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  1. AP Calculus
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Integration and Accumulation of Change

Question 1
college-boardCalculus AB/BCAPExam Style
1 mark

In a partial fraction decomposition, what can be done if a factor in the denominator is raised to a power greater than one?

Question 2
college-boardCalculus AB/BCAPExam Style
1 mark

What does a repeated linear factor in the denominator indicate when using linear partial fractions?

Question 3
college-boardCalculus AB/BCAPExam Style
1 mark

Which of the following is true about the degrees of the numerator and denominator in a partial fraction decomposition?

Question 4
college-boardCalculus AB/BCAPExam Style
1 mark

Which step must be taken first when evaluating ∫20(x−7)(x3+8) dx\int \dfrac{20 }{( x-7 )( x^{3}+8 )}\ dx∫(x−7)(x3+8)20​ dx using partial fractions?

Question 5
college-boardCalculus AB/BCAPExam Style
1 mark

What value of B completes a correct partial fraction decomposition if ∫18−x2(9−x)(9+x)dx=∫(−99−x+B9+x)dx\int \frac{18-x^2}{(9-x) (9+x)} dx = \int (\frac{-9}{9-x}+\frac{B}{9+x}) dx∫(9−x)(9+x)18−x2​dx=∫(9−x−9​+9+xB​)dx?

Question 6
college-boardCalculus AB/BCAPExam Style
1 mark

Which expression represents the partial fraction decomposition of the rational function 5x2+4(x+2)(x2+1)\frac{5x^2 + 4}{(x+2)(x^2+1)}(x+2)(x2+1)5x2+4​?

Question 7
college-boardCalculus AB/BCAPExam Style
1 mark

When using linear partial fractions, what is the first step in the process?

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Question 8
college-boardCalculus AB/BCAPExam Style
1 mark

In a partial fraction decomposition, what is the purpose of assigning variables to the unknown coefficients?

Question 9
college-boardCalculus AB/BCAPExam Style
1 mark

In decomposing ∫x2+4(x−5)(x4−16),dx\int \frac{x^2+4}{(x-5)(x^4-16)} , dx∫(x−5)(x4−16)x2+4​,dx using partial fractions, what dictates whether there are repeated linear or irreducible quadratic factors?

Question 10
college-boardCalculus AB/BCAPExam Style
1 mark

For what reason does adding non-repeating linear factors to your denominators help when determining coefficients in decomposing f(x)=x5−7x3+11(5−x)(9+x3)f(x)=\frac{x^{5}-7x^{3}+11}{(5-x)(9+x^{3})}f(x)=(5−x)(9+x3)x5−7x3+11​?