The object experiences angular acceleration.

It increases the magnitude of the torque.

The object is in rotational equilibrium, meaning it has no angular acceleration.

It increases the moment of inertia, as described by the parallel axis theorem.

1: Identify the force vector ($\vec{F}$) and the position vector ($\vec{r}$). 2: Determine the angle ($\theta$) between $\vec{r}$ and $\vec{F}$. 3: Calculate the magnitude of the torque using $\tau = rF\sin(\theta)$. 4: Use the right-hand rule to find the direction of the torque.

1: Identify the object and the new axis of rotation. 2: Find the moment of inertia about the center of mass ($I_{cm}$). 3: Determine the distance ($h$) between the two axes. 4: Plug the values into the formula $I = I_{cm} + Mh^2$ and solve for $I$.

1: Draw a free-body diagram, including all forces and their points of application. 2: Choose a convenient pivot point. 3: Apply the first condition of equilibrium: $\sum \vec{F} = 0$. 4: Apply the second condition of equilibrium: $\sum \vec{\tau} = 0$. 5: Solve the resulting equations for the unknowns.

Translational Equilibrium: Net force is zero, no linear acceleration. | Rotational Equilibrium: Net torque is zero, no angular acceleration.

Force: Linear push or pull, causes linear acceleration. | Torque: Rotational force, causes angular acceleration.

Mass: Resistance to linear acceleration, scalar quantity. | Moment of Inertia: Resistance to angular acceleration, depends on mass distribution, scalar quantity.