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  1. AP Physics 2 Revised
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Electric Circuits

Question 1
Physics 2 (2025)APExam Style
1 mark

How should an ammeter be connected to measure the current flowing through a resistor in a circuit?

Question 2
Physics 2 (2025)APExam Style
1 mark

Two resistors, R1=5ΩR_1 = 5 \OmegaR1​=5Ω and R2=15ΩR_2 = 15 \OmegaR2​=15Ω, are connected in series. What is the equivalent resistance of this combination?

Question 3
Physics 2 (2025)APExam Style
1 mark

Consider a circuit with three resistors: R1=2ΩR_1 = 2 \OmegaR1​=2Ω, R2=4ΩR_2 = 4 \OmegaR2​=4Ω, and R3=6ΩR_3 = 6 \OmegaR3​=6Ω. R1R_1R1​ and R2R_2R2​ are in parallel, and this combination is in series with R3R_3R3​. What is the total equivalent resistance of the circuit?

Question 4
Physics 2 (2025)APExam Style
1 mark

A battery with an internal resistance is connected to two external resistors in series. If the internal resistance of the battery is 1 \Omega, and the external resistors are R1=4ΩR_1 = 4 \OmegaR1​=4Ω and R2=5ΩR_2 = 5 \OmegaR2​=5Ω, what is the current in the circuit if the battery's emf is 20V?

Question 5
Physics 2 (2025)APExam Style
1 mark

A voltmeter with a finite internal resistance is connected in parallel with a resistor in a circuit. How does this voltmeter affect the voltage reading across the resistor?

Question 6
Physics 2 (2025)APExam Style
1 mark

A 4 \Omega and an 8 \Omega resistor are connected in parallel. What is their equivalent resistance?

Question 7
Physics 2 (2025)APExam Style
1 mark

A battery has an emf of 10 V and an internal resistance of 0.5 Ω\OmegaΩ. If the current flowing through the battery is 2 A, what is the terminal voltage of the battery?

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Question 8
Physics 2 (2025)APExam Style
1 mark

A non-ideal battery with an emf E\mathcal{E}E and internal resistance rrr is connected to an external resistor RRR. Which expression correctly describes the power dissipated by the internal resistance?

Question 9
Physics 2 (2025)APExam Style
1 mark

A student connects an ammeter in series with a resistor in a simple circuit. If the ammeter has a non-negligible internal resistance, how will the measured current compare to the actual current without the ammeter?