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Differentiation of Composite & Inverse Functions

Emily Davis

Emily Davis

5 min read

Next Topic - Derivatives of Inverse Trigonometric Functions

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Study Guide Overview

This study guide covers the reciprocal of a derivative and derivatives of inverse functions. It explains the relationship between f'(x) and (f⁻¹)'(x), including the derivation and application of the Inverse Function Theorem. The guide provides worked examples, practice questions, and a glossary of key terms like derivative, inverse function, and chain rule. Key concepts include finding the derivative of an inverse function and relating rates of change.

#Study Notes: The Reciprocal of a Derivative and Derivatives of Inverse Functions

#Table of Contents

  1. The Reciprocal of a Derivative
    • Concept Overview
    • Useful Applications
  2. Derivatives of Inverse Functions
    • Relationship between Function and Inverse Derivatives
    • Deriving the Inverse Function Theorem
  3. Worked Examples
  4. Practice Questions
  5. Glossary
  6. Summary and Key Takeaways

#The Reciprocal of a Derivative

#Concept Overview

Derivatives are not fractions, but they behave similarly when finding reciprocals. The reciprocal of a derivative is crucial in various calculations, especially involving inverse functions.

1(dydx)=dxdy\frac{1}{\left( \frac{dy}{dx} \right)} = \frac{dx}{dy}(dxdy​)1​=dydx​

This holds true as long as dydx≠0\frac{dy}{dx} \neq 0dxdy​=0.

Likewise, the reciprocal of dxdy\frac{dx}{dy}dydx​ is:

1(dxdy)=dydx\frac{1}{\left( \frac{dx}{dy} \right)} = \frac{dy}{dx}(dydx​)1​=dxdy​

This is valid if dxdy≠0\frac{dx}{dy} \neq 0dydx​=0.

#Useful Applications

Key Concept
  • **Finding the derivative of the inverse of ...
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Previous Topic - The Chain RuleNext Topic - Derivatives of Inverse Trigonometric Functions

Question 1 of 10

Let's warm up! 🚀 If dydx=5\frac{dy}{dx} = 5dxdy​=5 at a certain point, what is the value of dxdy\frac{dx}{dy}dydx​ at that same point?

5

-5

15\frac{1}{5}51​

0