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Differentiation of Composite & Inverse Functions

Emily Davis

Emily Davis

5 min read

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Study Guide Overview

This study guide covers the reciprocal of a derivative and derivatives of inverse functions. It explains the relationship between f'(x) and (f⁻¹)'(x), including the derivation and application of the Inverse Function Theorem. The guide provides worked examples, practice questions, and a glossary of key terms like derivative, inverse function, and chain rule. Key concepts include finding the derivative of an inverse function and relating rates of change.

Study Notes: The Reciprocal of a Derivative and Derivatives of Inverse Functions

Table of Contents

  1. The Reciprocal of a Derivative
  2. Derivatives of Inverse Functions
  3. Worked Examples
  4. Practice Questions
  5. Glossary
  6. Summary and Key Takeaways

The Reciprocal of a Derivative

Concept Overview

Derivatives are not fractions, but they behave similarly when finding reciprocals. The reciprocal of a derivative is crucial in various calculations, especially involving inverse functions.

1(dydx)=dxdy\frac{1}{\left( \frac{dy}{dx} \right)} = \frac{dx}{dy}

This holds true as long as dydx0\frac{dy}{dx} \neq 0.

Likewise, the reciprocal of dxdy\frac{dx}{dy} is:

1(dxdy)=dydx\frac{1}{\left( \frac{dx}{dy} \right)} = \frac{dy}{dx}

This is valid if dxdy0\frac{dx}{dy} \neq 0.

Useful Applications

Key Concept
  • Finding the derivative of the inverse of a function
  • Relating rates of change using the chain rule

Derivatives of Inverse Functions

Relationship between Function and Inverse Derivatives

For a function ff that is differentiable and has an inverse f1f^{-1}, the derivative of the inverse at a point aa is given by:

(f1)(a)=1f(f1(a))\left( f^{-1} \right)'(a) = \frac{1}{f'\left( f^{-1}(a) \right)}

This is valid if f(f1(a))0f'\left( f^{-1}(a) \right) \neq 0.

You may also see this written as:

g(a)=1f(g(a))g'(a) = \frac{1}{f'\left( g(a) \right)}

Where g(a)=f1(a)g(a) = f^{-1}(a).

This property is known as the Inverse Function Theorem.

Deriving the Inverse Function Theorem

To derive the Inverse Function Theorem, we use the definition of an inverse and the chain rule:

  1. Let g(x)=f1(x)g(x) = f^{-1}(x).
  2. Since ff and gg are inverses, we have f(g(x))=xf(g(x)) = x.
  3. Differentiate both sides with respect to xx:

ddx(f(g(x)))=ddx(x)\frac{d}{dx} \left( f(g(x)) \right) = \frac{d}{dx} (x)

  1. Apply the chain rule to the left-hand side:

f(g(x))g(x)=1f'\left( g(x) \right) \cdot g'(x) = 1

  1. Rearrange to solve for g(x)g'(x):

g(x)=1f(g(x))g'(x) = \frac{1}{f'\left( g(x) \right)}

  1. Recall that g(x)=f1(x)g(x) = f^{-1}(x):

(f1)(x)=1f(f1(x))\left( f^{-1} \right)'(x) = \frac{1}{f'\left( f^{-1}(x) \right)}


Worked Examples

Example 1

Given that f(0)=256f(0) = 256, find the value of g(256)g'(256).

Write the inverse function theorem using f(x)f(x) and f1(x)=g(x)f^{-1}(x) = g(x):

g(256)=1f(g(256))g'(256) = \frac{1}{f'\left( g(256) \right)}

Since f(0)=256f(0) = 256, then g(256)=0g(256) = 0. Now find f(0)f'(0):

f(x)=12(3x+4)3f'(x) = 12(3x + 4)^3

Evaluate at x=0x = 0:

f(0)=12(3(0)+4)3=12(4)3=768f'(0) = 12(3(0) + 4)^3 = 12(4)^3 = 768

So,

g(256)=1768g'(256) = \frac{1}{768}

Example 2

Show that the inverse of f(x)=x3+2x10f(x) = x^3 + 2x - 10 exists and find the derivative of the inverse at x=125x = 125.

First, check if the inverse exists:

f(x)=3x2+2f'(x) = 3x^2 + 2

Since f(x)f'(x) is always positive, f(x)f(x) is one-to-one and thus f1(x)f^{-1}(x) exists.

Use the inverse function theorem:

(f1)(125)=1f(f1(125))\left( f^{-1} \right)'(125) = \frac{1}{f'\left( f^{-1}(125) \right)}

Find f1(125)f^{-1}(125). Solve:

125=y3+2y10125 = y^3 + 2y - 10

By solving, y=5y = 5:

f1(125)=5f^{-1}(125) = 5

Thus,

(f1)(125)=1f(5)\left( f^{-1} \right)'(125) = \frac{1}{f'(5)}

Evaluate f(5)f'(5):

f(5)=3(5)2+2=77f'(5) = 3(5)^2 + 2 = 77

So,

(f1)(125)=177\left( f^{-1} \right)'(125) = \frac{1}{77}


Practice Questions

Practice Question
  1. Given f(x)=x2+1f(x) = x^2 + 1, find (f1)(2)\left( f^{-1} \right)'(2).
Practice Question
  1. If h(x)=ln(x)h(x) = \ln(x), find (h1)(e)\left( h^{-1} \right)'(e).
Practice Question
  1. Show that the inverse of f(x)=ex+xf(x) = e^x + x exists and find (f1)(2)\left( f^{-1} \right)'(2).

Glossary

  • Derivative: A measure of how a function changes as its input changes.
  • Inverse Function: A function that "reverses" another function.
  • Chain Rule: A formula for computing the derivative of the composition of two or more functions.
  • Inverse Function Theorem: A theorem that provides a formula for the derivative of the inverse of a function.

Summary and Key Takeaways

Summary

  • The reciprocal of a derivative dydx\frac{dy}{dx} is dxdy\frac{dx}{dy}.
  • The Inverse Function Theorem provides a method to find the derivative of the inverse function.
  • The theorem is derived using the chain rule and the definition of an inverse function.

Key Takeaways

  • Understand the reciprocal relationship between dydx\frac{dy}{dx} and dxdy\frac{dx}{dy}.
  • Apply the Inverse Function Theorem to find the derivative of inverse functions.
  • Use the chain rule effectively in derivations and calculations.
Exam Tip

Remember, always verify if the function is one-to-one before applying the Inverse Function Theorem.

Common Mistake

A common mistake is to forget that the reciprocal relationship only holds when the derivative is non-zero.