zuai-logo
zuai-logo
  1. AP Chemistry
FlashcardFlashcardStudy GuideStudy GuideQuestion BankQuestion Bank

Acids and Bases

Question 1
2021ChemistryAPConcept Practice
11 marks

Methanoic acid, HCOOH, ionizes according to the equation above.

HCOOH(aq)+H2O(l)⇌H3O+(aq)+HCOO−(aq)HCOOH (aq) + H_2O(l) \rightleftharpoons H_3O^+(aq) + HCOO^-(aq)HCOOH(aq)+H2​O(l)⇌H3​O+(aq)+HCOO−(aq) Ka=1.8×10−4K_a = 1.8 \times 10^{-4}Ka​=1.8×10−4

1.a) Write the expression for the equilibrium constant, KaK_aKa​, for the reaction. (1 point)

Ka=[H3O+][HCOO−][HCOOH]K_a = \frac{[H_3O^+][HCOO^-]}{[HCOOH]}Ka​=[HCOOH][H3​O+][HCOO−]​

1 mark

1.b) Calculate the pH of a 0.25 MMM solution of HCOOH. (3 points)

Ka=x20.25=1.8×10−4K_a = \frac{x^2}{0.25} = 1.8 \times 10^{-4}Ka​=0.25x2​=1.8×10−4 x2=4.5×10−5x^2 = 4.5 \times 10^{-5}x2=4.5×10−5 x=[H3O+]=6.7×10−3x = [H_3O^+] = 6.7 \times 10^{-3}x=[H3​O+]=6.7×10−3 pH=−log(6.7×10−3)=2.17pH = -log(6.7 \times 10^{-3}) = 2.17pH=−log(6.7×10−3)=2.17

3 marks

1.c) In the box below, complete the Lewis electron-dot diagram for HCOOH. Show all bonding and nonbonding valence electrons. (2 points)

markdown-image

2 marks

1.d) In aqueous solution, the compound H2NNH2H_2NNH_2H2​NNH2​ reacts according to the equation above. A 50.0 mL sample of 0.25 MMM H2NNH2(aq)H_2NNH_2 (aq)H2​NNH2​(aq) is combined with a 50.0 mL sample of 0.25 MMM HCOOH(aq)(aq)(aq).

1.d.i) Write the balanced net ionic equation for the reaction that occurs when <math-inline>H\_2NNH\_2</math-inline> is combined with HCOOH. (1 point)

<math-inline>H\_2NNH\_2(aq) + HCOOH(aq) \rightarrow H\_2NNH\_3^+(aq) + HCOO^-(aq)</math-inline>

1.d.ii) Is the resulting solution acidic, basic, or neutral? Justify your answer. (2 points)

The resulting solution is basic. <math-inline>K\_a</math-inline> of HCOOH is $1.8 \times 10^{-4}$ and <math-inline>K\_b</math-inline> of <math-inline>H\_2NNH\_2</math-inline> is $1.3 \times 10^{-6}$. Since the <math-inline>K\_a</math-inline> of the acid is greater than the <math-inline>K\_b</math-inline> of the base, the solution is expected to be acidic. However, the reaction is between a weak acid and a weak base, so the solution will be slightly basic because the <math-inline>K\_b</math-inline> of <math-inline>H\_2NNH\_2</math-inline> is larger than the <math-inline>K\_a</math-inline> of HCOOH.
3 marks

1.e) When a catalyst is added to a solution of HCOOH(aq)(aq)(aq), the reaction represented by the following equation occurs. Is the reaction a redox reaction? Justify your answer. (1 point)

<math-inline>HCOOH (aq) \rightarrow H\_2(g) + CO\_2(g)</math-inline>

Yes, the reaction is a redox reaction. The oxidation state of carbon in HCOOH is +2, and it changes to +4 in <math-inline>CO\_2</math-inline>. The oxidation state of hydrogen in HCOOH is +1 and it changes to 0 in <math-inline>H\_2</math-inline>. Since there is a change in oxidation states, this is a redox reaction.
1 mark

1.f) The reaction occurs in a rigid 4.3 L vessel at 25°C, and the total pressure is monitored, as shown in the graph above. The vessel originally did not contain any gas. Calculate the number of moles of CO2(g)CO_2(g)CO2​(g) produced in the reaction. (Assume that the amount of CO2(g)CO_2(g)CO2​(g) dissolved in the solution is negligible.) (2 points)

![](https://zustagstorage.blob.core.windows.net/community/files_questions/frq/ap24-frq-chemistry_948ed8b8a7fc4d1b82923fd4738dccd1)

<math-inline>P\_{total} = 0.60 atm</math-inline>
<math-inline>P\_{total} = P\_{H\_2} + P\_{CO\_2}</math-inline> and <math-inline>P\_{H\_2} = P\_{CO\_2}</math-inline>
<math-inline>P\_{CO\_2} = 0.30 atm</math-inline>
<math-inline>PV = nRT</math-inline>
<math-inline>n = \frac{PV}{RT} = \frac{(0.30 atm)(4.3 L)}{(0.08206 L atm/mol K)(298 K)} = 0.053 mol</math-inline>
2 marks

1.g) After the reaction has proceeded for several minutes, does the amount of catalyst increase, decrease, or remain the same? Justify your answer. (1 point)

The amount of catalyst remains the same. A catalyst is not consumed in a chemical reaction.
1 mark
Question 2
2024ChemistryAPConcept Practice
10 marks

A student is studying the reaction between lactic acid, C3H6O3C_3H_6O_3C3​H6​O3​, and sodium hydroxide, NaOHNaOHNaOH, as represented in the balanced equation above.

1.a) The structural formula of lactic acid is shown in the following diagram. Circle the hydrogen atom that most readily participates in the chemical reaction with sodium hydroxide.

markdown-image

1 mark

1.b) The student begins the experiment by dissolving 10.22 g of sodium hydroxide (molar mass 40.00 g / mol) in enough water to produce 500. mL of solution. Calculate the molarity of the sodium hydroxide solution.

2 marks

1.c) The student uses the sodium hydroxide solution from part (b), a buret, a pH meter, and a 100 mL Erlenmeyer flask to titrate a 25.0 mL sample of lactic acid solution. The student’s data are shown in the following graph. Use the information in the graph to determine the approximate pKaK_aKa​ of lactic acid.

markdown-image

1 mark

1.d) The preceding diagram represents the relative amounts of major species in a sample of the solution in the flask at one point during the titration. (Note that water molecules are omitted.)

markdown-image

1.d.i) Draw an X on the preceding titration curve at a point in the titration where the reaction mixture would be represented by this diagram.

1.d.ii) Justify your answer.

2 marks

1.e) The student repeats the experiment but uses a solution of NaOH(aq)NaOH(aq)NaOH(aq) with twice the concentration, as shown in the preceding table. On the following graph, draw the titration curve that would be expected for experiment 2. |Experiment |Mass of NaOH(s) (grams) | Volume of Solution (mL) | Titration Curve | | - | - | - | - | |1 |10.22 | 500. | Already shown on graph| |2 |20.44 | 500. | ?|

markdown-image

1 mark

1.f) In a third experiment, the student investigates the enthalpy of the reaction between lactic acid and sodium hydroxide. The student combines 100.0 mL of a 0.500 MMM lactic acid solution at 20.0°C with 100.0 mL of a 0.500 MMM NaOHNaOHNaOH solution at 20.0°C in a calorimeter. The final temperature of the resulting combined solution is 23.2°C. Assume that the density of each solution before combining is 1.00 g / mL and that the specific heat capacity of the combined solution is 4.2 J / (g · ° C).

1.f.i) Calculate the quantity of heat produced in the reaction, in J.

1.f.ii) Calculate the molar enthalpy of reaction, in kJ / molrxn_{rxn}rxn​. Include the sign in your answer.

1.f.iii) The student claims that if heat is lost from the calorimeter to the surrounding air during the reaction, then the experimental value of the molar enthalpy of reaction will be smaller in magnitude than the actual value. Do you agree or disagree with the student’s claim? Justify your answer.

3 marks
Question 3
2023ChemistryAPConcept Practice
4 marks

A student is asked to prepare a buffer solution made with equimolar amounts of CH3_33​NH2_22​(aqaqaq) and CH3_33​NH3_33​Cl(sss). The student uses 25.00 mL of 0.100 M CH3_33​NH2_22​(aqaqaq), which contains 0.00250 mol of CH3_33​NH2_22​, to make the buffer.

4.a) Calculate the mass of CH3_33​NH3_33​Cl(sss) that contains 0.00250 mol of CH3_33​NH3_33​Cl.

1 mark

4.b) The following table contains a partial procedure for making the buffer solution. Fill in steps 1 and 4 to complete the procedure using only materials and equipment selected from the choices given. (Not all materials listed will be used. Assume that all appropriate safety measures are already in place.)

StepProcedure
1
2Place the solid in the 50 mL beaker.
3Clean the buret and rinse with distilled water.
4
5Use the buret to add 25.00 mL of 0.100 M CH3_33​NH2_22​(aqaqaq) to the beaker.
6Mix well.
7Check the pH with the pH meter.
2 marks

4.c) The student prepares a second buffer solution. The student uses 25.00 mL of 0.050 M CH3_33​NH2_22​(aqaqaq) instead of 25.00 mL of 0.100 M CH3_33​NH2_22​(aqaqaq), and half the mass of CH3_33​NH3_33​Cl(sss) that was used in the first buffer. Is the pH of the second buffer greater than, less than, or equal to the pH of the first buffer? Justify your answer.

1 mark
Question 4
2018ChemistryAPConcept Practice
4 marks

The ionization of HF(aq)HF(aq)HF(aq) in water is represented by the equation above.

HF(aq)+H2O(l)⇌F−(aq)+H3O+(aq)HF(aq) + H_2O(l) \rightleftharpoons F^-(aq) + H_3O^+(aq)HF(aq)+H2​O(l)⇌F−(aq)+H3​O+(aq)

In a 0.0350 M HF(aq)HF(aq)HF(aq) solution, the percent ionization of HF is 13.0 percent.

5.a. Two particulate representations of the ionization of HF molecules in the 0.0350 M HF(aq)HF(aq)HF(aq) solution are shown below in Figure 1 and Figure 2. Water molecules are not shown. Explain why the representation of the ionization of HF molecules in water in Figure 1 is more accurate than the representation in Figure 2. (The key below identifies the particles in the representations.)

markdown-image

2 marks

5.b. Use the percent ionization data above to calculate the value of KaK_aKa​ for HF.

1 mark

5.c. If 50.0 mL of distilled water is added to 50.0 mL of 0.035 M HF(aq)HF(aq)HF(aq), will the percent ionization of HF(aq)HF(aq)HF(aq) in the solution increase, decrease, or remain the same? Justify your answer with an explanation or calculation.

1 mark
Feedback stars icon

How are we doing?

Give us your feedback and let us know how we can improve