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What does the graph of y=bxy = b^x (where b>1b > 1) look like?

An increasing curve that passes through (0, 1), approaching the x-axis as x goes to negative infinity.

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What does the graph of y=bxy = b^x (where b>1b > 1) look like?

An increasing curve that passes through (0, 1), approaching the x-axis as x goes to negative infinity.

What does the graph of y=logb(x)y = \log_b(x) (where b>1b > 1) look like?

An increasing curve that passes through (1, 0), approaching the y-axis as x goes to 0.

How can you identify the base bb from the graph of y=bxy = b^x?

Find the point where x=1x = 1. The yy-coordinate of that point is the value of bb.

How can you identify the base bb from the graph of y=logb(x)y = \log_b(x)?

Find the point where y=1y = 1. The xx-coordinate of that point is the value of bb.

What does the intersection of y=bxy = b^x and y=logb(x)y = \log_b(x) with y=xy=x represent?

It shows the points where the function and its inverse have the same x and y values.

What are the differences between exponential and logarithmic functions regarding asymptotes?

Exponential: Horizontal asymptote. | Logarithmic: Vertical asymptote.

Compare the domains and ranges of f(x)=bxf(x) = b^x and g(x)=logb(x)g(x) = \log_b(x).

Exponential: Domain is (,)(-\infty, \infty), Range is (0,)(0, \infty). | Logarithmic: Domain is (0,)(0, \infty), Range is (,)(-\infty, \infty).

Compare the growth rates of exponential and logarithmic functions.

Exponential: Grows rapidly as xx increases. | Logarithmic: Grows slowly as xx increases.

Compare the behavior of bxb^x and logb(x)\log_b(x) as xx approaches infinity.

Exponential: Approaches infinity. | Logarithmic: Approaches infinity, but much slower.

What is the general form of an exponential function?

f(x)=abxf(x) = ab^x

What is the general form of a logarithmic function?

f(x)=alogb(x)f(x) = a \log_b(x)

If (s,t)(s, t) is on g(x)=bxg(x) = b^x, what point is on its inverse?

(t,s)(t, s) is on f(x)=logb(x)f(x) = \log_b(x)

Express t=bst = b^s in logarithmic form.

s=logb(t)s = \log_b(t)

Express s=logb(t)s = \log_b(t) in exponential form.

t=bst = b^s