^{-kt}I(t)=I0​eāˆ’kt

where t is the time elapsed from the instant the switch is closed, and I0I_0I0​ and k are constants.

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a) Using the information in the graph, determine the potential difference V0V_0V0​ across the resistor immediately after the switch is closed.

b) Determine the value of k from this best-fit curve. Show your work and be sure to include units in your answer.

c) Determine the following in terms of R, k, I0I_0I0​, and t:

i. The power delivered to the resistor at time t = 0 ii. The power delivered to the resistor as a function of time t iii. The total energy delivered to the resistor from t = 0 until the current is reduced to zero

#

Exam Tip

Solutions and Explanations

#Multiple Choice Answers

Question 1: (B) 0.50 A

Explanation: Use P=IVP = IVP=IV. Rearrange to solve for III: I=P/V=60W/120V=0.5AI = P/V = 60W / 120V = 0.5AI=P/V=60W/120V=0.5A

Question 2: (C) 40 W

Explanation: Use P=I2RP = I^2RP=I2R. P=(2A)2āˆ—10Ī©=40WP = (2A)^2 * 10\Omega = 40WP=(2A)2āˆ—10Ī©=40W

#Short Answer Answer

Question 3:

Explanation: Use P=V2/RP = V^2/RP=V2/R. P=(120V)2/15Ī©=960WP = (120V)^2 / 15\Omega = 960WP=(120V)2/15Ī©=960W

#Free Response Answers

a) According to the graph, the current at t=0 is approximately 9.3A. Using V = IR that gives us a Voltage of 31V across the 3.3Ī© Resistor

b) Using Io=9.3AI_o=9.3AIo​=9.3A, I=7.5AI=7.5AI=7.5A, t=0.5hrt=0.5hrt=0.5hr

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c)

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#

Exam Tip

Final Exam Focus

Alright, you've made it to the final stretch! Here's what to focus on:

  • Master the Power Equations: Know when to use P=IVP=IVP=IV, P=I2RP=I^2RP=I2R, and P=V2/RP=V^2/RP=V2/R. Practice switching between them.
  • Relate Power and Energy: Understand that energy is just power multiplied by time (E=PtE=PtE=Pt).
  • Problem-Solving Skills: Practice applying these concepts in various circuit scenarios. Focus on both simple and complex problems.
  • FRQ Strategies: For free-response questions, always show your work, include units, and clearly explain your reasoning. Partial credit is your friend!

#Last-Minute Tips

  • Time Management: Don't get stuck on one problem. If a question is taking too long, move on and come back to it later.

  • Units: Always include units in your calculations and answers. It's an easy way to avoid losing points.

  • Common Mistakes: Be careful with algebra and substitutions. Double-check your work.

  • Stay Calm: Take deep breaths, and remember all the hard work you've put in. You've got this! šŸ’Ŗ

Common Mistake

Forgetting units or using the wrong power equation are common mistakes. Double-check your formulas and units!

You've got the knowledge and the tools. Now go out there and show that exam what you're made of! Good luck, and may the power be with you! šŸ˜‰

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Question 1 of 9

A circuit has a voltage of 10 V and a current of 2 A. What is the power dissipated in the circuit? šŸ’”

5 W

10 W

20 W

100 W