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The Product Rule

Hannah Hill

Hannah Hill

6 min read

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Study Guide Overview

This study guide covers the product rule for finding derivatives. It includes the formula, a step-by-step walkthrough, practice problems, and common mistakes. It emphasizes the importance of this rule for the AP Calculus exam, providing practice multiple choice and free-response questions with answers and a scoring rubric.

The Product Rule 🚀

Welcome back! Let's master the product rule, a crucial tool for finding derivatives of functions multiplied together. This is a key skill that you'll see throughout the AP Calculus exam.


🏁 Product Rule Definition

The product rule helps us find the derivative of two functions multiplied together. It's not as simple as just multiplying the derivatives!


Formula: ddx(f(x)g(x))=f(x)g(x)+g(x)f(x)\frac{d}{dx}(\textcolor{red}{f(x)}\textcolor{green}{g(x)})= \textcolor{red}{f(x)} \textcolor{blue}{g'(x)} + \textcolor{green}{g(x)} \textcolor{pink}{f'(x)}


Memory Aid

Mnemonic: "First d second plus second d first"

  • First function times the derivative of the second
  • Plus the second function times the derivative of the first

Key Concept

The derivative of a product is NOT the product of the derivatives.


✏️ Product Rule: Walkthrough

Let's break it down with an example:

f(x)=sin(x)(x2+2x)f(x) = \sin(x)(x^2 + 2x)

Applying the product rule:

f(x)=sin(x)ddx(x2+2x)+(x2+2x)ddx(sin(x))f'(x) = \sin(x) \frac{d}{dx}(x^2 + 2x) + (x^2+2x) \frac{d}{dx}(\sin(x))

f(x)=sin(x)(2x+2)+(x2+2x)cos(x)f'(x) = \sin(x)(2x+2) + (x^2+2x)\cos(x)


Common Mistake

A common mistake is to incorrectly calculate the derivative as cos(x)(2x+2)cos(x)(2x+2). This is incorrect! Always use the product rule.


Here's a visual to show the difference between the correct and incorrect derivative:


Graph of f(x)

Graph of f(x)f(x)

Graph of f'(x)

Graph of f(x)f'(x) (Correct)

Incorrect Graph of f'(x)

Incorrect Graph of f(x)f'(x)


🧮 Product Rule: Practice Problems

Let's solidify your understanding with some practice!


Product Rule: Example 1

Find yy' for y=(3x24x)(2x1)y = (3x^2-4x)(2x-1) with and without the Product Rule.


Solving Example 1 Without Product Rule

First, expand the function:

y=6x33x28x2+4x=6x311x2+4xy = 6x^3 - 3x^2 - 8x^2 + 4x = 6x^3 -11x^2 + 4x

Now, take the derivative:

y=18x222x+4y' = 18x^2 - 22x + 4


Solving Example 1 With Product Rule

Apply the product rule:

y=(3x24x)ddx(2x1)+(2x1)ddx(3x24x)y' = (3x^2-4x) \frac{d}{dx}(2x-1) + (2x-1) \frac{d}{dx}(3x^2-4x)

y=(3x24x)(2)+(2x1)(6x4)y' = (3x^2-4x)(2) + (2x-1)(6x-4)


Exam Tip

You do not need to simplify your answer on the AP exam unless specifically asked!


Product Rule: Example 2

Find f(x)f'(x) if f(x)=sin(x)(3x22x+5)f(x) = \sin(x)(3x^2 - 2x + 5).


Using the product rule:

f(x)=sin(x)ddx(3x22x+5)+(3x22x+5)ddxsin(x)f'(x) = \sin(x) \frac{d}{dx}(3x^2-2x+5) + (3x^2-2x+5) \frac{d}{dx}\sin(x)

f(x)=sin(x)(6x2)+(3x22x+5)cos(x)f'(x) = \sin(x)(6x-2) + (3x^2-2x+5)\cos(x)


Product Rule: Example 3

Find yy' if y=exsin(x)y = e^x\sin(x)


Remember that the derivative of exe^x is exe^x!

y=exddx(sin(x))+sin(x)ddx(ex)y'=e^x \frac{d}{dx}(\sin(x)) + \sin(x)\frac{d}{dx}(e^x)

y=excos(x)+exsin(x)y' = e^x\cos(x) + e^x\sin(x)


🌟 Closing

Great job! You've now got a solid grasp of the product rule. This is a fundamental concept, so make sure you're comfortable with it. You'll definitely see it on the AP exam.


The product rule is a high-value topic. Expect to see it in multiple-choice and free-response questions.


Encouraging GIF with animated ice cream


Final Exam Focus

  • Master the Basics: The product rule is a foundational concept. Make sure you can apply it quickly and accurately.
  • Look for Opportunities: Be on the lookout for functions that are products.
  • Don't Simplify Unless Necessary: Save time by not simplifying unless the question explicitly asks you to.
  • Combine with Other Rules: The product rule often appears with other derivative rules (chain rule, etc.).

Practice Questions

Practice Question

Multiple Choice Questions

  1. If f(x)=x2sin(x)f(x) = x^2 \sin(x), what is f(x)f'(x)? (A) 2xcos(x)2x \cos(x) (B) 2xsin(x)+x2cos(x)2x \sin(x) + x^2 \cos(x) (C) 2xsin(x)x2cos(x)2x \sin(x) - x^2 \cos(x) (D) x2cos(x)x^2 \cos(x)

  1. Find the derivative of y=(x3+1)exy = (x^3 + 1)e^x (A) 3x2ex3x^2e^x (B) (x3+1)ex+3x2(x^3 + 1)e^x + 3x^2 (C) (x3+3x2+1)ex(x^3 + 3x^2 + 1)e^x (D) 3x2ex+(x3+1)ex3x^2e^x + (x^3 + 1)e^x

Free Response Question

Let f(x)=x2cos(x)f(x) = x^2 \cos(x).

(a) Find f(x)f'(x).

(b) Find the equation of the tangent line to the graph of ff at x=πx = \pi.

(c) Find all values of x for which f(x)=0f'(x) = 0 on the interval [0,2π][0, 2\pi].

Scoring Rubric:

(a) 2 points * 1 point for correct application of the product rule * 1 point for the correct derivative

(b) 3 points * 1 point for finding the correct slope at x=πx=\pi * 1 point for correct yy-value at x=πx=\pi * 1 point for the equation of the tangent line

(c) 4 points * 1 point for setting f(x)=0f'(x) = 0 * 1 point for factoring or simplifying * 2 points for correct x-values

Answers

Multiple Choice:

  1. (B)
  2. (C)

Free Response:

(a) f(x)=2xcos(x)x2sin(x)f'(x) = 2x \cos(x) - x^2 \sin(x)

(b) f(π)=π2cos(π)=π2f(\pi) = \pi^2 \cos(\pi) = -\pi^2. f(π)=2πcos(π)π2sin(π)=2πf'(\pi) = 2\pi \cos(\pi) - \pi^2 \sin(\pi) = -2\pi. The tangent line is y(π2)=2π(xπ)y - (-\pi^2) = -2\pi(x - \pi) or y=2πx+π2y = -2\pi x + \pi^2.

(c) f(x)=x(2cos(x)xsin(x))=0f'(x) = x(2\cos(x) - x\sin(x)) = 0. x=0x = 0 or 2cos(x)xsin(x)=02\cos(x) - x\sin(x) = 0. Using a calculator, the approximate values are x=0,0.860,2.289,4.273x=0, 0.860, 2.289, 4.273.

Question 1 of 8

If f(x)=xsin(x)f(x) = x \sin(x), what is f(x)f'(x)?

cos(x)\cos(x)

xcos(x)x \cos(x)

sin(x)+xcos(x)\sin(x) + x \cos(x)

xcos(x)+sin(x)x \cos(x) + \sin(x)