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  1. AP Chemistry
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Atomic Structure and Properties

Question 1
mock_examChemistryAPZuAI Powered
1 mark

Which equation shows the enthalpy of formation, ∆Hf, of ethanol?

Question 2
2018ChemistryAPConcept Practice
10 marks

Answer the following questions relating to Fe and its ions, Fe2+Fe^{2+}Fe2+ and Fe3+Fe^{3+}Fe3+.

3.a. Write the ground-state electron configuration of the Fe2+Fe^{2+}Fe2+ ion.

1 mark

3.b. The radii of the ions are given in the table above. Using principles of atomic structure, explain why the radius of the Fe2+Fe^{2+}Fe2+ ion is larger than the radius of the Fe3+Fe^{3+}Fe3+ ion.

IonIonic Radius (pm)
Fe2+Fe^{2+}Fe2+92
Fe3+Fe^{3+}Fe3+79
1 mark

3.c. Fe3+Fe^{3+}Fe3+ ions interact more strongly with water molecules in aqueous solution than Fe2+Fe^{2+}Fe2+ ions do. Give one reason for this stronger interaction, and justify your answer using Coulomb’s law.

1 mark

3.d. A student obtains a solution that contains an unknown concentration of Fe2+(aq)Fe^{2+}(aq)Fe2+(aq). To determine the concentration of Fe2+(aq)Fe^{2+}(aq)Fe2+(aq) in the solution, the student titrates a sample of the solution with MnO4−(aq)MnO_4^-(aq)MnO4−​(aq), which converts Fe2+(aq)Fe^{2+}(aq)Fe2+(aq) to Fe3+(aq)Fe^{3+}(aq)Fe3+(aq), as represented by the following equation.

5Fe2+(aq)+MnO4−(aq)+8H+(aq)→5Fe3+(aq)+Mn2+(aq)+4H2O(l)5 Fe^{2+}(aq) + MnO_4^-(aq) + 8 H^+(aq) \rightarrow 5 Fe^{3+}(aq) + Mn^{2+}(aq) + 4 H_2O(l)5Fe2+(aq)+MnO4−​(aq)+8H+(aq)→5Fe3+(aq)+Mn2+(aq)+4H2​O(l)

Write the balanced equation for the half-reaction for the oxidation of Fe2+(aq)Fe^{2+}(aq)Fe2+(aq) to Fe3+(aq)Fe^{3+}(aq)Fe3+(aq).

1 mark

3.e. The student titrates a 10.0 mL sample of the Fe2+(aq)Fe^{2+}(aq)Fe2+(aq) solution. Calculate the value of [Fe2+][Fe^{2+}][Fe2+] in the solution if it takes 17.48 mL of added 0.0350 M KMnO4(aq)KMnO_4(aq)KMnO4​(aq) to reach the equivalence point of the titration.

1 mark

3.f. To deliver the 10.0 mL sample of the Fe2+(aq)Fe^{2+}(aq)Fe2+(aq) solution in part (e), the student has the choice of using one of the pieces of glassware listed below.

  • 25 mL buret
  • 25 mL beaker
  • 25 mL graduated cylinder
  • 25 mL volumetric flask

Explain why the 25 mL volumetric flask would be a poor choice to use for delivering the required volume of the Fe2+(aq)Fe^{2+}(aq)Fe2+(aq) solution.

1 mark

3.g. In a separate experiment, the student is given a sample of powdered Fe(s) that contains an inert impurity. The student uses a procedure to oxidize the Fe(s) in the sample to Fe2O3(s)Fe_2O_3(s)Fe2​O3​(s). The student collects the following data during the experiment.

Mass of Fe(s) with inert impurity6.724 g
Mass of Fe2O3(s)Fe_2O_3(s)Fe2​O3​(s) produced7.531 g

3.g.i. Calculate the number of moles of Fe in the Fe2O3(s)Fe_2O_3(s)Fe2​O3​(s) produced.

3.g.ii. Calculate the percent by mass of Fe in the original sample of powdered Fe(s) with the inert impurity.

3.g.iii. If the oxidation of the Fe(s) in the original sample was incomplete so that some of the 7.531 g of product was FeO(s) instead of Fe2O3(s)Fe_2O_3(s)Fe2​O3​(s), would the calculated mass percent of Fe(s) in the original sample be higher, lower, or the same as the actual mass percent of Fe(s)? Justify your answer.

3 marks
Question 3
2018ChemistryAPConcept Practice
4 marks

The complete photoelectron spectrum of an element is represented above.

markdown-image

7.a. Identify the element.

1 mark

7.b. A radioactive isotope of the element decays with a half-life of 10. minutes.

7.b.i. Calculate the value of the rate constant, kkk, for the radioactive decay. Include units with your answer.

7.b.ii. If 64 atoms of the radioactive isotope are originally present in a sample, what is the expected amount of time that will pass until only one atom of the isotope remains? Show how you arrived at your answer.

2 marks
Question 4
2019ChemistryAPConcept Practice
4 marks

The complete photoelectron spectrum of an element in its ground state is represented below.

![](https://zustagstorage.blob.core.windows.net/community/files_questions/frq/ap24-frq-chemistry_beba940851a745b295fc2d706caf2e6a)

5.a. (2 points) Based on the spectrum,

    5.a.i. (1 point) write the ground-state...

5.a.i. 1s22s22p63s23p41s^22s^22p^63s^23p^41s22s22p63s23p4

5.a.ii. Sulfur

5.b. E = 1.0 x 10−1810^{-18}10−18 J

E = hcλ\frac{hc}{\lambda}λhc​

λ=hcE\lambda = \frac{hc}{E}λ=Ehc​

λ=6.626×10−34×3.0×1081.0×10−18\lambda = \frac{6.626 \times 10^{-34} \times 3.0 \times 10^8}{1.0 \times 10^{-18}}λ=1.0×10−186.626×10−34×3.0×108​ = 1.99 x 10−710^{-7}10−7 m

4 marks
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