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What is the Sum Rule for limits?

limxoc[f(x)+g(x)]=limxocf(x)+limxocg(x)lim_{x o c} [f(x) + g(x)] = lim_{x o c} f(x) + lim_{x o c} g(x)

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What is the Sum Rule for limits?

limxoc[f(x)+g(x)]=limxocf(x)+limxocg(x)lim_{x o c} [f(x) + g(x)] = lim_{x o c} f(x) + lim_{x o c} g(x)

What is the Difference Rule for limits?

limxoc[f(x)g(x)]=limxocf(x)limxocg(x)lim_{x o c} [f(x) - g(x)] = lim_{x o c} f(x) - lim_{x o c} g(x)

What is the Constant Multiple Rule for limits?

limxoc[kcdotf(x)]=kcdotlimxocf(x)lim_{x o c} [k cdot f(x)] = k cdot lim_{x o c} f(x)

What is the Product Rule for limits?

limxoc[f(x)cdotg(x)]=limxocf(x)cdotlimxocg(x)lim_{x o c} [f(x) cdot g(x)] = lim_{x o c} f(x) cdot lim_{x o c} g(x)

What is the Quotient Rule for limits?

limxocf(x)g(x)=limxocf(x)limxocg(x)lim_{x o c} \frac{f(x)}{g(x)} = \frac{lim_{x o c} f(x)}{lim_{x o c} g(x)}, if limxocg(x)eq0lim_{x o c} g(x) eq 0

What is the Power Rule for limits?

limxoc[f(x)]n=[limxocf(x)]nlim_{x o c} [f(x)]^n = [lim_{x o c} f(x)]^n

What is the Root Rule for limits?

limxocf(x)n=limxocf(x)nlim_{x o c} \sqrt[n]{f(x)} = \sqrt[n]{lim_{x o c} f(x)}

Formula to find limxcklim_{x \to c} k where k is a constant?

limxck=klim_{x \to c} k = k

Formula to find limxcxlim_{x \to c} x?

limxcx=clim_{x \to c} x = c

Formula to find limxcxnlim_{x \to c} x^n?

limxcxn=cnlim_{x \to c} x^n = c^n

What is a limit?

The value that a function approaches as the input approaches some value.

What is direct substitution in the context of limits?

Evaluating a limit by plugging in the value that x is approaching into the function.

What is an indeterminate form?

An expression whose value cannot be determined, such as 0/0.

Define the Sum Rule for limits.

The limit of a sum is the sum of the limits: limxoc[f(x)+g(x)]=limxocf(x)+limxocg(x)lim_{x o c} [f(x) + g(x)] = lim_{x o c} f(x) + lim_{x o c} g(x)

Define the Difference Rule for limits.

The limit of a difference is the difference of the limits: limxoc[f(x)g(x)]=limxocf(x)limxocg(x)lim_{x o c} [f(x) - g(x)] = lim_{x o c} f(x) - lim_{x o c} g(x)

Define the Constant Multiple Rule for limits.

The limit of a constant times a function is the constant times the limit of the function: limxoc[kcdotf(x)]=kcdotlimxocf(x)lim_{x o c} [k cdot f(x)] = k cdot lim_{x o c} f(x)

Define the Product Rule for limits.

The limit of a product is the product of the limits: limxoc[f(x)cdotg(x)]=limxocf(x)cdotlimxocg(x)lim_{x o c} [f(x) cdot g(x)] = lim_{x o c} f(x) cdot lim_{x o c} g(x)

Define the Quotient Rule for limits.

The limit of a quotient is the quotient of the limits, provided the limit of the denominator is not zero: limxocf(x)g(x)=limxocf(x)limxocg(x)lim_{x o c} \frac{f(x)}{g(x)} = \frac{lim_{x o c} f(x)}{lim_{x o c} g(x)}, if limxocg(x)eq0lim_{x o c} g(x) eq 0

Define the Power Rule for limits.

The limit of a function raised to a power is the limit of the function raised to that power: limxoc[f(x)]n=[limxocf(x)]nlim_{x o c} [f(x)]^n = [lim_{x o c} f(x)]^n

Define the Root Rule for limits.

The limit of a root of a function is the root of the limit of the function: limxocf(x)n=limxocf(x)nlim_{x o c} \sqrt[n]{f(x)} = \sqrt[n]{lim_{x o c} f(x)}

How to solve limxo2(x2+3x5)lim_{x o 2} (x^2 + 3x - 5)?

  1. Direct substitution: (2)2+3(2)5=4+65=5(2)^2 + 3(2) - 5 = 4 + 6 - 5 = 5. Therefore, the limit is 5.

How to solve limxo3x29x3lim_{x o 3} \frac{x^2 - 9}{x - 3}?

  1. Direct substitution yields 0/0. 2. Factor the numerator: x29=(x3)(x+3)x^2 - 9 = (x - 3)(x + 3). 3. Simplify: (x3)(x+3)x3=x+3\frac{(x - 3)(x + 3)}{x - 3} = x + 3. 4. Evaluate the limit: limxo3(x+3)=3+3=6lim_{x o 3} (x + 3) = 3 + 3 = 6.

How to solve limxo0x+42xlim_{x o 0} \frac{\sqrt{x + 4} - 2}{x}?

  1. Direct substitution yields 0/0. 2. Rationalize the numerator by multiplying by the conjugate: x+42xcdotx+4+2x+4+2\frac{\sqrt{x + 4} - 2}{x} cdot \frac{\sqrt{x + 4} + 2}{\sqrt{x + 4} + 2}. 3. Simplify: x+44x(x+4+2)=xx(x+4+2)=1x+4+2\frac{x + 4 - 4}{x(\sqrt{x + 4} + 2)} = \frac{x}{x(\sqrt{x + 4} + 2)} = \frac{1}{\sqrt{x + 4} + 2}. 4. Evaluate the limit: limxo01x+4+2=14+2=14lim_{x o 0} \frac{1}{\sqrt{x + 4} + 2} = \frac{1}{\sqrt{4} + 2} = \frac{1}{4}.

How to solve limxo5(2x23)lim_{x o 5} (2x^2 - 3)?

  1. Direct substitution: 2(5)23=2(25)3=503=472(5)^2 - 3 = 2(25) - 3 = 50 - 3 = 47. Therefore, the limit is 47.

How to solve limxo2x3+8x+2lim_{x o -2} \frac{x^3 + 8}{x + 2}?

  1. Direct substitution yields 0/0. 2. Factor the numerator: x3+8=(x+2)(x22x+4)x^3 + 8 = (x + 2)(x^2 - 2x + 4). 3. Simplify: (x+2)(x22x+4)x+2=x22x+4\frac{(x + 2)(x^2 - 2x + 4)}{x + 2} = x^2 - 2x + 4. 4. Evaluate the limit: limxo2(x22x+4)=(2)22(2)+4=4+4+4=12lim_{x o -2} (x^2 - 2x + 4) = (-2)^2 - 2(-2) + 4 = 4 + 4 + 4 = 12.

How to solve limxo4x2x4lim_{x o 4} \frac{\sqrt{x} - 2}{x - 4}?

  1. Direct substitution yields 0/0. 2. Rationalize the numerator: x2x4cdotx+2x+2\frac{\sqrt{x} - 2}{x - 4} cdot \frac{\sqrt{x} + 2}{\sqrt{x} + 2}. 3. Simplify: x4(x4)(x+2)=1x+2\frac{x - 4}{(x - 4)(\sqrt{x} + 2)} = \frac{1}{\sqrt{x} + 2}. 4. Evaluate the limit: limxo41x+2=14+2=14lim_{x o 4} \frac{1}{\sqrt{x} + 2} = \frac{1}{\sqrt{4} + 2} = \frac{1}{4}.

How to solve limxo1x2+4x5x1lim_{x o 1} \frac{x^2 + 4x - 5}{x - 1}?

  1. Direct substitution yields 0/0. 2. Factor the numerator: x2+4x5=(x1)(x+5)x^2 + 4x - 5 = (x - 1)(x + 5). 3. Simplify: (x1)(x+5)x1=x+5\frac{(x - 1)(x + 5)}{x - 1} = x + 5. 4. Evaluate the limit: limxo1(x+5)=1+5=6lim_{x o 1} (x + 5) = 1 + 5 = 6.

How to solve limxo0(x+5)225xlim_{x o 0} \frac{(x+5)^2 - 25}{x}?

  1. Direct substitution yields 0/0. 2. Expand: x2+10x+2525x=x2+10xx\frac{x^2+10x+25 - 25}{x} = \frac{x^2+10x}{x}. 3. Simplify: x(x+10)x=x+10\frac{x(x+10)}{x} = x+10. 4. Evaluate the limit: limx0(x+10)=0+10=10lim_{x \to 0} (x+10) = 0+10 = 10.

How to solve limxo2(5x3x3)lim_{x o 2} (5x - 3x^3)?

  1. Direct substitution: 5(2)3(2)3=103(8)=1024=145(2) - 3(2)^3 = 10 - 3(8) = 10 - 24 = -14. Therefore, the limit is -14.

How to solve limxo1x21x+1lim_{x o -1} \frac{x^2 - 1}{x + 1}?

  1. Direct substitution yields 0/0. 2. Factor the numerator: x21=(x1)(x+1)x^2 - 1 = (x - 1)(x + 1). 3. Simplify: (x1)(x+1)x+1=x1\frac{(x - 1)(x + 1)}{x + 1} = x - 1. 4. Evaluate the limit: limxo1(x1)=11=2lim_{x o -1} (x - 1) = -1 - 1 = -2.