sin(x): Input is angle, output is ratio | arcsin(x): Input is ratio, output is angle.

cos(x): Input is angle, output is ratio | arccos(x): Input is ratio, output is angle.

tan(x): Input is angle, output is ratio | arctan(x): Input is ratio, output is angle.

Equations: Find specific angle values | Inequalities: Find intervals where the condition holds.

Sine: All real numbers | Arcsine: [-1, 1]

Cosine: [-1, 1] | Arccosine: [0, $\pi$]

Both have a period of 2$\pi$.

arcsin(x): [-$\frac{\pi}{2}$, $\frac{\pi}{2}$] | arctan(x): (-$\frac{\pi}{2}$, $\frac{\pi}{2}$)

arccos(x): [-1, 1] | arctan(x): All real numbers

arccos(x) range is [0, $\pi$], arcsin(x) range is [-$\frac{\pi}{2}$, $\frac{\pi}{2}$].

The inverse sine function, giving the angle whose sine is x.

The inverse cosine function, giving the angle whose cosine is x.

The inverse tangent function, giving the angle whose tangent is x.

[-1, 1]

[-$\frac{\pi}{2}$, $\frac{\pi}{2}$]

[-1, 1]

[0, $\pi$]

All real numbers

(-$\frac{\pi}{2}$, $\frac{\pi}{2}$)

It repeats its values at regular intervals.

x = arcsin(a) + 2$\pi$k or x = $\pi$ - arcsin(a) + 2$\pi$k, where k is an integer.

x = arccos(a) + 2$\pi$k or x = -arccos(a) + 2$\pi$k, where k is an integer.

x = arctan(a) + $\pi$k, where k is an integer.

Find arcsin(a). If arcsin(a) is in the interval, it's one solution. The other is $\pi$ - arcsin(a).

Find arccos(a). If arccos(a) is in the interval, it's one solution. The other is 2$\pi$ - arccos(a).

Find arctan(a). If arctan(a) is in the interval, it's the solution.

[-$\frac{\pi}{2}$, $\frac{\pi}{2}$]

[0, $\pi$]

(-$\frac{\pi}{2}$, $\frac{\pi}{2}$)

x = arcsin(0.5) = $\frac{\pi}{6}$ or 30°