Limits and Continuity
A student is trying to solve this problem . Here is what this student did Step 1: Step 2: Step 3: Is this student correct?
No, the student made an error in step 1.
No, the student made an error in step 2.
Yes, the student is right so far, but the student needs to do more in order to get it to the right answer.
Yes, the student is correct.
True or False: the limit of a constant a constant.
Depends on the type of constant.
false
true
There is not enough information.
What type of discontinuity does exhibit as approaches ?
A jump discontinuity due to differing one-sided limits.
No discontinuity; the limits match 's values.
An infinite discontinuity because becomes unbounded near .
A point discontinuity since is undefined only at .
A pair of students are trying to solve this problem: . The following are the steps the students follow: Step 1: Step 2 = Step 3 = Are the students correct?
No, the students are wrong because a limit cannot be 0. If it ends up as zero, the students needs to do L'hospital rule.
No, the students are incorrect because to do the limit of sec cannot be done unless it is turned into a sin first.
No, the student is wrong because the student cannot separate the terms like this, , in step 1.
Yes, the students are correct because 0 times 0 is 0.
Find the limit of the function as approaches 1.
5
1
-1
Undefined
Find the .
7
9
5
39
Consider the function . Find the limit as approaches 4.
5
4
6
10

How are we doing?
Give us your feedback and let us know how we can improve
What is ?
8
-9
Undefined
0
Given that and , which expression accurately expresses L in terms of m?
L equals to negative infinity times m.
The expression for L cannot be determined from the given information about m.
When faced with computing where is a positive integer, why would expansion using binomial theorem be less favorable than applying another technique?
Implementing L'Hôpital's Rule after initial algebraic simplification of the expression.
Recognizing it as a difference quotient prompting usage of derivative rules.
Taking advantage of cancellation opportunities provided by polynomial long division.
Preferring factoring through synthetic division prior to taking the limit.