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Rates of Change in Applied Contexts other than Motion

Benjamin Wright

Benjamin Wright

7 min read

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Study Guide Overview

This study guide covers rates of change in applied contexts (non-motion) for AP Calculus AB/BC. It focuses on interpreting the meaning of a function and its derivative in real-world scenarios, including calculating and interpreting instantaneous rates of change with proper units. Practice problems and exam tips are provided, emphasizing the importance of units and showing work. Key exam topics include interpreting derivatives, understanding units, and applying derivatives to solve problems.

AP Calculus AB/BC: Rates of Change in Applied Contexts πŸš€

Hey there, future AP Calculus master! Let's dive into rates of change beyond just motion. You've already rocked rectilinear motion; now, let's apply those skills to other real-world scenarios. This is where calculus gets super cool and practical! 😎

This topic is crucial because it connects derivatives to real-world applications, which is a common theme in both multiple-choice and free-response questions. Expect to see these concepts in various forms on the exam.

πŸ“‰ Rates of Change in Applied Contexts (Non-Motion)

The key to understanding rates of change in non-motion problems is to focus on what the given function represents.

  • Function Meaning: If f(x)f(x) gives the volume (in liters) of water in a tank tt minutes after the drain opens, then: * f(t)f(t) = Volume of water at time t * fβ€²(t)f'(t) = Rate of change of volume (liters per minute) at time t

Key Concept

Remember, the derivative fβ€²(x)f'(x) always represents the instantaneous rate of change of the function f(x)f(x). The units of fβ€²(x)f'(x) are always the units of f(x)f(x) divided by the units of xx.

πŸšΆβ€β™€οΈ Walkthrough: Pogo Stick Jumping

Let's break down an example: Karen's height on a pogo stick is given by:

H(t)=3sin⁑(t10)+12H(t) = 3\sin\left(\frac{t}{10}\right) + \frac{1}{2}

  • Goal: Find the instantaneous rate of change of her height at t=10t = 10 seconds. This means we need to find Hβ€²(10)H'(10).

  • Step 1: Find the derivative, Hβ€²(t)H'(t):

Hβ€²(t)=310cos⁑(t10)H'(t) = \frac{3}{10}\cos\left(\frac{t}{10}\right)

  • Step 2: Evaluate at t=10t = 10:

Hβ€²(10)=310cos⁑(1)β‰ˆ0.162H'(10) = \frac{3}{10}\cos(1) \approx 0.162

  • Answer: The instantaneous rate of change of Karen's height is approximately 0.162 feet per second. The units are feet per second because the original function was in feet and time was in seconds.

Exam Tip

Always include units in your answers! This is a common place where students lose points on the AP exam. Make sure to show all your work, including the derivative and the evaluation.

πŸ“ Practice Problems

Time to try it yourself! Remember to think about what the function represents and what the derivative tells you.

❓ Problems

Question 1:

Thomas's Instagram likes are modeled by:

L(t)=200e0.1tL(t) = 200e^{0.1t}

Find the instantaneous rate of change of likes 5 days after posting.

Question 2:

Jen's gas tank volume is modeled by:

G(t)=300+4tG(t) = 300 + 4t

Find the instantaneous rate of change of the gas volume 4 minutes after she starts filling up.

βœ… Answers and Solutions

Question 1:

  • Derivative: Lβ€²(t)=200β‹…0.1e0.1t=20e0.1tL'(t) = 200 \cdot 0.1e^{0.1t} = 20e^{0.1t}
  • Evaluate at t=5t = 5: Lβ€²(5)=20e0.5β‰ˆ32.97L'(5) = 20e^{0.5} \approx 32.97
  • Answer: The rate of change is approximately 32.97 likes per day.

Question 2:

  • Derivative: Gβ€²(t)=4G'(t) = 4

  • Evaluate at t=4t = 4: Gβ€²(4)=4G'(4) = 4

  • Answer: The rate of change is 4 liters per minute. Notice that the rate of change is constant in this case.

Memory Aid

Units Matter! Always include units in your answers. The units of the derivative are the units of the function divided by the units of the variable. For example, if f(t)f(t) is in meters and tt is in seconds, then fβ€²(t)f'(t) is in meters per second.

Practice Question

Multiple Choice Questions

  1. Question: The function P(t)P(t) models the population of a city at time tt years. What does Pβ€²(5)P'(5) represent?

    • The population of the city in 5 years.
    • The average population of the city over the first 5 years.
    • The rate of change of the population at t=5t=5 years.
    • The total population increase over the first 5 years. Answer: The rate of change of the population at t=5t=5 years.
  2. Question: A spherical balloon is being inflated. The function V(r)V(r) gives the volume of the balloon in cubic centimeters as a function of its radius rr in centimeters. What are the units of Vβ€²(r)V'(r)?

    • cm
    • cm^2
    • cm^3
    • cm^3/cm Answer: cm^3/cm
  3. Question: The temperature of a room, in degrees Celsius, is given by the function T(h)T(h), where hh is the number of hours since noon. What does Tβ€²(3)T'(3) represent?

    • The temperature of the room at 3 PM.
    • The average temperature of the room between noon and 3 PM.
    • The rate at which the temperature is changing at 3 PM.
    • The total change in temperature between noon and 3 PM. Answer: The rate at which the temperature is changing at 3 PM.

Free Response Question

Question: The amount of water in a tank, in gallons, is modeled by the function W(t)=100+20tβˆ’t2W(t) = 100 + 20t - t^2, where tt is measured in minutes for 0≀t≀100 \le t \le 10. (a) Find Wβ€²(t)W'(t). What does Wβ€²(t)W'(t) represent in the context of this problem? (b) Find Wβ€²(5)W'(5). What does this value represent in the context of this problem? (c) At what time tt is the water level in the tank increasing most rapidly? Justify your answer. (d) At what time tt is the water level in the tank decreasing most rapidly? Justify your answer.

Scoring Guidelines

  • (a) (2 points) 1 point for the correct derivative, 1 point for the correct interpretation
  • (b) (2 points) 1 point for the correct value, 1 point for the correct interpretation
  • (c) (2 points) 1 point for finding the critical point, 1 point for justification
  • (d) (3 points) 1 point for finding the critical point, 1 point for justification, 1 point for correct answer

Solution

  • (a) Wβ€²(t)=20βˆ’2tW'(t) = 20 - 2t. Wβ€²(t)W'(t) represents the rate of change of the amount of water in the tank in gallons per minute at time tt.
  • (b) Wβ€²(5)=20βˆ’2(5)=10W'(5) = 20 - 2(5) = 10. This means that at t=5t=5 minutes, the amount of water in the tank is increasing at a rate of 10 gallons per minute.
  • (c) To find when the water level is increasing most rapidly, we need to find when Wβ€²(t)W'(t) is maximized. Since Wβ€²(t)W'(t) is a linear function with a negative slope, it is maximized at the smallest value of tt, which is t=0t=0. Thus the water level is increasing most rapidly at t=0t=0.
  • (d) To find when the water level is decreasing most rapidly, we need to find when Wβ€²(t)W'(t) is minimized. Since Wβ€²(t)W'(t) is a linear function with a negative slope, it is minimized at the largest value of tt, which is t=10t=10. However, Wβ€²(10)=20βˆ’2(10)=0W'(10) = 20-2(10)=0. The water level is decreasing when Wβ€²(t)<0W'(t)<0, which is when 20βˆ’2t<020-2t<0 or t>10t>10. However, since the domain is 0≀t≀100 \le t \le 10, we need to check the endpoints. At t=10t=10, the rate of change is zero. Therefore, the water level is decreasing most rapidly at t=10t=10.

Final Exam Focus 🎯

  • High-Priority Topics: * Interpreting derivatives in context (especially non-motion). * Understanding units of derivatives. * Applying derivatives to solve real-world problems.

  • Common Question Types: * Multiple-choice questions asking for the interpretation of a derivative. * Free-response questions involving finding and interpreting derivatives in applied contexts.

  • Last-Minute Tips: * Time Management: Don't spend too much time on one question. If you're stuck, move on and come back later. * Common Pitfalls: Forgetting units, not showing work, and misinterpreting the question are common mistakes. Double-check your work! * Strategies: Read the question carefully, identify what the function represents, and then think about what the derivative means in that context.

You've got this! You're well-prepared, and now it's time to show off your calculus skills. Go get that 5! 🌟

Question 1 of 10

The function V(t)V(t) represents the volume of a balloon, in cubic centimeters, as a function of time tt in seconds. What does V(t)V(t) represent?

The rate of change of the volume of the balloon

The volume of the balloon at time tt

The surface area of the balloon at time t

The change in volume of the balloon over time