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  1. AP Pre Calculus
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How do you find the average rate of change of f(x)=x2+2xf(x) = x^2 + 2xf(x)=x2+2x over the interval [0, 2]?

  1. Calculate f(2) = 8. 2. Calculate f(0) = 0. 3. Apply the formula: (f(2) - f(0)) / (2 - 0) = (8 - 0) / 2 = 4.
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How do you find the average rate of change of f(x)=x2+2xf(x) = x^2 + 2xf(x)=x2+2x over the interval [0, 2]?

  1. Calculate f(2) = 8. 2. Calculate f(0) = 0. 3. Apply the formula: (f(2) - f(0)) / (2 - 0) = (8 - 0) / 2 = 4.

Given a table of values, how do you estimate the average rate of change between two points?

  1. Identify the y-values corresponding to the given x-values. 2. Subtract the y-values. 3. Subtract the x-values. 4. Divide the change in y by the change in x.

How to determine if a function is concave up or down given its equation?

  1. Find the second derivative of the function. 2. If the second derivative is positive, it's concave up. 3. If the second derivative is negative, it's concave down.

How do you find the interval where a quadratic function is increasing?

  1. Find the vertex of the parabola. 2. If the coefficient of x2x^2x2 is positive, the function is increasing to the right of the vertex. 3. If the coefficient of x2x^2x2 is negative, the function is increasing to the left of the vertex.

How do you determine if a function is linear from a table of values?

  1. Calculate the rate of change between consecutive points. 2. If the rate of change is constant, the function is linear.

How do you find the average rate of change of f(x)=3x−2f(x) = 3x - 2f(x)=3x−2 over the interval [-1, 4]?

  1. Calculate f(4)=3(4)−2=10f(4) = 3(4) - 2 = 10f(4)=3(4)−2=10. 2. Calculate f(−1)=3(−1)−2=−5f(-1) = 3(-1) - 2 = -5f(−1)=3(−1)−2=−5. 3. Apply the formula: f(4)−f(−1)4−(−1)=10−(−5)5=3\frac{f(4) - f(-1)}{4 - (-1)} = \frac{10 - (-5)}{5} = 34−(−1)f(4)−f(−1)​=510−(−5)​=3.

How do you determine the x-value at which the instantaneous rate of change of f(x)=x2−4x+5f(x) = x^2 - 4x + 5f(x)=x2−4x+5 is equal to zero?

  1. Find the derivative: f′(x)=2x−4f'(x) = 2x - 4f′(x)=2x−4. 2. Set the derivative equal to zero: 2x−4=02x - 4 = 02x−4=0. 3. Solve for x: x=2x = 2x=2.

How do you find the average rate of change of f(x)=−x2+5x−3f(x) = -x^2 + 5x - 3f(x)=−x2+5x−3 over the interval [0, 2]?

  1. Calculate f(2)=−(2)2+5(2)−3=3f(2) = -(2)^2 + 5(2) - 3 = 3f(2)=−(2)2+5(2)−3=3. 2. Calculate f(0)=−(0)2+5(0)−3=−3f(0) = -(0)^2 + 5(0) - 3 = -3f(0)=−(0)2+5(0)−3=−3. 3. Apply the formula: f(2)−f(0)2−0=3−(−3)2=3\frac{f(2) - f(0)}{2 - 0} = \frac{3 - (-3)}{2} = 32−0f(2)−f(0)​=23−(−3)​=3.

How do you determine the concavity of f(x)=2x2−3x+1f(x) = 2x^2 - 3x + 1f(x)=2x2−3x+1?

  1. Find the second derivative: f′(x)=4x−3f'(x) = 4x - 3f′(x)=4x−3, f′′(x)=4f''(x) = 4f′′(x)=4. 2. Since f′′(x)=4>0f''(x) = 4 > 0f′′(x)=4>0, the function is concave up for all x.

How do you find the interval where f(x)=−x2+6x−8f(x) = -x^2 + 6x - 8f(x)=−x2+6x−8 is decreasing?

  1. Find the vertex: x=−b2a=−62(−1)=3x = \frac{-b}{2a} = \frac{-6}{2(-1)} = 3x=2a−b​=2(−1)−6​=3. 2. Since the coefficient of x2x^2x2 is negative, the function is decreasing for x>3x > 3x>3.

What are the differences between the average rate of change and instantaneous rate of change?

Average rate of change: over an interval | Instantaneous rate of change: at a single point.

What are the differences between linear and quadratic functions in terms of their rates of change?

Linear: constant rate of change | Quadratic: changing rate of change.

What are the differences between concave up and concave down?

Concave Up: Increasing rate of change | Concave Down: Decreasing rate of change

Compare the average rate of change of f(x)=2xf(x) = 2xf(x)=2x and g(x)=x2g(x) = x^2g(x)=x2 over the interval [1, 3].

f(x): Constant rate of change = 2 | g(x): Changing rate of change, average rate of change = 4

What is the difference between a secant line and a tangent line?

Secant line: intersects the curve at two points | Tangent line: touches the curve at one point.

Compare the concavity of f(x)=x2f(x) = x^2f(x)=x2 and g(x)=−x2g(x) = -x^2g(x)=−x2.

f(x): Concave up | g(x): Concave down

Compare the average rate of change of a linear function with a positive slope and a linear function with a negative slope.

Positive slope: Average rate of change is positive | Negative slope: Average rate of change is negative

Compare the average rate of change of f(x)=xf(x) = xf(x)=x and g(x)=x2g(x) = x^2g(x)=x2 as x approaches infinity.

f(x): Rate of change remains constant | g(x): Rate of change increases without bound

Compare the concavity of f(x)=x3f(x) = x^3f(x)=x3 and g(x)=x2g(x) = x^2g(x)=x2 around x = 0.

f(x): Changes concavity at x=0 (inflection point) | g(x): Always concave up

Compare the average rate of change of f(x)=xf(x) = xf(x)=x and g(x)=x+5g(x) = x+5g(x)=x+5.

f(x): Average rate of change is 1 | g(x): Average rate of change is 1

What is the formula for average rate of change?

f(b)−f(a)b−a\frac{f(b) - f(a)}{b - a}b−af(b)−f(a)​

How do you calculate the slope of a secant line between points (a, f(a)) and (b, f(b))?

f(b)−f(a)b−a\frac{f(b) - f(a)}{b - a}b−af(b)−f(a)​

Given a quadratic function in the form f(x)=ax2+bx+cf(x) = ax^2 + bx + cf(x)=ax2+bx+c, how do you find the x-coordinate of the vertex?

x=−b2ax = \frac{-b}{2a}x=2a−b​

What is the formula for the average rate of change of f(x)f(x)f(x) over the interval [x1,x2][x_1, x_2][x1​,x2​]?

ΔyΔx=f(x2)−f(x1)x2−x1\frac{\Delta y}{\Delta x} = \frac{f(x_2) - f(x_1)}{x_2 - x_1}ΔxΔy​=x2​−x1​f(x2​)−f(x1​)​

If f(x)=ax+bf(x) = ax + bf(x)=ax+b, what is the average rate of change over any interval?

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If f(x)=ax2+bx+cf(x) = ax^2 + bx + cf(x)=ax2+bx+c, what is the average rate of change over the interval [x1,x2][x_1, x_2][x1​,x2​]?

a(x1+x2)+ba(x_1 + x_2) + ba(x1​+x2​)+b

What formula represents the slope of the secant line of a function f(x)f(x)f(x)?

msec=f(x+h)−f(x)hm_{sec} = \frac{f(x+h)-f(x)}{h}msec​=hf(x+h)−f(x)​

How is the average rate of change related to the difference quotient?

Average rate of change is equivalent to the difference quotient: f(x2)−f(x1)x2−x1\frac{f(x_2)-f(x_1)}{x_2-x_1}x2​−x1​f(x2​)−f(x1​)​

How do you find the instantaneous rate of change?

lim⁡h→0f(x+h)−f(x)h\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}limh→0​hf(x+h)−f(x)​

What is the general form for a linear equation?

y=mx+by = mx + by=mx+b