zuai-logo

Differentiation of Composite & Inverse Functions

Emily Davis

Emily Davis

6 min read

Listen to this study note

Study Guide Overview

This study guide covers the chain rule for differentiating composite functions. It explains the rule, provides worked examples with increasing complexity (including combining with the product rule), and offers practice questions. Key concepts include identifying inner functions, extending the chain rule to longer chains, and applying it in conjunction with other differentiation rules. A glossary and exam tips are also included.

Derivatives of Composite Functions

Table of Contents

  1. Understanding Composite Functions
  2. Using the Chain Rule
  3. Worked Examples
  4. Advanced Applications of the Chain Rule
  5. Practice Questions
  6. Glossary
  7. Summary and Key Takeaways

Understanding Composite Functions

When differentiating composite functions, we use the chain rule. Composite functions are of the form f(g(x))f(g(x)).

The Chain Rule

If y=f(u)y = f(u) and u=g(x)u = g(x), then: dydx=dydu×dudx\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}

In function notation, if h(x)=f(g(x))h(x) = f(g(x)), then: h(x)=f(g(x))g(x)h'(x) = f'(g(x)) \cdot g'(x)

The chain rule can be extended to longer chains of functions: dydx=dydu×dudt×dtdr×drdx\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dt} \times \frac{dt}{dr} \times \frac{dr}{dx}

The terms are derivatives, not fractions, but they can be treated similarly in this context to simplify the process.

Using the Chain Rule

Example: Differentiating y=(2x3+4x)6y = (2x^3 + 4x)^6

  1. Identify the inside function: u=2x3+4xu = 2x^3 + 4x
  2. Rewrite the original function: y=u6y = u^6
  3. Differentiate the inside function with respect to xx: dudx=6x2+4\frac{du}{dx} = 6x^2 + 4
  4. **Differentiate yy wi...

Question 1 of 11

In the composite function y=(2x+1)3y = (2x+1)^3, what is the inner function?

y=u3y=u^3

u=2x+1u = 2x+1

y=x3y = x^3

3u^2