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What is a one-to-one function?
A function where each output (y-value) corresponds to only one input (x-value).
What is an invertible function?
A function that has an inverse function. It must be one-to-one and have an unrestricted domain.
What is the inverse function notation for f(x)?
The inverse of a function ( f(x) ) is written as ( f^{-1}(x) ).
Define the domain of a function.
The set of all possible input values (x-values) for which the function is defined.
Define the range of a function.
The set of all possible output values (y-values) that the function can produce.
What is the horizontal line test?
A test to determine if a function is one-to-one. If any horizontal line intersects the graph more than once, the function is not one-to-one.
What does it mean for a domain to be unrestricted?
The function's domain isn't limited in a way that prevents it from having an inverse; it covers all possible input values.
What happens to input-output pairs in an inverse function?
If ( f(a) = b ), then ( f^{-1}(b) = a ). The input and output pairs are flipped.
What is a multivalued inverse?
If a function isn't one-to-one, its inverse might not be a function (it could have multiple outputs for one input).
What is the graphical relationship between a function and its inverse?
The graph of ( f^{-1}(x) ) is a reflection of ( f(x) ) across the line ( y = x ).
How do you denote the inverse of a function f(x)?
\( f^{-1}(x) )
If f(a) = b, what is f⁻¹(b)?
\( f^{-1}(b) = a )
Given ( y = f(x) ), how do you start finding the inverse?
Swap ( x ) and ( y ) to get ( x = f(y) ).
What is the relationship between the domain of f(x) and the range of f⁻¹(x)?
Domain of ( f(x) ) = Range of ( f^{-1}(x) )
What is the relationship between the range of f(x) and the domain of f⁻¹(x)?
Range of ( f(x) ) = Domain of ( f^{-1}(x) )
How to determine if ( f(x) = x^2 ) is invertible?
1. Graph ( f(x) = x^2 ). 2. Apply the horizontal line test. 3. Since a horizontal line can intersect the graph more than once, ( f(x) = x^2 ) is not invertible unless the domain is restricted.
Steps to find the inverse of ( f(x) = 3x + 2 )?
1. Replace ( f(x) ) with ( y ): ( y = 3x + 2 ). 2. Swap ( x ) and ( y ): ( x = 3y + 2 ). 3. Solve for ( y ): ( y = (x - 2) / 3 ). 4. Replace ( y ) with ( f^{-1}(x) ): ( f^{-1}(x) = (x - 2) / 3 ).
How to find the domain and range of ( f(x) = sqrt{x - 1} ) and its inverse?
1. For ( f(x) ): Domain is ( x geq 1 ), Range is ( y geq 0 ). 2. Find the inverse: ( f^{-1}(x) = x^2 + 1 ). 3. For ( f^{-1}(x) ): Domain is ( x geq 0 ), Range is ( y geq 1 ).
How to verify that ( f^{-1}(x) = (x - 1) / 2 ) is the inverse of ( f(x) = 2x + 1 )?
1. Compute ( f(f^{-1}(x)) ): ( f((x - 1) / 2) = 2((x - 1) / 2) + 1 = x - 1 + 1 = x ). 2. Compute ( f^{-1}(f(x)) ): ( f^{-1}(2x + 1) = ((2x + 1) - 1) / 2 = 2x / 2 = x ). 3. Since both compositions equal ( x ), the functions are inverses.
How to find the inverse of ( f(x) = x^3 )?
1. Replace ( f(x) ) with ( y ): ( y = x^3 ). 2. Swap ( x ) and ( y ): ( x = y^3 ). 3. Solve for ( y ): ( y = sqrt[3]{x} ). 4. Replace ( y ) with ( f^{-1}(x) ): ( f^{-1}(x) = sqrt[3]{x} ).
Given ( f(x) = frac{1}{x} ), find its inverse.
1. Replace ( f(x) ) with ( y ): ( y = frac{1}{x} ). 2. Swap ( x ) and ( y ): ( x = frac{1}{y} ). 3. Solve for ( y ): ( y = frac{1}{x} ). 4. Replace ( y ) with ( f^{-1}(x) ): ( f^{-1}(x) = frac{1}{x} ).
Find the inverse of ( f(x) = e^x ).
1. Replace ( f(x) ) with ( y ): ( y = e^x ). 2. Swap ( x ) and ( y ): ( x = e^y ). 3. Solve for ( y ): ( y = ln(x) ). 4. Replace ( y ) with ( f^{-1}(x) ): ( f^{-1}(x) = ln(x) ).
How to determine the domain of the inverse of ( f(x) = sqrt{x+3} )?
1. Find the range of ( f(x) ): Range is ( y geq 0 ). 2. The domain of ( f^{-1}(x) ) is the range of ( f(x) ), so the domain of ( f^{-1}(x) ) is ( x geq 0 ).
How do you restrict the domain of ( f(x) = x^2 ) to make it invertible?
1. Choose either ( x geq 0 ) or ( x leq 0 ). 2. If ( x geq 0 ), the function is one-to-one and invertible. 3. If ( x leq 0 ), the function is one-to-one and invertible.
If ( f(x) = 5x - 2 ), find ( f^{-1}(7) ).
1. Find ( f^{-1}(x) ): ( f^{-1}(x) = frac{x + 2}{5} ). 2. Substitute ( x = 7 ) into ( f^{-1}(x) ): ( f^{-1}(7) = frac{7 + 2}{5} = frac{9}{5} ).