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What is the effect of increasing the force applied to an object, assuming constant velocity?

Increased instantaneous power.

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What is the effect of increasing the force applied to an object, assuming constant velocity?

Increased instantaneous power.

What happens if the angle between force and velocity is 90 degrees?

Instantaneous power is zero because $cos(90^\circ) = 0$ .

What is the effect of increasing the time interval over which work is done, assuming constant work?

Decreased average power.

What happens when energy is transferred more quickly?

The power increases.

What happens when work is done in a shorter amount of time?

The power increases.

How do you calculate Average Power using energy?

Determine the change in energy ( $\Delta E$ ). 2. Determine the change in time ( $\Delta t$ ). 3. Divide the change in energy by the change in time: $P_{avg} = \frac{\Delta E}{\Delta t}$ .

How do you calculate Average Power using work?

Determine the work done (W). 2. Determine the change in time ( $\Delta t$ ). 3. Divide the work done by the change in time: $P_{avg} = \frac{W}{\Delta t}$ .

How do you calculate Instantaneous Power?

Determine the force (F) acting on the object. 2. Determine the velocity (v) of the object at that instant. 3. Determine the angle ( $\theta$ ) between the force and velocity vectors. 4. Calculate: $P_{inst} = Fv \cos \theta$ .

What are the differences between Average Power and Instantaneous Power?

Average Power: Rate of energy transfer over a time interval. | Instantaneous Power: Rate of energy transfer at a specific moment.

Compare calculating power using energy vs. work.

Energy: $P = \frac{\Delta E}{\Delta t}$ , focuses on the change in energy. | Work: $P = \frac{W}{\Delta t}$ , focuses on the work done during energy transfer.