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Riemann Sums & Definite Integrals

David Brown

David Brown

7 min read

Next Topic - Evaluating Definite Integrals

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Study Guide Overview

This study guide covers the concept of definite integrals, including their definition as the limit of Riemann sums and their interpretation as the area under a curve. It explores key properties such as manipulating constant multipliers, integrating sums/differences of functions, and changing the limits of integration. The guide also includes practice questions and a glossary of terms.

#Definite Integrals Study Guide

#Table of Contents

  1. Introduction to Definite Integrals
  2. Definite Integral as a Limit of Riemann Sums
  3. Properties of Definite Integrals
  4. Practice Questions
  5. Glossary
  6. Summary and Key Takeaways

#Introduction to Definite Integrals

#What is a Definite Integral?

A definite integral is written as:

∫abf(x),dx\int_{a}^{b} f(x) , dx∫ab​f(x),dx

  • Integrand (f(x)f(x)f(x)): The function being integrated.
  • Integration Variable (dxdxdx): Indicates the variable of integration.
  • Limits of Integration (aaa and bbb): The bounds between which the function is integrated.
    • The function is integrated 'from aaa to bbb'.
    • Typically, a≤ba \leq ba≤b, but a>ba > ba>b is also valid.
Key Concept

Key Concept: A definite integral represents the area under the curve of a function f(x)f(x)f(x) from x=ax = ax=a to x=bx = bx=b.

**Example**: If f(x)≥0f(x) \geq 0f(x)≥0 on the interval [a,b][a, b][a,b], the definite integral ∫_abf(x) dx\int\_{a}^{b} f(x) \, dx∫_abf(x)dx gives the area between the function f(x)f(x)f(x) and the xxx-axis, from x=ax = ax=a to x=bx = bx=b.

#Interpreting Definite Integrals

  • A definite integral outputs a number based on f(x)f(x)f(x) and the values of aaa and bbb.
  • If f(x)f(x)f(x) is a rate of change function, the definite integral represents the accumulation of change from x=ax = ax=a to x=bx = bx=b.
**Note**: The definite integral can also be interpreted as the signed area under the curve, where areas above the xxx-axis are positive and those below are negative.

#Definite Integral as a Limit of Riemann Sums

#Definition

The value of a definite integral can be defined as a limit of Riemann sums:

∫abf(x),dx=lim⁡Δxi→0∑i=1nf(xi∗)Δxi\int_{a}^{b} f(x) , dx = \lim_{{\Delta x_i \to 0}} \sum_{i=1}^{n} f(x_i^*) \Delta x_i∫ab​f(x),dx=Δxi​→0lim​i=1∑n​f(xi∗​)Δxi​

  • nnn: The number of subintervals.
  • xi∗x_i^*xi∗​: Any value within the iii-th subinterval.
  • Δxi\Delta x_iΔxi​: The width of the iii-th subinterval.
  • lim⁡Δxi→0\lim_{{\Delta x_i \to 0}}limΔxi​→0​: The limit as the width of the largest subinterval approaches zero.
**Example**: As the subintervals get narrower, the area of the approximating rectangles gets closer to the exact area under the curve.
Exam Tip

IB Objective: Understand the connection between Riemann sums and definite integrals.

#Alternate Form

The Riemann sum limit for a definite integral can also be written as:

∫abf(x),dx=lim⁡n→∞∑i=1nf(xi∗)Δxi\int_{a}^{b} f(x) , dx = \lim_{{n \to \infty}} \sum_{i=1}^{n} f(x_i^*) \Delta x_i∫ab​f(x),dx=n→∞lim​i=1∑n​f(xi∗​)Δxi​

If the subintervals are of equal width:

Δx=b−an\Delta x = \frac{b - a}{n}Δx=nb−a​

Exam Tip

Exam Tip: You are not expected to calculate definite integrals using Riemann sums in exams. Instead, use standard integration techniques.

#Worked Example

Evaluate the following limit:

lim⁡n→∞∑i=1n(−3+5ni)2+1⋅(5n)\lim_{{n \to \infty}} \sum_{i=1}^{n} \left(-3 + \frac{5}{n}i\right)^2 + 1 \cdot \left(\frac{5}{n}\right)n→∞lim​i=1∑n​(−3+n5​i)2+1⋅(n5​)

Solution:

Recognize this as a limit of Riemann sums. The key term is 5n\frac{5}{n}n5​, indicating the width of subintervals. The interval is [−3,2][-3, 2][−3,2].

∫−32(x2+1),dx\int_{-3}^{2} (x^2 + 1) , dx∫−32​(x2+1),dx

Evaluate the integral:

∫−32(x2+1),dx=[x33+x]−32=143−(−12)=503\int_{-3}^{2} (x^2 + 1) , dx = \left[ \frac{x^3}{3} + x \right]_{-3}^{2} = \frac{14}{3} - (-12) = \frac{50}{3}∫−32​(x2+1),dx=[3x3​+x]−32​=314​−(−12)=350​

Thus,

lim⁡n→∞∑i=1n(−3+5ni)2+1⋅(5n)=503\lim_{{n \to \infty}} \sum_{i=1}^{n} \left(-3 + \frac{5}{n}i\right)^2 + 1 \cdot \left(\frac{5}{n}\right) = \frac{50}{3}n→∞lim​i=1∑n​(−3+n5​i)2+1⋅(n5​)=350​

#Properties of Definite Integrals

#Definite Integral of a Constant Times a Function

If kkk is a constant:

∫abkf(x),dx=k∫abf(x),dx\int_{a}^{b} k f(x) , dx = k \int_{a}^{b} f(x) , dx∫ab​kf(x),dx=k∫ab​f(x),dx

Key Concept

Key Concept: Constants can be factored out of the integral.

#Definite Integral of a Sum or Difference of Functions

If fff and ggg are two functions:

∫ab(f(x)±g(x)),dx=∫abf(x),dx±∫abg(x),dx\int_{a}^{b} (f(x) \pm g(x)) , dx = \int_{a}^{b} f(x) , dx \pm \int_{a}^{b} g(x) , dx∫ab​(f(x)±g(x)),dx=∫ab​f(x),dx±∫ab​g(x),dx

**Example**: ∫_02(3x+4) dx=∫_023x dx+∫_024 dx\int\_{0}^{2} (3x + 4) \, dx = \int\_{0}^{2} 3x \, dx + \int\_{0}^{2} 4 \, dx∫_02(3x+4)dx=∫_023xdx+∫_024dx

#Changing Limits of Integration

#Zero-Length Interval

For any function fff:

∫aaf(x),dx=0\int_{a}^{a} f(x) , dx = 0∫aa​f(x),dx=0

#Reversing the Limits

For a function fff:

∫baf(x),dx=−∫abf(x),dx\int_{b}^{a} f(x) , dx = -\int_{a}^{b} f(x) , dx∫ba​f(x),dx=−∫ab​f(x),dx

#Adjacent Intervals

For a function fff, and ccc such that a≤c≤ba \leq c \leq ba≤c≤b:

∫abf(x),dx=∫acf(x),dx+∫cbf(x),dx\int_{a}^{b} f(x) , dx = \int_{a}^{c} f(x) , dx + \int_{c}^{b} f(x) , dx∫ab​f(x),dx=∫ac​f(x),dx+∫cb​f(x),dx

**Example**: If ∫_25f(x) dx=−3\int\_{2}^{5} f(x) \, dx = -3∫_25f(x)dx=−3 and ∫_27f(x) dx=12\int\_{2}^{7} f(x) \, dx = 12∫_27f(x)dx=12, find ∫_57f(x) dx\int\_{5}^{7} f(x) \, dx∫_57f(x)dx.

∫27f(x),dx=∫25f(x),dx+∫57f(x),dx\int_{2}^{7} f(x) , dx = \int_{2}^{5} f(x) , dx + \int_{5}^{7} f(x) , dx∫27​f(x),dx=∫25​f(x),dx+∫57​f(x),dx

12=−3+∫57f(x),dx12 = -3 + \int_{5}^{7} f(x) , dx12=−3+∫57​f(x),dx

∫57f(x),dx=15\int_{5}^{7} f(x) , dx = 15∫57​f(x),dx=15

#Practice Questions

Practice Question

Question 1: Evaluate ∫03(2x2+3x),dx\int_{0}^{3} (2x^2 + 3x) , dx∫03​(2x2+3x),dx.

Answer: ∫03(2x2+3x),dx=[2x33+3x22]03=(18+13.5)−0=31.5\int_{0}^{3} (2x^2 + 3x) , dx = \left[ \frac{2x^3}{3} + \frac{3x^2}{2} \right]_{0}^{3} = \left(18 + 13.5\right) - 0 = 31.5∫03​(2x2+3x),dx=[32x3​+23x2​]03​=(18+13.5)−0=31.5

Practice Question

Question 2: If ∫14f(x),dx=7\int_{1}^{4} f(x) , dx = 7∫14​f(x),dx=7 and ∫46f(x),dx=−2\int_{4}^{6} f(x) , dx = -2∫46​f(x),dx=−2, find ∫16f(x),dx\int_{1}^{6} f(x) , dx∫16​f(x),dx.

Answer: ∫16f(x),dx=∫14f(x),dx+∫46f(x),dx=7+(−2)=5\int_{1}^{6} f(x) , dx = \int_{1}^{4} f(x) , dx + \int_{4}^{6} f(x) , dx = 7 + (-2) = 5∫16​f(x),dx=∫14​f(x),dx+∫46​f(x),dx=7+(−2)=5

Practice Question

Question 3: Use the property of reversing limits to evaluate ∫315x,dx\int_{3}^{1} 5x , dx∫31​5x,dx.

Answer: ∫315x,dx=−∫135x,dx=−[5x22]13=−(452−52)=−20\int_{3}^{1} 5x , dx = -\int_{1}^{3} 5x , dx = -\left[ \frac{5x^2}{2} \right]_{1}^{3} = -\left( \frac{45}{2} - \frac{5}{2} \right) = -20∫31​5x,dx=−∫13​5x,dx=−[25x2​]13​=−(245​−25​)=−20

#Glossary

  • Definite Integral: The integral of a function over a specific interval, resulting in a number.
  • Integrand: The function being integrated.
  • Limits of Integration: The bounds aaa and bbb in the integral ∫abf(x),dx\int_{a}^{b} f(x) , dx∫ab​f(x),dx.
  • Riemann Sum: A method for approximating the definite integral of a function.
  • Subinterval: A division of the interval [a,b][a, b][a,b] used in Riemann sums.

#Summary and Key Takeaways

#Summary

  • Definite integrals are used to calculate the total accumulation of a function over an interval.
  • They can be interpreted as the area under the curve of the function.
  • Definite integrals can be defined using Riemann sums.
  • There are several properties of definite integrals, such as dealing with constants, sums, and differences.

#Key Takeaways

  • Understand the notation and basic interpretation of definite integrals.
  • Recognize that definite integrals can be evaluated using standard integration techniques, not Riemann sums.
  • Be familiar with properties such as changing limits, reversing limits, and dealing with sums/differences of functions.
Exam Tip

Exam Tip: Practice evaluating definite integrals and understanding their geometric and physical interpretations.

Exam Tip

IB Objective: Ensure you can link definite integrals to real-world applications and problems, as well as solve them efficiently.

**Note**: Always double-check your integration limits and the function you are integrating to avoid common mistakes.

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Question 1 of 10

In the definite integral ∫25(x3+2),dx\int_{2}^{5} (x^3 + 2) , dx∫25​(x3+2),dx, what is the integrand?

x3x^3x3

2

x3+2x^3 + 2x3+2

dxdxdx