Electrostatics
What describes best how Gauss's Law applies to a charged spherical conducting shell?
Incorrect Answer Choice
Incorrect Answer Choice
Incorrect Answer Choice
The electric field is zero anywhere inside the shell space but non-zero outside based on total enclosed charge.
A non-conducting sphere of radius R has a volume charge density that varies with distance r from the center as , where k is a constant; what is the electric field at a point P located at a distance 2R from the center of the sphere?
E = zero
E = \frac{k}{8 \pi \epsilon_0 R^2}
E = \frac{3k}{8 \pi \epsilon_0 R^2}
E = \frac{k}{4 \pi \epsilon_0 R^2}
How would you describe the magnitude of the field within a hollow conducting sphere carrying net charge ?
due to Gauss's Law.
Nonzero outward from the surface proportional to the charge magnitude and inversely with the square of the distance from the surface.
as if it is a point charge at the center.
Zero everywhere inside the shell due to the nature of conductors' equilibrium conditions.
If you double the amount of enclosed charge in a Gaussian surface without changing its size or shape, what happens to the electric flux through that surface?
It halves.
It remains constant.
It doubles as well.
It quadruples.
If a parallel plate capacitor with area A and separation d is immersed in a dielectric medium with constant k, what electric field intensity inside results when an external electric field is applied perpendicular to the plates?
The electric field intensity increases to .
The electric field intensity is reduced to .
The electric field intensity becomes zero if .
The electric field intensity inside remains at .
What does Gauss's Law relate to in the context of an electric field?
The potential difference across two points in an electric field.
The magnetic field around a current-carrying wire.
The net electric flux through a closed surface.
The resistance encountered within a closed loop circuit.
Which quantity must be zero when applying Gauss's Law to a closed surface with no charge inside it?
Electric potential
Electric flux
Current
Electric field strength

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What would be the electric flux through a closed cylindrical surface in vacuum when oriented perpendicular to a uniform electric field ?
times the area of one circular base
times twice the height times times diameter
Zero
times twice the area of one circular base
For an infinitely long cylinder carrying uniform surface charge density , if one chooses a Gaussian surface as coaxial cylinder with length and radius greater than that of charged cylinder, how does its electric field vary outside?
It decreases exponentially with radial distance.
It increases linearly with radial distance.
It varies inversely with radial distance from axis.
It remains constant regardless of radial distance.
A charge is placed at the center of a hollow conductive spherical shell; how would changing the radius of this shell affect the electric flux passing through it?
It does not change because all charge-induced fields emanate from or terminate on charges inside.
It increases as radius increases since there’s more space for lines to spread out.
It fluctuates depending on whether radius expands or contracts.
It decreases as radius increases due to dilution of field lines over a larger surface area.