Limits and Continuity
When checking if a rational function is continuous over its domain, what must hold true for all values except where equals zero?
p(x) and q(x) are both continuous functions across their domains independent of each other except where .
should exist and be finite across their shared domain exclusive of points where .
p(x) must intersect q(x) at least once in their domains excluding where .
p(x) must have a higher degree polynomial than q(x).
For which type of discontinuity is it appropriate to apply L'Hôpital's Rule when determining if a function is continuous across an interval?
A jump discontinuity where there is a sudden change in function values within the interval.
An infinite discontinuity where the function approaches infinity within that interval.
An indeterminate form such as or at a point in the interval.
A removable discontinuity where there is a hole in the graph of the function on that interval.
Is continuous over the open interval ?
No, it is not continuous over the interval .
Yes, it is continuous over the interval .
The continuity of cannot be determined based on the given information.
It is continuous for all values of .
For function defined by , what can we deduce about its continuity and differentiability at ?
Neither continuous nor differentiable
Both continuous and differentiable
Differentiable but not continuous
Continuous but not differentiable
Which of the following must be true for a function to be continuous at ?
The limit as approaches of exists, but is not equal to .
The limit as approaches of equals .
The function has a vertical asymptote at .
The limit as approaches of equals the limit as approaches of , but both do not equal to .
Which expression describes the conditions under which a piecewise-defined function with two pieces, each defined and continuous on adjoining intervals [a,b) and [b,c], respectively, is guaranteed to be continuous on [a,c]?
Both pieces have vertical asymptotes at x=b.
A function is defined via parametric representation , over interval , what condition ensures smoothness function without vertical tangents?
The derivatives & never both reach zero simultaneously within the given range.
When takes value one.
When reaches maximum value.
When derivative doesn't exist anywhere within the interval.

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For which of the following values of k would the function be continuous at ?
k=-2
k=1
k=0
k=3
Which condition might indicate that function is not continuous at ?
There's a vertical asymptote at
exists for all points except at
When analyzing whether or not is continuous over , what more complex approach might one use aside from standard limit processes?
Attempting polynomial long division on prior to evaluating limits.
Using trig identities alone to transform before taking limits.
Applying logarithmic differentiation followed by l’Hôpital’s rule.
Conducting synthetic division involving terms of , then assessing limits.